Python生成符合规则的身份证号码。

注：本文内容为本人做记录用，如有雷同纯属巧合。

话不多说直接贴码：

# encoding:utf-8
import time
import random
from datetime import date, timedelta


class CreateIDCard:

    @staticmethod
    def CreateIDCard():
        """
        随机生成符合规则的身份证号码
        """
        # 随机身份证前六位 townNum
        ProvinceID = ['110000', '120100', '120102', '120103']
        townNum = random.choice(ProvinceID)
        # 随机身份证年份,大于18岁  yearNum
        timeDate = time.time()
        yearDate = time.strftime("%Y", time.localtime(timeDate))
        yearNum = random.randint(1980, int(yearDate)-18)
        # 随机身份证月 日 dateNum
        someDate = date.today() + timedelta(days=random.randint(1, 366))
        dateNum = someDate.strftime("%m%d")
        # 随机身份证后四位的前三位 lastThree
        lastThree = random.randint(100, 999)
        # 随机身份证的前17位 id17(注：都加str仅仅是为了排版。)
        id17 = str(townNum) + str(yearNum) + str(dateNum) + str(lastThree)

        count = 0
        # 权重项
        weight = [7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2]
        # 校验项
        CheckCode = ["1", "0", "X", "9", "8", "7", "6", "5", "4", "3", "2"]

        for i in range(0, len(id17)):
            count = count + weight[i]*int(id17[i])
        # 获取校验码
        CheckNum = count % 11
        # 得到符合规则的身份证号码
        IDCard = id17 + CheckCode[CheckNum]
        return IDCard


if __name__ == '__main__':
    print("生成随机身份证号码：", CreateIDCard.CreateIDCard())

来源：https://blog.csdn.net/l505703438/article/details/102753773