Java convert double to date format

强颜欢笑 提交于 2019-12-02 08:28:25

Since your double represents the number of seconds of you date from now, and the Date constructor in Java is expecting a number of milliseconds since 01-01-1970, you have to multiply your number to get a number of milliseconds (* 1000) and substract that from the current number of milliseconds since 01-01-1970 (System.currentTimeMillis()):

double myDouble = -242528463.775282;
long myLong = System.currentTimeMillis() + ((long) (myDouble * 1000));
System.out.println(myLong);

Date itemDate = new Date(myLong);
String myDateStr = new SimpleDateFormat("dd-MM-yyyy").format(itemDate);
System.out.println(myDateStr);

But, the problem with the way you store your dates is that if you are calling this code today and tomorrow it will not return the same date, as the current time is changing. You should use timeIntervalSince1970 instead of timeIntervalSinceNow.

Alan

Have a play around with statements below. In particular; long myLong = todate.getTime();
and store this to interpret later perhaps?

import java.text.SimpleDateFormat;
import java.util.Date;

public class dateConvertDouble {

    public static void main(String[] args) {
        Date todate = new Date();
        System.out.println(todate);

        long myLong = todate.getTime();
        System.out.println(myLong);

        double myDouble = (double)myLong;
        System.out.println(myDouble);

        String myDateStr = new SimpleDateFormat("dd-MM-yyyy").format(myLong);             
        System.out.println(myDateStr);

    }
}
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