Java - execute a program with options, like ls -l

问题

In Java, how do I execute a linux program with options, like this:

ls -a (the option is -a),

and another: ./myscript name=john age=24

I know how to execute a command, but cannot do the option.

回答1:

You need to execute an external process, take a look at ProcessBuilder and just because it almost answers your question, Using ProcessBuilder to Make System Calls

UPDATED with Example

I ripped this straight from the list example and modified it so I could test on my PC and it runs fine

private static void copy(InputStream in, OutputStream out) throws IOException {
    while (true) {
        int c = in.read();
        if (c == -1) {
            break;
        }
        out.write((char) c);
    }
}

public static void main(String[] args) throws IOException, InterruptedException {

//        if (args.length == 0) {
//            System.out.println("You must supply at least one argument.");
//            return;
//        }

    args = new String[] {"cmd", "/c", "dir", "C:\\"};

    ProcessBuilder processBuilder = new ProcessBuilder(args);
    processBuilder.redirectErrorStream(true);

    Process process = processBuilder.start();
    copy(process.getInputStream(), System.out);
    process.waitFor();
    System.out.println("Exit Status : " + process.exitValue());
}

回答2:

Apache Commons has a library built to handle this type of thing. I wish I knew about it before I coded something like this by hand. I found it later on. It takes options in various formats for a command line program.

Apache Commons CLI

来源：https://stackoverflow.com/questions/11893469/java-execute-a-program-with-options-like-ls-l

标签

java

terminal

command