zsh

I've a question on how to tell which shell the user is using. Suppose a script that if the user is using zsh, then put PATH to his .zshrc and if using bash should put in .bashrc. And set rvmrc accordingly. #!/usr/bin/env bash export PATH='/usr/local/bin:$PATH'" >> ~/.zshrc source ~/.zshrc I've tried the following but it does not work : ( if [[ $0 == "bash ]]; then export PATH='/usr/local/bin:$PATH'" >> ~/.bashrc elif [[ $0 == "zsh" ]]; then export PATH='/usr/local/bin:$PATH'" >> ~/.zshrc fi # ... more commands ... if [[ $0 == "bash ]]; then [[ -s '/Users/`whoami`/.rvm/scripts/rvm' ]] && source

I am trying to set up a .vimrc file in my home directory. The only thing it contains is the following. " Enable syntax highlighting syntax on Whenever I want to source the file running . ~/.vimrc this message is returned. /Users/username/.vimrc:3: unmatched " My working environment is the following. MacOS Lion 10.7.2 zsh 4.3.12 (i386-apple-darwin11.2.0) oh_my_zsh Terminal 2.2.1 VIM 7.3 How can I get rid of this warning/error message. What does it mean?! EDIT When I try the same from bash it does not work either. bash-3.2$ . ~/.vimrc bash: /Users/username/.vimrc: line 1: unexpected EOF while

The title should say it all. I'm looking for an equivalent to ${BASH_SOURCE[0]} in zsh. Note: I keep finding " $0 is equivalent to ${BASH_SOURCE[0]} " around the Internet, but this seems to be false: $0 seems to be the name of the executing command. (It's argv[0] , which makes sense.) Echoing $0 in my script ( .zshrc ) gives zsh for $0 , which isn't the same as what ${BASH_SOURCE[0]} is. In fact, ${BASH_SOURCE[0]} seems to work in zsh , except for inside .zshrc files. What I'm really doing in my .zshrc (that isn't working): echo ${BASH_SOURCE[0]} source `dirname $0`/common-shell-rc.sh The

Bash allows me to write the statement, $ for i in {h..k} ; do echo $i ; done but zsh only allows number list expansion such as {8..13} . What's the best workaround? Something like seq for characters... As this is still a top google result, an updated answer: The current release supports bash style {c1..c2} where c1 and c2 are characters: An expression of the form ‘ {c1..c2} ’, where c1 and c2 are single characters (which may be multibyte characters), is expanded to every character in the range from c1 to c2 in whatever character sequence is used internally. For characters with code points

There are lots of SO questions on running shell programs from vim. What I'm wondering is if it is possible to do the reverse - i.e. $ vim :BundleInstall for example, to allow me to run BundleInstall as part of a script, rather than having to open Vim and run it manually on first running? Is this possible? jvc26 Note, now the syntax has changed, and the line should read (As per @sheharyar ): vim +PluginInstall +qall For posterity, previously, the correct line was: vim +BundleInstall +qall Should anyone other than me be looking! Note: this is in the Github README for vundle. I think that this is

I run the following codes separately as my prompt unsuccessfully in .zshrc. This suggests me that apparently I do not have a program called __git_ps1. It is not in MacPorts. #1 PROMPT="$(__git_ps1 " \[\033[1;32m\] (%s)\[\033[0m\]")\$"$ #2 PROMPT="$(__git_ps1 " (%s)")\$"$ #3 # Get the name of the branch we are on git_prompt_info() { branch_prompt=$(__git_ps1) if [ -n "$branch_prompt" ]; then status_icon=$(git_status) echo $branch_prompt $status_icon fi } # Show character if changes are pending git_status() { if current_git_status=$(git status | grep 'added to commit' 2> /dev/null); then echo "☠