zillow

How do I iterate a Zillow API call / output parse function in R over a list of addresses and zip codes?

a 夏天 提交于 2020-01-05 05:52:09
问题 I've been working on a project where the goal is to take a two-column CSV of street addresses and zip codes, read it into R, then perform a Zillow query for each one (GetSearchResults, specifically), parse the output, and store the parsed output in a dataframe to be written to a CSV (and placed right next to the existing data). caveat: I can only call one address/zip combo at a time through the zillow API, so anything that violates that is off the table immediately. As of this point, I have

Simple XML reading question (PHP)

℡╲_俬逩灬. 提交于 2019-12-20 03:46:04
问题 I have the following XML file: <?xml version="1.0" encoding="utf-8"?> <SearchResults:searchresults xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.zillow.com/static/xsd/SearchResults.xsd /vstatic/279989c5e93d519f8d8f23d3f6cac661/static/xsd/SearchResults.xsd" xmlns:SearchResults="http://www.zillow.com/static/xsd/SearchResults.xsd"> <request> <address>2114 Bigelow Ave</address> <citystatezip>Seattle, WA</citystatezip> </request> <message> <text>Request

How to send data to an API call and get it back, using zillow.com API

我怕爱的太早我们不能终老 提交于 2019-12-18 03:43:36
问题 I am trying to get the API from a website called zillow working for me, but I am way new to web stuff. They try and explain here how to use it, but it had me lost so I looked in their forums. Someone posted an "example" there, but I can not see where their code even calls the API. Basically I need to take a form field that will be an address and send that info to get data back, here is the source code taken from the guys example, <html xml:lang="en" lang="en"> <head> <title></title> </head>

Getting Zillow API Data

空扰寡人 提交于 2019-12-11 03:37:58
问题 I can't access any zillow information even though I feel that I am using their API correctly. Any help? $zillow_id = '<MY ZPID>'; $search = "2114 Bigelow Ave"; $citystate = "Seattle, WA"; $address = urlencode($search); $citystatezip = urlencode($citystate); $url = "http://www.zillow.com/webservice/GetSearchResults.htm?zws-id=$zillow_id&address=$address&citystatezip=$citystatezip"; $result = file_get_contents($url); //$data = simplexml_load_string($result); print_r($result); Edit 1: Error When

Pulling Zillow Rent Data from Zillow API

核能气质少年 提交于 2019-12-10 18:50:08
问题 I am playing around with the Zillow API, but I am having trouble retrieving the rent data. Currently I am using a Python Zillow wrapper, but I am not sure if it works for pulling the rent data. This is the help page I am using for the Zillow API: https://www.zillow.com/howto/api/GetSearchResults.htm import pyzillow from pyzillow.pyzillow import ZillowWrapper, GetDeepSearchResults import pandas as pd house = pd.read_excel('Housing_Output.xlsx') ### Login to Zillow API address = ['123 Test

Pyzillow, cannot get home attributes

江枫思渺然 提交于 2019-11-28 12:00:56
问题 Following the instructions from here. I noticed that some addresses do not work for example: address = "5621 N Atlantic Ave, Portland, OR" zipcode = "97217" zillow_id = get_zillow_id(key, address, zipcode) zillow_data = ZillowWrapper(key) updated_property_details_response = zillow_data.get_updated_property_details(zillow_id) result = GetUpdatedPropertyDetails(updated_property_details_response) result.rooms # number of rooms of the home Although, I still get the zillow_id returned which means