xstream

spring batch exception Cannot construct java.util.Map$Entry

匿名 (未验证) 提交于 2019-12-03 08:57:35
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: We are facing following exception while executing spring batch job from command line. Spring Batch Version - 3.0.2.RELEASE Spring Version - 4.0.0.RELEASE xStream version - 1.4.7 Data Base - mysql (I am connecting to new DB schema.) While executing a job using following command, I am getting below exception... java %JAVA_OPTS% org.springframework.batch.core.launch.support.CommandLineJobRunner config/spring-config.xml partitionJdbcJob Exception ---------- INFO: Loaded JDBC driver: com.mysql.jdbc.Driver Feb 20, 2015 3:22:28 PM org

Security framework of XStream not initialized, XStream is probably vulnerable

匿名 (未验证) 提交于 2019-12-03 08:36:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Security framework of XStream not initialized, XStream is probably vulnerable I keep getting this console error in red while using XStream (1.4.10) I tried the following: XStream.setupDefaultSecurity(xs); and xs.addPermission(AnyTypePermission.ANY); xs.addPermission(NoTypePermission.NONE); none of which got rid of it. I do not need any fancy security settings, I just want to silence that warning. Maybe also prepare the code for 1.5.x 回答1: When dealing with security issues, I wouldn't take it lightly. Firstly one would understand the severity

Spring REST 3 to Support XML and JSON

纵饮孤独 提交于 2019-12-03 07:56:41
问题 If we develop REST using Spring MVC, it will support XML and JSON data. I have wrote ContentNegotiationViewResorver in my spring config bean app-servlet.xml <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver" p:order="1"> <property name="mediaTypes"> <map> <entry key="xml" value="application/xml" /> <entry key="json" value="application/json" /> </map> </property> <property name="defaultViews"> <list> <bean class="org.springframework.web.servlet.view.xml

XStream and underscores

我是研究僧i 提交于 2019-12-03 07:48:06
问题 It looks like XStream (com.thoughtworks.xstream -> xstream 1.4.2) is handling underscores in element and attribute names in a very strange way. I need to fetch and parse an xml from a customer that are having underscores in their attributes. This is my first try with XStream and I'm a bit disappointed as I was hoping to avoid all the ugly xml parsing. Here I provide a small test sample to hi light the behaviour. The last example shows my problem. public class MyTest { public void testIt() {

How to make XStream skip unmapped tags when parsing XML?

柔情痞子 提交于 2019-12-03 04:56:20
问题 I have a large XML document that I want to convert to a Java bean. It has a lot of tags and attributes, but I'm interested only in a handful of those. Unfurtounately, it seems that XStream forces you to declare a property in that bean for each and every tag that may ever be in that XML. Is there a way around this? 回答1: Initialize XStream as shown below to ignore fields that are not defined in your bean. XStream xstream = new XStream() { @Override protected MapperWrapper wrapMapper

What are the relative advantages of XMLEncoder and XStream?

荒凉一梦 提交于 2019-12-03 04:47:12
Suppose I want to store many small configuration objects in XML, and I don't care too much about the format. The XMLDecoder class built into the JDK would work, and from what I hear, XStream works in a similar way. What are the advantages to each library? I really like the XStream library. It does a really good job of outputting fairly simple xml as a result of a provided Java object. It works great for reproducing the object back from the xml as well. And, one of our 3rd party libraries already depended on it anyway. We chose to use it because we wanted our xml to be human readable. Using the

Cannot construct org.apache.maven.plugin.war.util.WebappStructure as it does not have a no-args constructor

匿名 (未验证) 提交于 2019-12-03 02:44:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: [INFO] [war:war {execution: default-war}] [INFO] Packaging webapp [INFO] ------------------------------------------------------------------------ [ERROR] FATAL ERROR [INFO] ------------------------------------------------------------------------ [INFO] Cannot construct org.apache.maven.plugin.war.util.WebappStructure as it does not have a no-args constructor ---- Debugging information ---- message : Cannot construct org.apache.maven.plugin.war.util.WebappStructure as it does not have a no-args constructor cause-exception : com.thoughtworks

xstream CannotResolveClassException

匿名 (未验证) 提交于 2019-12-03 02:14:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'm trying to use xstream 1.4.2 to convert xml to object. It does work perfectly fine for me until I put the object's class file in a separate package than where the main code runs. Then I get a CannotResolveClassException. I've tried using the setClassLoader method as recommended by others but that doesn't help. Exception in thread "main" com.thoughtworks.xstream.mapper.CannotResolveClassException: result at com.thoughtworks.xstream.mapper.DefaultMapper.realClass(DefaultMapper.java:56) at com.thoughtworks.xstream.mapper.MapperWrapper

Format XML generated by Xstream

匿名 (未验证) 提交于 2019-12-03 01:41:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I want to format the output XML generated by Xstream, to make it more readable. Currently, a newline is added after each element but I would like newline to be added after every attribute. Is there a way to do this? Pretty Print Writer is used by default to format the output of the xml but this doesn't suffice for me. I want newline to be added after every 回答1: XStream includes a PrettyPrintWriter After building your XStream... XStream xstream = //...whatever Instead of: // p is my object needing xml serialization xstream.toXML(p) Use

XStream JavaBeanConverter not serializing properties

匿名 (未验证) 提交于 2019-12-03 01:22:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Attempting to use XStream's JavaBeanConverter and running into an issue. Most likely I'm missng something simple, or not understanding XStream's converter handling well enough. @XStreamAlias("test") public class TestObject { private String foo; public String getFoo() { //return foo; -- Adjusted for EDIT#2 return foo.toLowerCase(); } public void setFoo(String foo) { this.foo = foo; } } public void test() throws Exception { XStream x = new XStream(new XppDriver()); x.autodetectAnnotations(true); x.processAnnotations(TestObject.class); x