xslt

问题 I'm new to XSLT and trying to figure out how to use it to turn this XML: <people> <person> <role>Parent</role> <lastname>Smith</lastname> <locations> <location> <city>Springfield</city> <state>MA</state> <unimportant-field>123</unimportant-field> </location> <location> <city>Chicago</city> <state>IL</state> <unimportant-field>456</unimportant-field> </location> </locations> </person> <person> <role>Child</role> <lastname>Smith</lastname> <locations> <location> <city>Springfield</city> <state

问题 I'm new to XSLT and trying to figure out how to use it to turn this XML: <people> <person> <role>Parent</role> <lastname>Smith</lastname> <locations> <location> <city>Springfield</city> <state>MA</state> <unimportant-field>123</unimportant-field> </location> <location> <city>Chicago</city> <state>IL</state> <unimportant-field>456</unimportant-field> </location> </locations> </person> <person> <role>Child</role> <lastname>Smith</lastname> <locations> <location> <city>Springfield</city> <state

问题 I'm new to XSLT and trying to figure out how to use it to turn this XML: <people> <person> <role>Parent</role> <lastname>Smith</lastname> <locations> <location> <city>Springfield</city> <state>MA</state> <unimportant-field>123</unimportant-field> </location> <location> <city>Chicago</city> <state>IL</state> <unimportant-field>456</unimportant-field> </location> </locations> </person> <person> <role>Child</role> <lastname>Smith</lastname> <locations> <location> <city>Springfield</city> <state

问题 I have the problem with xslt. How to exactly use template to build output like this? I get tired already a long time with this, and it is problematic to use a tag xmlns <?xml version="1.0" encoding="utf-8"?> <books xmlns="http://example.net/books/1.0" xmlns:a="http://example.net/author/1.0"> <book> <a:author> <a:name>John</a:name> <a:surname>Applesed</a:surname> </a:author> <title>Missing opportunity</title> </book> <book> <a:author> <a:name>Paul</a:name> <a:surname>Morgan</a:surname> </a

问题 I am trying to create an xslt file that will take currency values in either EUR, JPY, GBP or USD and present them in an Excel output. To do this, I have created the following condition to capture the currency: <Style ss:ID="s63"> <xsl:choose> <xsl:when test='$currency = "EUR"'> <NumberFormat ss:Format="_("€"\ * #,##0.00_);_("€"\ * \(#,##0.00\);_("€"\ * "-"??_);_(@_)"/> </xsl:when> <xsl:when test='$currency = "JPY"'> <NumberFormat ss:Format="_("¥"\ * #,##0.00_);_("€"\ * \(#,##0.00\);_("€"\ * "

问题 I am trying to create an xslt file that will take currency values in either EUR, JPY, GBP or USD and present them in an Excel output. To do this, I have created the following condition to capture the currency: <Style ss:ID="s63"> <xsl:choose> <xsl:when test='$currency = "EUR"'> <NumberFormat ss:Format="_("€"\ * #,##0.00_);_("€"\ * \(#,##0.00\);_("€"\ * "-"??_);_(@_)"/> </xsl:when> <xsl:when test='$currency = "JPY"'> <NumberFormat ss:Format="_("¥"\ * #,##0.00_);_("€"\ * \(#,##0.00\);_("€"\ * "

问题 I am trying to create an xslt file that will take currency values in either EUR, JPY, GBP or USD and present them in an Excel output. To do this, I have created the following condition to capture the currency: <Style ss:ID="s63"> <xsl:choose> <xsl:when test='$currency = "EUR"'> <NumberFormat ss:Format="_("€"\ * #,##0.00_);_("€"\ * \(#,##0.00\);_("€"\ * "-"??_);_(@_)"/> </xsl:when> <xsl:when test='$currency = "JPY"'> <NumberFormat ss:Format="_("¥"\ * #,##0.00_);_("€"\ * \(#,##0.00\);_("€"\ * "

问题 What XSLT would I use to extract some nodes to output, ignoring others, when the nodes to be be extracted are some times nested nodes to be ignored? Consider: <alpha_top>This prints. <beta>This doesn't. <alpha_bottom>This too prints.</alpha_bottom> </beta> </alpha_top> I want a transform that produces: <alpha_top>This prints. <alpha_bottom>This too prints.</alpha_bottom> </alpha_top> This answer shows how to select nodes based on the presence of a string in the element tag name. 回答1: Ok, here

问题 Given the following structure, how to copy the first and the second nodes with all their elements from the document based on the predicate in XSLT: <list> <slot>xx</slot> <data> <name>xxx</name> <age>xxx</age> </data> <data> <name>xxx</name> <age>xxx</age> </data> <data> <name>xxx</name> <age>xxx</age> </data> </list> <list> <slot>xx</slot> <data> <name>xxx</name> <age>xxx</age> </data> <data> <name>xxx</name> <age>xxx</age> </data> <data> <name>xxx</name> <age>xxx</age> </data> </list> How

问题 Usign XSLT we wish to transform the JSON to XML : <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:math="http://www.w3.org/2005/xpath-functions/math" xmlns:xs="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xs math" version="3.0"> <xsl:output indent="yes" /> <xsl:template match="data"> <xsl:copy-of select="json-to-xml(.)" /> </xsl:template> </xsl:stylesheet> We have follwing JSON output from Microsoft Dynamics 365 that