xslt-2.0

问题 I wish to generate a generic code for parsing special characters in xslt. I wish to replace all special characters found in any node of the xml document with symbols of my choice. eg special characters= "&#174"; also" &#169"; etc I have tried something like follows but nothing happens. <xsl:template match="*"> <xsl:choose> <xsl:when test="contains(.,'&ndash;')"> <xsl:value-of select="replace(.,'&ndash;','-')" /> </xsl:when> </xsl:choose> </xsl:template> the function of character output is:

问题 Basically, what I'm doing right now is running an XSLT, then opening the result in Visual Studio and doing a find and replace for one word - for this example, I want to change all instances of "bar" to "myBar". All instances of "bar" may be assumed to be in text elements like so: <someElement>bar.whatever</someElement> This would be transformed to: <someElement>myBar.whatever</someElement> But the caveat to this is that I'm also running other transformations, such as renaming or moving the

问题 We have the below not well formed input XML which is coming from source system. <?xml version="1.0" encoding="UTF-8"?> <ns0:invoiceOrder xmlns:ns0="http://cts.com" type="ABCD" businessDivision="X0" salesOrganization="XYZ10" Channel="Y0"> <ns0:references> <ns0:key type="Source System">ABC</ns0:key> <ns0:relationship scheme="Customer" schemeAgency="APAC" role="Sell to">703760000</ns0:relationship> <ns0:document type="Purchase Order">AB123</ns0:document> </ns0:references> <ns0:notes> <ns0:note

问题 I am trying to write an if condition inside my data attribute... right now I am receiving the xsml vaue but dont know how to put if there... when i use if outside html it works fine.. providing my code below... http://xsltransform.net/bFukv8i/16 <xsl:if test="//Devices//SideMenu//NavTitleCheckBox='SideMenu'"> Data_Nav_Title="<xsl:value-of select='//Devices//SideMenu//NavTitle'/>" </xsl:if> <article class="banner-hero banner-hero--blocks" data-nav-title="{//Devices//SideMenu//NavTitle}"><

问题 I have almost the same issue for this one: Get value after each last colon. In my case, I need to iterate for every occurrence of :A: and :B:, :B: is a child of :A:. In my code, I am using a call-template which is I'm not very familiar with. But, I need to explore the other functionalities/elements in xslt. Here is my sample test file: <Record> :A:This is sample only 1 :B:This is sample only 2 :B:This is sample only 3 :A:This is sample only 4 :B:This is sample only 5 </Record> Expected output

问题 While transforming XML to XML using XSLT I have included doctype in output XML. But a line break is created in the output XML doctype declaration. XSLT: <xsl:output method="xml" doctype-system="book3.dtd" doctype-public="-//Atypon//DTD test//EN" version="1.0" encoding="UTF-8" indent="no"/> output XML after using XSLT: <!DOCTYPE book PUBLIC "-//Atypon//DTD test//EN" "book3.dtd"> Space and line break are created in between book and public in doctype declaration. I need the doctype declaration

问题 I need to convert a name value pair into XML. I'm able to generate an XML, but the element name should be grouped and it should not be duplicated. Please see below. The FieldValue element contains 2 OrderItem values in the Detail node. If the FieldValue with OrderItem repeats, then the result should be grouped into one OrderItem node. Please help. Source XML: <SC> <Header> <Record> <FieldName>Schema</FieldName> <FieldValue>OrderHeader</FieldValue> </Record> <Record> <FieldName>Order<

问题 I have a requirement to copy the child node from one parent to another based on a employee match but needs to place in a separate node. I have almost got the solution using key, but I am not able to paste the child node in a new separate node. I developed the below code using key function: <?xml version="1.0" encoding="UTF-8"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:wd="urn

问题 I have worked on generating the elements and attributes names along with output elements and attributes. Here I'm converting input xml to docbook xml by using Oxygen XML Editor 18.0. I'm having input xml like: <Section1 id="1"> <Section1Heading>Section 1</Section1Heading> <Section2 id="2"> <Section2Heading>Heading</Section2Heading> <Para>other.</Para> </Section2> </Section1> XSL I'm having: <xsl:template match="Section1"> <sect1> <xsl:attribute name="label"> <xsl:value-of select="@id"/> </xsl

问题 In XSLT, there is a remove() function for sequences. Given a sequence and a position, it returns the sequence minus the item at the given position. The question is: How do I employ this function in an actual XSLT file? The only place I've found mention of an example that isn't just a regurgitation of the function spec completely devoid of context is here: http://books.google.com/books?id=W6SpffnfEPoC&pg=PA776&lpg=PA776&dq=xslt+%22remove+function%22&source=bl&ots=DQQrnXF_nB&sig