xmlns

SEVERE: Allocate exception for servlet <myservlet-name> java.lang.ClassNotFoundException: <myservlet> exception

匿名 (未验证) 提交于 2019-12-03 07:50:05
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: When I use the following web.xml , my project runs fine and I can see "Hello World" getting displayed via index.jsp page. I am using Netbeans 7.4 and Apache tomcat 6.0.41 <?xml version="1.0" encoding="UTF-8"?> <web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd"> <session-config> <session-timeout> 30 </session-timeout> </session-config> </web-app> However, when I created my

DTD约束与schema约束的不同

独自空忆成欢 提交于 2019-12-03 07:18:00
本篇笔记了解------Schema约束的语法       ------可以参考W3school之Schema教程。 Schema: 是基于 XML 的 DTD 替代者,用于描述XML文档结构。 支持 XML 命名空间-----xmlns-- XML namespace的缩写 。      XML Schema语言也称作XML Schema定义(XML Schema Definition,XSD)。      因此,schema文件的 扩展名为 .xsd ,其本身也是个XML文件。 注意: XML Schema是W3c预先规定的一套xml元素和属性创建的,这些元素和属性定义了xml文档的结构和内容模式。    在声明<Schema>文档时, 必须以 XML 声明开头 ,其 根节点是<Schema>。     必须在根节点中声明几个属性: xmlns:xsi="http://www.w3.org/2001/XMLSchema" --表示声明 当前XML文件为一个约束文件,Schema中使用的元素和数据类型、属性来自该命名空间。   targetNamespace属性 ------设置该约束文档的 唯一标识 ,一般设置为URL路径---相当于身份证号, 通过该属性值能引入约束文件。       elementFormDefault属性 :有两个值 qualified 和

springmvc idea 运行 404

一个人想着一个人 提交于 2019-12-03 04:50:58
在最新的idea环境下,使用springmcv 4.x 发布到tomcat的时候,一直报404的问题,在网上查询得知,需要在配置文件里加入 < mvc:annotation-driven /> 完整文件如下所示 <?xml version="1.0" encoding="UTF-8"?> < beans xmlns = "http://www.springframework.org/schema/beans" xmlns:xsi = "http://www.w3.org/2001/XMLSchema-instance" xmlns:context = "http://www.springframework.org/schema/context" xmlns:p = "http://www.springframework.org/schema/p" xmlns:mvc = "http://www.springframework.org/schema/mvc" xsi:schemaLocation = "http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans.xsd http://www.springframework.org/schema

servlet服务器

笑着哭i 提交于 2019-12-03 04:33:42
在项目中的web.xml配置servlet <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://xmlns.jcp.org/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd" version="4.0"> <!-- 告诉servlet这个名字 --> <servlet> <servlet-name>servelt</servlet-name> <servlet-class>com.hei.servelt</servlet-class> </servlet> <!-- 注册servelt的映射,通过访问url这个路径,访问这个servletd的名字 --> <servlet-mapping> <servlet-name>servelt</servlet-name> <url-pattern>/a</url-pattern> </servlet-mapping> <servlet> <servlet-name

How can I validate xsd using apache camel?

匿名 (未验证) 提交于 2019-12-03 02:52:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I'm using apacheservicemix and I try to validate a xml document with apache camel. I have this route called students_route.xml : <?xml version="1.0" encoding="UTF-8"?> <blueprint xmlns="http://www.osgi.org/xmlns/blueprint/v1.0.0" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation=" http://www.osgi.org/xmlns/blueprint/v1.0.0 http://www.osgi.org/xmlns/blueprint/v1.0.0/blueprint.xsd"> <camelContext xmlns="http://camel.apache.org/schema/blueprint"> <route> <from uri="file:project/students.xml"/> <doTry> <to uri="validator

Parsing SOAP response

匿名 (未验证) 提交于 2019-12-03 02:52:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: Calling a web service from my controller: $client = new \SoapClient("http://.../webservice/NAME_OF_PAGE.asmx?WSDL"); $result = $client->EstadoHabitacionesFechas(); I get this: <xs:schema xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" id="NewDataSet"> <xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:MainDataTable="TablaEstadoHabitacion" msdata:UseCurrentLocale="true"> <xs:complexType> <xs:choice minOccurs="0" maxOccurs="unbounded"> <xs:element name="TablaEstadoHabitacion">

SOAPFaultException “MustUnderstand headers (oasis-200401-wss-wssecurity-secext-1.0.xsd) are not understood”

匿名 (未验证) 提交于 2019-12-03 02:50:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I try to get information from web service that uses PasswordText WSS type. Firstly, I test it using soapUI and successfully got data. Then I implemented authentication on Java, writing SecurityHandler: public final class SecurityHandler implements SOAPHandler<SOAPMessageContext> { ... @Override public boolean handleMessage(SOAPMessageContext messageContext) { boolean outInd = (Boolean) messageContext.get(MessageContext.MESSAGE_OUTBOUND_PROPERTY); if (outInd) { try { WSSecUsernameToken builder = new WSSecUsernameToken(); builder

Error: “schemaLocation value *** must have even number of URI&#039;s.” on namespaces in spring dispatcher

匿名 (未验证) 提交于 2019-12-03 02:45:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I was getting following error <Ignored XML validation warning> org.xml.sax.SAXParseException; lineNumber: 9; columnNumber: 55; SchemaLocation: schemaLocation value = 'http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-2.0.xsd http://www.springframework.org/schema/tx' must have even number of URI's. and my dispatcher servlet was having following namespaces <beans xmlns="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:p="http://www

security.xml strange error using Spring

匿名 (未验证) 提交于 2019-12-03 02:34:02
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: I am trying to configure Spring Security in my simple application. Here is my configuration file, security.xml : <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:b="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:jdbc="http://www.springframework.org/schema/jdbc" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/jdbc http://www.springframework.org

Jersey 2.x Security context does not work?

匿名 (未验证) 提交于 2019-12-03 02:31:01
可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效,请关闭广告屏蔽插件后再试): 问题: While i am trying to create java jersey application authentication roles does not work for me. Java code :- package org.student.resource; import javax.annotation.security.PermitAll; import javax.annotation.security.RolesAllowed; import javax.ws.rs.GET; import javax.ws.rs.POST; import javax.ws.rs.Path; import javax.ws.rs.ext.Provider; @Path("/resource") @PermitAll public class Resource { @GET public String get(){ return "GET"; } @RolesAllowed("admin") @POST public String post(){ return "Post content."; } } Deployment descriptor :- <web-app