xml-parsing

问题 When parsing an XML feed, I am getting text from the content tag, like this: The Government has awarded funding for a major refurbishment project to go ahead at St Eunan’s College. This is in addition to last month’s announcement that grant for its prefabs to be replaced with permanent accomodation. The latest grant will allow for major refurbishment to a section of the school to allow for new accommodation for classes – the project will also involve roof repairs, the installation of a dust

问题 I have to fetch the data from xml feed and display on android application. my xml feed is looking like: <root> <Categories> <Category name="Books"> <Articles> <article articleid="4537" title="Android" /> <article articleid="4560" title="Java" /> <article articleid="4585" title="PHP" /> <article articleid="4731" title="MySql" /> </Articles> </Category> <Category name="Names"> <Articles> <article articleid="266" title="Dita" /> <article articleid="268" title="Frieda" /> <article articleid="269"

问题 I am new to simplexml parser in PHP. I have run the examples that I have found and they work as advertised. I can't get it to work with my program though. I have searched in here for hours. I have an XML file called core.xml (note that the node tags have colons in): <?xml version="1.0" encoding="UTF-8" standalone="yes"?> <cp:coreProperties xmlns:cp="http://schemas.openxmlformats.org/package/2006/metadata/core-properties" xmlns:dc="http://purl.org/dc/elements/1.1/" xmlns:dcterms="http://purl

问题 I got some trouble parsing an XML document. For some reason, there are text nodes where I would not expect them to be and therefore my test turns red. The XML file looks like this: <?xml version="1.0" encoding="UTF-8"?> <RootNode> <PR1>PR1</PR1> <ROL>one</ROL> <ROL>two</ROL> <DG1>DG1</DG1> <ROL>three</ROL> <ZBK>ZBK</ZBK> <ROL>four</ROL> </RootNode> Now I have this snippet of code which can reproduce the error: DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();

问题 I am new to XSLT and would like to add Attribute and Value of the same to all parent nodes starting from 2nd parent node. here the logic should be the if there is Main node, the attribute(Mainattribute) should be one time and for rest of all parent nodes under the Main node should have different attribute(childattribute) which should be same across all other than Main node. we have a input xml like below : It is just have some fields only, ideally there will be more tags and may differ. <?xml

问题 I am using XStream to convert XML into domain objects, and have come by a problem. Omitting a few details, the XML looks like this : <airport> <flights> <flight>.....</flight> <flight>.....</flight> <flight>.....</flight> </flights> </airport> There can be 0 to N flight elements. The flight elements themselves contain other elements. I have created classes for airport, flights, and flight and registered them with the xstream.alias function. xstream = new XStream(); xstream.alias("airport",

问题 I spotted a weird behavior in scala xml event reader. For an xml like this: <page> <title>AT&T Bell Labs</title> <ns>0</ns> <id>63739</id> </page> It generates to EvText events for title since it contains the special xml encoding of &. case EvText( text ) => { println(text) } As a result for the code above, I get the output AT T Bell Labs instead of AT&T Bell Labs . 回答1: Entity reference events are represented by their own constructor, EvEntityRef (and in general you shouldn't count on

问题 I can't understand why object is null: WebClient browse = new WebClient(); StreamReader res = new StreamReader(browse.OpenRead("http://ws.audioscrobbler.com/2.0/?method=track.getinfo&api_key=b25b959554ed76058ac220b7b2e0a026&artist=cher&track=believe")); string result = res.ReadToEnd(); XmlDocument xmltrackinfo = new XmlDocument(); xmltrackinfo.InnerXml = result; XmlRootAttribute xRoot = new XmlRootAttribute(); xRoot.ElementName = "lfm"; xRoot.IsNullable = true; XmlSerializer xs = new

问题 I have a XML file, and I want to read it - remove a node - save it. I run perl from terminal (perl script.pl) example XML (filename.xml): <?xml version="1.0" encoding="UTF-8"?> <twice> <inner> <twice> <name>John</name> <surname>Smith</surname> </twice> <twice> <name>Alan</name> <surname>Bowler</surname> </twice> <twice> <name>Michael</name> <surname>Deck</surname> </twice> </inner> </twice> example perl script (script.pl): use strict; use warnings; use XML::LibXML; my $filename = "filename

问题 I am using Simple XML Serialization(simple-xml-2.6.6.jar) here to convert my XML response from webservice to POJO class. XML is as follow: <Alerts> <Alert> <CCRDataObjectID>38</CCRDataObjectID> <DateTime> <Type> <Text>Verified</Text> </Type> <ExactDateTime>2010-06-16T00:00:00Z</ExactDateTime> </DateTime> <Type> <Text>Allergy</Text> </Type> <Description> <Text>R-Tanna</Text> </Description> <Source> <Actor> <ActorID>122</ActorID> </Actor> </Source> <Reaction> <Description> <Text>rash</Text> <