xml-parsing

问题 I'm very new to python and please treat me as same. When i tried to convert the XML content into List of Dictionaries I'm getting output but not as expected and tried a lot playing around. XML Content: <project> <panelists> <panelist panelist_login="pradeep"> <login/> <firstname/> <lastname/> <gender/> <age>0</age> </panelist> <panelist panelist_login="kumar"> <login>kumar</login> <firstname>kumar</firstname> <lastname>Pradeep</lastname> <gender/> <age>24</age> </panelist> </panelists> <

问题 I have a requirement where I have to use an large XML (4 GB file) for finding values in it. Basically I have to write around 30 different Xpath and store the values in a list. When I try to parse an XML, it throws memory error. I have tried using lxml and ElementTree with start and end events, still no luck the processing time is too high and my Pycharm/Jupyter notebook throws me memory error. Is there a better way to do it? Even though this implementation is not restricted to any programming

问题 I have a requirement where I have to use an large XML (4 GB file) for finding values in it. Basically I have to write around 30 different Xpath and store the values in a list. When I try to parse an XML, it throws memory error. I have tried using lxml and ElementTree with start and end events, still no luck the processing time is too high and my Pycharm/Jupyter notebook throws me memory error. Is there a better way to do it? Even though this implementation is not restricted to any programming

问题 I have a requirement where I have to use an large XML (4 GB file) for finding values in it. Basically I have to write around 30 different Xpath and store the values in a list. When I try to parse an XML, it throws memory error. I have tried using lxml and ElementTree with start and end events, still no luck the processing time is too high and my Pycharm/Jupyter notebook throws me memory error. Is there a better way to do it? Even though this implementation is not restricted to any programming

问题 I am trying to validate XML based on xsi:noNamespaceSchemaLocation . I researched this question but it doesn't seem any available solutions for it. My XML file looks this way: <shiporder orderid="889923" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="shiporder.xsd"> <orderperson>John Smith</orderperson> <shipto> <name>Ola Nordmann</name> <address>Langgt 23</address> <city>4000 Stavanger</city> <country>Norway</country> </shipto> <item> <title>Empire

问题 How can one parse HTML/XML and extract information from it? 回答1: Native XML Extensions I prefer using one of the native XML extensions since they come bundled with PHP, are usually faster than all the 3rd party libs and give me all the control I need over the markup. DOM The DOM extension allows you to operate on XML documents through the DOM API with PHP 5. It is an implementation of the W3C's Document Object Model Core Level 3, a platform- and language-neutral interface that allows programs

问题 I have some test code snippet: ​import groovy.xml.XmlUtil class Greet { Greet() { } def salute() { println "Hello !" def input = """ <manifest xmlns:android="http://schemas.android.com/apk/res/android"> <application > <activity android:name="me.aolphn.MainActivity"> </activity> </application> </manifest> """ // def root = new XmlParser(false, true).parseText(input) def root = new XmlSlurper(false, true).parseText(input) root.'application'.@'android:txt'='this is txt' XmlUtil.serialize(root) }

问题 I have the following code which prints out the name of the element I want to remove: import xml.etree.ElementTree as ET tree = ET.parse('myfile.xml') root = tree.getroot() for elem in tree.iter(tag='test'): print elem.tag How do I remove this element from my XML? My XML is similar to the following: <foo> <bar> <level> <test name="1"> <stuff> hello </stuff> </test> <test name="2"> <stuff> hello </stuff> </test> </level> </bar> </foo> 回答1: Based on the information provided, you need to have

问题 This bounty has ended . Answers to this question are eligible for a +50 reputation bounty. Bounty grace period ends in 17 hours . Garret Wilson wants to draw more attention to this question: Surely there must be something going wrong here, especially with the inappropriate xml:space . But what? I'm using Java 11 (AdoptOpenJDK 11.0.5 2019-10-15) on Windows 10. I'm parsing some legacy XHTML 1.1 files, which take the following general form: <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE html

问题 I have the following xml file: <resources> <resource id="res001"> <property name="propA" value="A" /> <property name="propB" value="B" /> </resource> <resource id="res002"> <property name="propC" value="C" /> <property name="propD" value="D" /> </resource> <resource id="res003"> <property name="propE" value="E" /> <property name="propF" value="F" /> </resource> </resources> How can I do something like this with Java/Xml: Xml xml = new Xml("my.xml"); Resource res001 = xml.getResouceById(