words

题目描述： 方法一：暴力O(MN) class Solution: def findSubstring(self, s: str, words: List[str]) -> List[int]: res = [] if not s or not words: return res for j in range(len(s)-len(words[0])*len(words)+1): i = j tmp = words.copy() while i - j <= (len(words)-1)*len(words[0]): if s[i:i+len(words[0])] in tmp: tmp.remove(s[i:i+len(words[0])]) if not tmp: res.append(j) i += len(words[0]) else: break return res 优化： class Solution: def findSubstring(self, s: str, words: List[str]) -> List[int]: from collections import Counter if not s or not words:return [] one_word = len(words[0]) all_len = len(words) * one_word

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'd like to set a parameter based on a parameter which is set when the module is instantiated. I have the following. module foo #(WORDS = 8); parameter P00 = 33; logic [7:0] tmp; generate case (WORDS) 4: begin : A assign tmp = 8'haa; parameter P00 = 4; end 8: begin : B assign tmp = 8'hbb; parameter P00 = 8; end 16: begin : C assign tmp = 8'hcc; parameter P00 = 16; end default: begin : D assign tmp = 8'hdd; parameter P00 = 8; end endcase endgenerate initial begin $display ("WORDS = %d", WORDS); $display ("tmp = %h", tmp); $display ("P00 = %d"

I'm in the early stages of designing a series of simple word games which I hope will help me learn new words. A crucial part of the ideas that I have is a fully parsable dictionary; I want to be able to use regular expressions to search the dictionary for given words and extract certain other bits of information (e.g. definition, type (noun/verb...), synonyms, antonyms, quotes demonstrating the word in use, etc). I currently have Wordbook (mac app) which I find okay, but haven't figured out if I can parse it using a python script. I'm assuming I can't, and was wondering if anyone knows of a

题目： 给定一个字符串，你需要反转字符串中每个单词的字符顺序，同时仍保留空格和单词的初始顺序。 输入: "Let's take LeetCode contest" 输出: "s'teL ekat edoCteeL tsetnoc" 注意： 在字符串中，每个单词由单个空格分隔，并且字符串中不会有任何额外的空格。 解题思路： 先分割每个单词，然后依次翻转单词中的字母。 时间复杂度 O(n) 。 代码实现： class Solution { public String reverseWords ( String s ) { String [] ss = s . split ( " " ) ; StringBuilder builder = new StringBuilder () ; for ( int i = ss . length - 1 ; i >= 0 ; i -- ) { builder . append ( ss [ i ]) ; if ( i > 0 ) builder . append ( " " ) ; } return builder . reverse () . toString () ; } } 文章来源: Leetcode 557. Reverse Words in a String III 反转字符串中的单词 III

This is what I have: <td style='width:500px; white-space: pre-wrap; white-space: -moz-pre-wrap; white-space: -pre-wrap; white-space: -o-pre-wrap; word-wrap: break-word;'> I think this solution will help you! pre { white-space: pre; /* CSS 2.0 */ white-space: pre-wrap; /* CSS 2.1 */ white-space: pre-line; /* CSS 3.0 */ white-space: -pre-wrap; /* Opera 4-6 */ white-space: -o-pre-wrap; /* Opera 7 */ white-space: -moz-pre-wrap; /* Mozilla */ white-space: -hp-pre-wrap; /* HP Printers */ word-wrap: break-word; /* IE 5+ */ } http://perishablepress.com/press/2010/06/01/wrapping-content/ // Edit It's

controller 1 using Aspose.Words; 2 using Aspose.Words.Saving; 3 using System.IO; 4 5 6 /// <summary> 7 /// 获取导入Word 文档 8 /// </summary> 9 /// <param name="PaperId"></param> 10 /// <returns></returns> 11 public ActionResult GetWord(int PaperId) 12 { 13 try 14 { 15 var __data = _paperApp.GetWord(PaperId); 16 string tempPath = Server.MapPath("~/Template/导出模版.docx"); 17 string outputPath = Server.MapPath("~/Resources/Output/模版_temp.doc"); 18 //载入模板 19 var doc = new Document(tempPath); 20 //提供数据源 21 String[] fieldNames = new String[] { "PaperName", "PaperTypeName", "SingleChoiceCount",

sorry for my english. I'm italian. Starting from a list like this: words = ['tree', 'water', 'dog', 'soap', 'bike', 'cat', 'bird'] i want to get (in Python) the sublist between two words that i input by keyboard or in the code. For example, if i put the words 'water' and 'bike' i want to get the sublist: words = ['water', 'dog', 'soap', 'bike'] or if the list is words = ['tree', 'water', 'dog', 'soap', 'tree', 'cat', 'bird'] and i put the words 'tree' and 'tree' i want to get this sublist: words = ['tree', 'water', 'dog', 'soap', 'tree'] I have also wrote a program like this in C, but i'm not