words

问题 I have 10 words. How can I get all possible combinations of 5 words (n=10, k=5) . The order does not matter . For example: "A", "B", "C", if k=2 (n=3 in this case) , it would like AB, BC and AC. Maybe you know some usefull code or example. P.S. Sorry if I'm not right enough cause I don't know English very good. 回答1: What you are trying to do is get all the permutations of a collection. Unique permutations of list permutations of k objects from a set of n algorithm Here is the code snippet:

问题 I have a data file (un-structed messy file) from which I have to scrub specific list of strings (delete strings). Here is what I am doing but with no result: infile = r"messy_data_file.txt" outfile = r"cleaned_file.txt" delete_list = ["firstname1 lastname1","firstname2 lastname2"....,"firstnamen lastnamen"] fin=open(infile,"") fout = open(outfile,"w+") for line in fin: for word in delete_list: line = line.replace(word, "") fout.write(line) fin.close() fout.close() When I execute the file, I

问题 Can I use python to define a word like this: x=raw_input("Enter Word: ") x=define(x) print x Is this possible? If si.. how 2 do it? This IS just a "what if" question.. so no hate plz. 回答1: You can probobally do this using the re and urllib2 modules.. Try this code out dawg. import re import urllib2 def find(x): srch=str(x) x=urllib2.urlopen("http://dictionary.reference.com/browse/"+srch+"?s=t") x=x.read() items=re.findall('<meta name="description" content="'+".*$",x,re.MULTILINE) for x in

问题 There is a great function here Converting words to numbers in PHP from El Yobo. But I have the problem that the string must begin with a written number. How can convert e.g. "iPhone has two hundred and thirty thousand, seven hundred and eighty-three apps" ? The explained function: function wordsToNumber($data) { // Replace all number words with an equivalent numeric value $data = strtr( $data, array( 'zero' => '0', 'a' => '1', 'one' => '1', 'two' => '2', 'three' => '3', 'four' => '4', 'five'

问题 I want to select the first N words of a text string. I have tried split() and substring() to no avail. What I want is to select the first 3 words of the following prayer and copy them to another variable. For example if I have a string: String greeting = "Hello this is just an example" I want to get into the variable Z the first 3 words so that Z = "Hello this is" 回答1: String myString = "Copying first N numbers of words to a string"; String [] arr = myString.split("\\s+"); //Splits words &

问题 This question already has an answer here : Read text from file skipping any spaces or empty lines (1 answer) Closed 5 years ago . Hi. I need to read several files without empty lines between words.They can have different layouts, such as 1.txt or 2.txt: 1.txt: treg hreger ig srg fre ig lre eg 2.txt: lregreg igregr kreggerg ereherh tershs hsehsteh asreh treshse How do i do that ? How can I count the number of words in the fastest way? I just have the following code: #include <stdio.h> #include

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 2 years ago . Here is the code I have: string words[n]; . . . for(int j = 0; j < sizeof(words)/sizeof(words[0]); j++){ if(words[j].find(new_word) != std::string::npos){...} //abort(3) called } However, SIGABRT isn't called in the same code when I call find on a normal string, like for(int j = 0; j < sizeof(words)/sizeof(words

问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 years ago . I would like to calculate unique words count in a table with jQuery or maybe SQL. I have no clue at the moment how to do this. So please forgive me when i dont give you my tries. This is the table: <table> <tr class="odd"> <td>450€ Job</td> <td>Aachen</td> </tr> <tr class="even"> <td>500€ Job</td> <td>Berlin</td

问题 i found a solution similar to my problem here: import java.util.Scanner; public class Counter { public static void main ( String args[] ) { String a = "", b = ""; Scanner s = new Scanner( System.in ); System.out.println( "Enter a string: " ); a = s.nextLine(); while ( b.length() != 1 ) { System.out.println( "Enter a single character: " ); b = s.next(); } int counter = 0; for ( int i = 0; i < a.length(); i++ ) { if ( b.equals(a.charAt( i ) +"") ) counter++; } System.out.println( "Number of

问题 I have about 500 sentences in which I would like to compile a set of ngrams. I am having trouble removing the stop words. I tried adding the lucene StandardFilter and StopFilter but I still have the same problem. Here is my code: for(String curS: Sentences) { reader = new StringReader(curS); tokenizer = new StandardTokenizer(Version.LUCENE_36, reader); tokenizer = new StandardFilter(Version.LUCENE_36, tokenizer); tokenizer = new StopFilter(Version.LUCENE_36, tokenizer, stopWords); tokenizer =