word-count

问题 I have the following list of tuples: [('a', 1), ('a', 1), ('b', 1), ('c',1), ('a', 1), ('c', 1)] I would like to know if I can utilize python's reduce function to aggregate them and produce the following output : [('a', 3), ('b', 1), ('c', 2)] Or if there are other ways, I would like to know as well (loop is fine) 回答1: It seems difficult to achieve using reduce , because if both tuples that you "reduce" don't bear the same letter, you cannot compute the result. How to reduce ('a',1) and ('b'

问题 I have the following list of tuples: [('a', 1), ('a', 1), ('b', 1), ('c',1), ('a', 1), ('c', 1)] I would like to know if I can utilize python's reduce function to aggregate them and produce the following output : [('a', 3), ('b', 1), ('c', 2)] Or if there are other ways, I would like to know as well (loop is fine) 回答1: It seems difficult to achieve using reduce , because if both tuples that you "reduce" don't bear the same letter, you cannot compute the result. How to reduce ('a',1) and ('b'

问题 I have the following list of tuples: [('a', 1), ('a', 1), ('b', 1), ('c',1), ('a', 1), ('c', 1)] I would like to know if I can utilize python's reduce function to aggregate them and produce the following output : [('a', 3), ('b', 1), ('c', 2)] Or if there are other ways, I would like to know as well (loop is fine) 回答1: It seems difficult to achieve using reduce , because if both tuples that you "reduce" don't bear the same letter, you cannot compute the result. How to reduce ('a',1) and ('b'

问题 I have the following list of tuples: [('a', 1), ('a', 1), ('b', 1), ('c',1), ('a', 1), ('c', 1)] I would like to know if I can utilize python's reduce function to aggregate them and produce the following output : [('a', 3), ('b', 1), ('c', 2)] Or if there are other ways, I would like to know as well (loop is fine) 回答1: It seems difficult to achieve using reduce , because if both tuples that you "reduce" don't bear the same letter, you cannot compute the result. How to reduce ('a',1) and ('b'

问题 I have a string: var text = @" I have a long string with a load of words, and it includes new lines and non-letter characters. I want to remove all of them and split this text to have one word per line, then I can count how many of each word exist." What is the best way to go about removing all non-letter characters, then splitting each word onto a new line so I can store and count how many of each word there are? var words = text.Split(' '); foreach(var word in words) { word.Trim(',','.','-'

问题 How can I manage to change a setting of a plugin dynamically when CKEDITOR instances are created? I wrote in a custom config.js: config.wordcount = { // Whether or not you want to show the Word Count showWordCount: false, // Whether or not you want to show the Char Count showCharCount: true }; What I want to do is to set maxCharCount to something, depending on the CKEDITOR instance. Is there an easy way to achieve this? 回答1: Found the solution: CKEDITOR.replace('field', { wordcount: {

来源： https://stackoverflow.com/questions/37630502/python-count-of-occurrences-in-dict-from-another-list

问题 I have a list of strings in cells - 1000s of them - and I need to work out the characters per word but separated by word - preferably in 1 swift formula... For Example: 1. "Black Cup With Handle" > Formula I need > 5,3,4,6 "Giant Bear Statue" > Formula I need > 5,4,6 I need this for a recurring task which has been macro'd in a very inefficient way to count words into columns (of which we need to use up to 20 for the just encase) but this needs to be tackled. Usually, we count the spaces and

问题 I wrote a code for word count in python. I wanted to get text and frequency of each words from the following page: http://www.holybible.or.kr/B_NIV/cgi/bibleftxt.php?VR=NIV&VL=1&CN=1&CV=99 Problem is that my program is giving me the word count divided by each verses, but I want it undivided. Please help me on that. import requests from bs4 import BeautifulSoup import operator def start(url): word_list = [] source_code = requests.get(url).text soup = BeautifulSoup(source_code, "html.parser")

问题 Here's what I have so far: import string So I have the user write a 5 worded sentence asking for only 5 words: def main(sentence = raw_input("Enter a 5 worded sentence: ")): if len(words)<5: words = string.split(sentence) wordCount = len(words) print "The total word count is:", wordCount If the user inputs more than 5 words: elif len(words)>5: print 'Try again. Word exceeded 5 word limit' Less than 5 words: else: print 'Try again. Too little words!' It keeps stating that: UnboundLocalError: