winner

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I'm setting values for properties of my NSManagedObject , these values are coming from a NSDictionary properly serialized from a JSON file. My problem is, that, when some value is [NSNull null] , I can't assign directly to the property: fight.winnerID = [dict objectForKey:@"winner"]; this throws a NSInvalidArgumentException "winnerID"; desired type = NSString; given type = NSNull; value = <null>; I could easily check the value for [NSNull null] and assign nil instead: fight.winnerID = [dict objectForKey:@"winner"] == [NSNull null] ? nil :

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have an int I intend to broadcast from root ( rank==(FIELD=0) ). int winner if (rank == FIELD) { winner = something; } MPI_Barrier(MPI_COMM_WORLD); MPI_Bcast(&winner, 1, MPI_INT, FIELD, MPI_COMM_WORLD); MPI_Barrier(MPI_COMM_WORLD); if (rank != FIELD) { cout << rank << " informed that winner is " << winner << endl; } But it appears I get [JM:6892] *** An error occurred in MPI_Bcast [JM:6892] *** on communicator MPI_COMM_WORLD [JM:6892] *** MPI_ERR_TRUNCATE: message truncated [JM:6892] *** MPI_ERRORS_ARE_FATAL: your MPI job will now abort

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: My task it to write a program that asks the user to enter 5 names which it stores in a list. Next, get it to pick one of these names at random and declare that person as the winner. The only issue is that when i try to run it, it says can't assign to literal This is my code: import random 1=input("Please enter name 1:") 2=int(input('Please enter name 2:')) 3=int(input('Please enter name 3:')) 4=int(input('Please enter name 4:')) 5=int(input('Please enter name 5:')) name=random.randint(1,6) print('Well done '+str(name)+'. You are the winner!'

题目： Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the next player. This continues until all the scores have been chosen. The player with the maximum score wins. Given an array of scores, predict whether player 1 is the winner. You can assume each player plays to maximize his score. Example 1: Input : [ 1 , 5 , 2 ] Output : False Explanation : Initially , player 1 can choose between 1 and 2. If he

题目链接： https://nanti.jisuanke.com/t/40259 Ichuan really likes to play games, so he organized a game competition with N N participating players. Follows are the rule of the game competition. There are three modes in the game, in each mode, players have different ability values, in addition, each player may have different ability value in different mode. There are a total of N-1 matches. In each match, two players who have not yet been eliminated will play against each other in one of the modes. The player who has high ability in this mode will win, and the other one will be eliminated. The only

Given an array of scores that are non-negative integers. Player 1 picks one of the numbers from either end of the array followed by the player 2 and then player 1 and so on. Each time a player picks a number, that number will not be available for the next player. This continues until all the scores have been chosen. The player with the maximum score wins. Given an array of scores, predict whether player 1 is the winner. You can assume each player plays to maximize his score. Example 1: Input: [1, 5, 2] Output: False Explanation: Initially, player 1 can choose between 1 and 2. If he chooses 2

Java从入门到放弃26―线程的三种创建方式之实现Runnable接口 01 Runnable接口 Runnable 接口应该由那些打算通过某一线程执行其实例的类来实现。类必须定义一个称为 run 的无参数方法。 Runnable 为非 Thread 子类的类提供了一种激活方式。通过实例化某个 Thread 实例并将自身作为运行目标，就可以运行实现 Runnable 的类而无需创建 Thread 的子类。大多数情况下，如果只想重写 run() 方法，而不重写其他 Thread 方法，那么应使用 Runnable 接口。 接口中的方法 Runnable接口中仅包含唯一一个抽象方法，因此它是一个函数式接口（Functional Interface）。可以通过Lambda表达式简化表达。 方法摘要 void **run**() 使用实现接口 Runnable 的对象创建一个线程时，启动该线程将导致在独立执行的线程中调用对象的 run 方法。 02 创建线程 通过实现Runnable接口创建线程的具体步骤： step1：实现runable接口 step2：创建runable接口实现类 step3：启动线程。需要创建一个线程Thread对象，然后把Runable接口的实现类的实例放入构造参数里，调用start方法启动。 代码示例 03 案例 案例1：抢票 public class

there are N ACMers in HDU team. ZJPCPC Sunny Cup 2007 is coming, and lcy want to select some excellent ACMers to attend the contest. There have been M matches since the last few days(No two ACMers will meet each other at two matches, means between two ACMers there will be at most one match). lcy also asks"Who is the winner between A and B?" But sometimes you can't answer lcy's query, for example, there are 3 people, named A, B, C.and 1 match was held between A and B, in the match A is the winner, then if lcy asks "Who is the winner between A and B", of course you can answer "A", but if lcy ask

<!DOCTYPE html> <html lang=" en"> <head> <meta charset=" UTF-8"> <meta name=" viewport" content=" width=device-width, initial-scale=1.0"> <meta http-equiv=" X-UA-Compatible" content=" ie=edge"> <title>Document </title> <script src=" jquery-3.4.1.js "> </script> <style> .container { width: 970px; margin: 0 auto; } header { text-align: center; width: 150px; height: 130px; margin: 0 auto; font-size: 45px; line-height: 130px; } .luckyPeople { height: 150px; border: 3px solid red; text-align: center; line-height: 150px; font-size: 128px; } .btn, .common, .winner { width: 150px; margin: 10px auto;

习题地址： http://sqlzoo.net/1b.htm 表结构：　　nobel(yr, subject, winner) 1a. Change the query shown so that it displays Nobel prizes for 1950. select * from nobel where yr = 1950 1b. Show who won the 1962 prize for Literature. select winner from nobel where yr = 1962 and subject = ' Literature ' 2a. Show the year and subject that won 'Albert Einstein' his prize. select yr, subject from nobel where winner = ' Albert Einstein ' 2b. Give the name of the 'Peace' winners since the year 2000, including 2000. select winner from nobel where subject = ' Peace ' and yr >= 2000 2c. Show all details (yr, subject,