weekend

How to get all weekends within date range in C# [closed]

半世苍凉 提交于 2019-12-06 05:51:33
Closed . This question needs to be more focused . It is not currently accepting answers. Want to improve this question? Update the question so it focuses on one problem only by editing this post . Closed 5 years ago . I am just wondering if there is a simple way or framework to to get all weekends within date range in C#? Is it possible to do with LINQ as well? Any clue? Thank you! If you make a way to enumerate all days, you can use linq to filter to weekends: IEnumerable<DateTime> GetDaysBetween(DateTime start, DateTime end) { for (DateTime i = start; i < end; i = i.AddDays(1)) { yield

Add hours to datetime but exclude weekends and should be between working hours

橙三吉。 提交于 2019-12-05 10:56:45
I am trying to add hours to a date but want the new date to exclude weekends and only be between 9.00 to 17.00. example: first scenario: if my date is 23/02/2012 16:00:00. if I add 4 hours to that my new date should be 24/02/2012 12:00:00 (which will be within working hours) second scenario: if my date is 24/02/2012 09:00:00 (which is a friday) if I add 24 hours then the new date should be 27/02/2012 09:00:00 (which would be monday next week at 9am) so far I got this but am stuck as this will not count for any date that is in past say date passed was 10/02/2012(Friday last week) : private

Get weekdays within a month

江枫思渺然 提交于 2019-12-04 16:46:11
I'm trying to get the dates within a given month. My plan is to Get the start and the end dates of a given month,. Get all the dates that fall within that range. Iterate through them and eliminate dates that fall within a weekend using the isDateInWeekend method. The remaining dates are the weekdays. So I created two NSDate extension methods to get the start and the end dates of the month. extension NSDate { var startOfMonth: NSDate { let calendar = NSCalendar.currentCalendar() let components = calendar.components([.Year, .Month], fromDate: self) return calendar.dateFromComponents(components)!

Php add 5 working days to current date excluding weekends (sat-sun) and excluding (multiple) holidays

喜夏-厌秋 提交于 2019-12-04 14:54:49
问题 For delivery of our webshop, we need to calculate 5 working days from the current date in php. Our working days are from monday to friday and we have several closing days (holidays) which cannot be included either. I've found this script, but this doesn't include holidays. <?php $_POST['startdate'] = date("Y-m-d"); $_POST['numberofdays'] = 5; $d = new DateTime( $_POST['startdate'] ); $t = $d->getTimestamp(); // loop for X days for($i=0; $i<$_POST['numberofdays']; $i++){ // add 1 day to

sql oracle ignore holidays

假如想象 提交于 2019-12-04 13:41:22
I am using this code to calculate the difference between two dates ignoring weekends: SELECT To_date(SYSDATE) - To_date('01.07.2014', 'DD.MM.YYYY') - 2 * ( TRUNC(Next_day(To_date(SYSDATE) - 1, 'FRI')) - TRUNC( Next_day(To_date('01.07.2014' , 'DD.MM.YYYY') - 1, 'FRI')) ) / 7 AS DAYS_BETWEEN FROM dual I have another table called table1 in which the column "date" exists (its type is "DATE") in which all dates where a holiday is are written down. Example table 1: DATES 12.06.2011 19.06.2014 09.05.2013 ... I am trying to make my code check this table and that if one date is between the two dates

Get number of weekdays in a given month

狂风中的少年 提交于 2019-11-27 15:41:44
I want to calculate the number of weekdays days in a give month and year. Weekdays means monday to friday. How do i do it ? Some basic code: $month = 12; $weekdays = array(); $d = 1; do { $mk = mktime(0, 0, 0, $month, $d, date("Y")); @$weekdays[date("w", $mk)]++; $d++; } while (date("m", $mk) == $month); print_r($weekdays); Remove the @ if your PHP error warning doesn't show notices. You don't need to count every day in the month. You already know the first 28 days contain 20 weekdays no matter what. All you have to do is determine the last few days. Change the start value to 29. Then add 20

Determine if Oracle date is on a weekend?

自闭症网瘾萝莉.ら 提交于 2019-11-27 12:50:37
Is this the best way to determine if an Oracle date is on a weekend? select * from mytable where TO_CHAR (my_date, 'DY', 'NLS_DATE_LANGUAGE=ENGLISH') IN ('SAT', 'SUN'); As of Oracle 11g, yes. The only viable region agnostic alternative that I've seen is as follows: SELECT * FROM mytable WHERE MOD(TO_CHAR(my_date, 'J'), 7) + 1 IN (6, 7); Not an answer to the question . But some more information. There are many more SQL tricks with date. to_char(sysdate, 'd') --- day of a week, 1,2,3 .. to 7 to_char(sysdate, 'dd') --- day of a month, 1,2,3 .. to 30 or 31 to_char(sysdate, 'ddd') --- day of a year

In Java, get all weekend dates in a given month

若如初见. 提交于 2019-11-27 05:05:37
I need to find all the weekend dates for a given month and a given year. Eg: For 01(month), 2010(year), the output should be : 2,3,9,10,16,17,23,24,30,31, all weekend dates. Here is a rough version with comments describing the steps: // create a Calendar for the 1st of the required month int year = 2010; int month = Calendar.JANUARY; Calendar cal = new GregorianCalendar(year, month, 1); do { // get the day of the week for the current day int day = cal.get(Calendar.DAY_OF_WEEK); // check if it is a Saturday or Sunday if (day == Calendar.SATURDAY || day == Calendar.SUNDAY) { // print the day -

Remove weekend data in a dataframe

∥☆過路亽.° 提交于 2019-11-26 23:12:10
问题 As you can see from the dataframe below, RBloomberg returns NAs for weekend dates. I want to remove the entire row if it falls on a weekend. How would I do this? I don't want to use the na.omit as this might remove weekday rows if/when I get an NA there in the data for a legitimate reason. ticker date yld_ytm_mid 1 R206 2011-05-11 6.946 2 R206 2011-05-12 6.969 3 R206 2011-05-13 7.071 4 R206 2011-05-14 NA 5 R206 2011-05-15 NA 6 R201 2011-05-11 7.201 7 R201 2011-05-12 7.213 8 R201 2011-05-13 7

Count days between two dates, excluding weekends (MySQL only)

…衆ロ難τιáo~ 提交于 2019-11-26 23:06:26
I need to calculate the difference (in days) between two dates in MySQL excluding weekends (Saturday and Sunday). That is, the difference in days minus the number of Saturday and Sunday in between. At the moment, I simply count the days using: SELECT DATEDIFF('2012-03-18', '2012-03-01') This return 17 , but I want to exclude weekends, so I want 12 (because the 3rd and 4th, 10th and 11th and 17th are weekends days). I do not know where to start. I know about the WEEKDAY() function and all related ones, but I do not know how to use them in this context. biziclop Illustration: mtwtfSSmtwtfSS