weekday

问题 When a user visits a page I need to check if the current time falls between 9:00 am and 5:30pm on a weekday and display something using jquery/javascript.But I am not sure how can check that. Could someone please help? Thanks 回答1: This should hopefully help: function checkTime() { var d = new Date(); // current time var hours = d.getHours(); var mins = d.getMinutes(); var day = d.getDay(); return day >= 1 && day <= 5 && hours >= 9 && (hours < 17 || hours === 17 && mins <= 30); } 回答2: var now

问题 When a user visits a page I need to check if the current time falls between 9:00 am and 5:30pm on a weekday and display something using jquery/javascript.But I am not sure how can check that. Could someone please help? Thanks 回答1: This should hopefully help: function checkTime() { var d = new Date(); // current time var hours = d.getHours(); var mins = d.getMinutes(); var day = d.getDay(); return day >= 1 && day <= 5 && hours >= 9 && (hours < 17 || hours === 17 && mins <= 30); } 回答2: var now

来源： https://stackoverflow.com/questions/29096381/num-day-to-name-day-with-pandas

来源： https://stackoverflow.com/questions/29096381/num-day-to-name-day-with-pandas

问题 I need help please, How can I calculate business hours between two dates? For example we have two dates; 01/01/2017 10:00 and 04/01/2017 15:00. And we have working hours 09:30 to 17:30 (8 hours) on weekdays. How can I calculate working hours and minutes with Java? Thanks for your help. 回答1: Off the top of my head. Let me suggest you begin by studying the java.time package with subpackages, the modern Java date and time API. There’s an Oracle tutorial as well as other good reading material on

问题 I want to calculate the number of weekdays days in a give month and year. Weekdays means monday to friday. How do i do it ? 回答1: Some basic code: $month = 12; $weekdays = array(); $d = 1; do { $mk = mktime(0, 0, 0, $month, $d, date("Y")); @$weekdays[date("w", $mk)]++; $d++; } while (date("m", $mk) == $month); print_r($weekdays); Remove the @ if your PHP error warning doesn't show notices. 回答2: You don't need to count every day in the month. You already know the first 28 days contain 20

问题 My data looks like this for one column: Date AED.USD 03/01/2005 3.6726 04/01/2005 3.6726 05/01/2005 3.6725 06/01/2005 3.6726 07/01/2005 3.6725 08/01/2005 NA 09/01/2005 NA 10/01/2005 3.6726 11/01/2005 3.6725 12/01/2005 3.6726 13/01/2005 3.6725 14/01/2005 3.6726 15/01/2005 NA 16/01/2005 NA 17/01/2005 3.6725 18/01/2005 3.6726 19/01/2005 3.6725 20/01/2005 3.6725 21/01/2005 3.6725 I want to remove the dates with the weekends, I have tried using x <- seq(as.Date("2005-01-03"),as.Date("2016-11-30")

问题 I used this script to create a calendar with JavaScript. I rewrote it enough, for instance, I built viewing of the previous and next month's days, viewing previous or next month, etc. But the basic algorithm remains the same as it was written in that article (for loops "// fill in the days"). Well now, when everything works pretty good, I need the first day of the week to be Monday, not Sunday. Unfortunately, I can't imagine how to change the loops in order this feature to work. So, how do I

问题 I have the following query which gives me the visit_date for each client: select visit_date from visit The output of the above query is the timestamp when the entry was inserted into the Database , it will appear as follows : visit_date 2013-12-21 06:31:04 2013-12-21 11:05:30 2013-12-21 23:03:12 How can I convert the above date to days of the week in MySQL? 回答1: Check MySQL DATETIME FUNCTIONS to fetch day of week or day name or day of month or day of year Try this: SELECT DAYOFWEEK(visit_date

问题 How can I make chosen page to display as homepage of my multisite site depending on a week day? I have this function to display my page depending if user is logged in or not, next I want it to work differently during tuesday (picking different pages as follows): function switch_homepage() { if ( is_main_site() ) { // Do stuff only for the main site if ( is_user_logged_in() ) { $page = 4284; // for logged in users update_option( 'page_on_front', $page ); update_option( 'show_on_front', 'page'