virtualization

In Docker ,guest OS share same kernel as Host OS have . Can someone elaborate more on it. Let I have centos os which have some kernel version ,when we pull ubuntu image then it have different kernel ,then how can we say that they have same kernel? when we pull ubuntu image then it have different kernel No it does not: it does not have the kernel part: it relies on the kernel of the host (the one running docker engine) for all system calls . As mentioned in " Docker vs Virtualization ": Initially Docker was built as an abstraction layer on top of Linux Containers (LXC). LXC itself is a just an

In full emulation the I/O devices, CPU, main memory are virtualized. The guest operating system would access virtual devices not physical devices. But what exactly is full virtualization? Is it the same as full emulation or something totally different? Emulation and virtualization are related but not the same. Emulation is using software to provide a different execution environment or architecture. For example, you might have an Android emulator run on a Windows box. The Windows box doesn't have the same processor that an Android device does so the emulator actually executes the Android

Since the release of Win Vista, Microsoft introduced file virtualization for legacy applications running as 32bit processes. Released as part of Microsoft's User Account Control (UAC) any legacy applications attempting to write to any locations considered protected by the operating system are redirected to the VirtualStore. At this point, steps have been taken to ensure that the application in question now runs as a 64bit process that is UAC aware, however, this does little to address the issue of migrating the users data to a location that is considered safe from virtualization. While

We currently have a DataGrid that is bound to a DataTable . It also has a template column with a CheckBox in it that we add in programatically. This purpose of this column is track multiple selections in the DataGrid . A factory is used to create the CheckBox es for each row. There are quite a few records, so row virtualization is set to true so that the performance is acceptable. However, we're seeing a strange issue where if we check some CheckBox es on the first 10 rows and then scroll down about 50 rows (the grid has about 10 rows visible at any one time), there are a bunch of other

Originally I believed the overhead to a context-switch was the TLB being flushed. However I just saw on wikipedia: http://en.wikipedia.org/wiki/Translation_lookaside_buffer In 2008, both Intel (Nehalem)[18] and AMD (SVM)[19] have introduced tags as part of the TLB entry and dedicated hardware that checks the tag during lookup. Even though these are not fully exploited, it is envisioned that in the future, these tags will identify the address space to which every TLB entry belongs. Thus a context switch will not result in the flushing of the TLB – but just changing the tag of the current