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How to use addView to add view to layout?

由 妖精的绣舞 提交于 2020-04-08 19:03:19
问题 I have read probably all posts and documentation but I still can't solve this issue. I want to use addView() method to add view to the existing (running) layout but for some reason I cant. I know that this should be easy and basic but still I cant do it. So, please help me. Here is a code: LinearLayout layout = (LinearLayout)findViewById(R.id.mainLayout); TextView text = new TextView(this); text.setText("test"); layout.addView(text); That's a code, and the result is that I have displayed only

How to use addView to add view to layout?

由 ぃ、小莉子 提交于 2020-04-08 19:01:38
问题 I have read probably all posts and documentation but I still can't solve this issue. I want to use addView() method to add view to the existing (running) layout but for some reason I cant. I know that this should be easy and basic but still I cant do it. So, please help me. Here is a code: LinearLayout layout = (LinearLayout)findViewById(R.id.mainLayout); TextView text = new TextView(this); text.setText("test"); layout.addView(text); That's a code, and the result is that I have displayed only

MS SQL Server View not allowing CONCAT

由 非 Y 不嫁゛ 提交于 2020-04-07 08:00:06
问题 MS SQL Server 2014. I have a SQL statement that works fine: SELECT CONCAT ( CAST(T1.[F1] AS INTEGER), CAST(T1.[F2] AS INTEGER) ) AS F3 FROM mytable AS T1 If I then put this into a view, and try to run I receive the error: Operand data type int is invalid for concat operator F1 and F2 both contain decimals but I want them concatenating e.g.: F1 = 123.00000 F2 = 456.00000 Therefore F3 = 123456 Why does the view not allow this and is there a solution? 回答1: Don't use the visual designers. They

How to detect swipe between views to make path across them in android java?

由 末鹿安然 提交于 2020-04-07 07:35:28
问题 I am trying to make game for which there are buttons with alphabets and if user swipes over them then it should detect the views as well as make a line across them. I searched many tutorials, examples and questions but unable to get the idea. I have attached image to help understand the question. Here are the codes: MainActivity.java package com.example.detecttouch; import androidx.appcompat.app.AppCompatActivity; import android.graphics.Rect; import android.os.Bundle; import android.util.Log

ViewPager嵌套ViewPager 滑动冲突

由 杀马特。学长 韩版系。学妹 提交于 2020-03-26 05:20:49
我在网上找了许多解决方法。但都不是很完美。 当进入子viewpager确实解决了子viewpager的滑动，但是父viewpager就失效了。现在奉上修改过的代码给大家。 //别忘了布局引用也要变 /** * <com.jing.meknow.ChildViewPager * android:id="@+id/iask_main_view_pager" * android:layout_width="match_parent" * android:layout_height="0px" * android:layout_weight="1" * > * </com.jing.meknow.ChildViewPager> */ package com.jing.meknow; import android.content.Context; import android.graphics.PointF; import android.support.v4.view.ViewPager; import android.util.AttributeSet; import android.view.MotionEvent; import android.view.View; public class ChildViewPager extends ViewPager { public

Create a WebView without xml

由 你离开我真会死。 提交于 2020-03-26 04:12:55
问题 For some reason (like loading and don't think too long) i need to create by code a web view and show it after 2s not immediately i have a pointer to my context. i have a id for my relative layout. I have try some code but i see nothing i don't know if it's the position who is bad or the view. So what is the good way to make a simple web View who match_parent without any XML? any sample somewhere? what i have try (i know it's not in match parent it's a test or see the limite of the view if she

Create a WebView without xml

由 廉价感情. 提交于 2020-03-26 04:09:21
问题 For some reason (like loading and don't think too long) i need to create by code a web view and show it after 2s not immediately i have a pointer to my context. i have a id for my relative layout. I have try some code but i see nothing i don't know if it's the position who is bad or the view. So what is the good way to make a simple web View who match_parent without any XML? any sample somewhere? what i have try (i know it's not in match parent it's a test or see the limite of the view if she

Sorting GridView Formed With Data Set

由 99封情书 提交于 2020-03-25 08:40:07
问题 The following code sample is for sorting a GridView formed With a DataSet . Source: http://www.highoncoding.com/Articles/176_Sorting_GridView_Manually_.aspx But it is not displaying any output. There is no problem in sql connection. I am unable to trace the error, please help me. Thank You. public partial class _Default : System.Web.UI.Page { private const string ASCENDING = " ASC"; private const string DESCENDING = " DESC"; private DataSet GetData() { SqlConnection cnn = new SqlConnection(

Editing file name when using export-view in Netlogo

由 拟墨画扇 提交于 2020-03-25 05:52:08
问题 I want to use export-view to save an image of my model. I have made a button in the interface to export image (JPG, PNG, or PDF) from the Netlogo. this is my current code in the export-view button file-open user-new-file export-view (word "view1.jpg") set view-number view-number + 1 Currently, file-open command helps in showing a pop-up input window before saving. There is a runtime error of "FILE-OPEN expected input to be a string but got the TRUE/FALSE false instead". I can still save the

fourColor-01

由 被刻印的时光 ゝ 提交于 2020-03-23 17:18:37
四、UIViewController生命周期 (1)第一次访问UIViewController的view时，view为nil，然后就会调用loadView方法创建view，通过懒加载的方式进行加载。 (2)重写loadView方法，可以根据重写loadView方法创建View。 (3)View创建完毕后会调用viewDidLoad方法进行界面元素的初始化。 (4)StoryBoard加载的是控制器及控制器View。 (5)XIB加载的仅仅是控制器View。 来源： https://www.cnblogs.com/wwbb/p/12552990.html
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