video-streaming

问题 I'm building an iOS app that Stream's video from Google drive the videos link looks like this https://drive.google.com/file/d/0B2Kri7-TaAFJSlJ4UTJuSElGamM/preview The only way to get the Stream Link from the URL above is by Decoding the webView HTML Code: let myURLString = "https://drive.google.com/file/d/0B2Kri7-TaAFJSlJ4UTJuSElGamM/preview" if let myURL = NSURL(string: myURLString) { do { let myHTMLString = try String(contentsOfURL: myURL, encoding: NSUTF8StringEncoding) print("HTML : \

问题 I am using embedded wmv player in my web project(jsp) to play *.avi files which are located on the server. When i click on the links in jsp they work fine, the video is being played. But when i try to open the page on another machine, the embedded player does not work, instead its downloading the file from the server. This is the code i used <script type="text/javascript"> function play(media){ document.getElementById('mediaplayer').innerHTML= '<object classid="clsid:22d6f312-b0f6-11d0-94ab

问题 I am streaming HTML 5 video with Express using fs.createReadStream(path).pipe(res); which eventually causes the error Error: EMFILE: too many open files if I refresh the page too many times (in the thousands). I assume I need to perform some kind of cleanup and close the file to prevent this but am unsure what needs to be done. I am creating a read stream every time the user seeks to a part of the video which the client has not loaded which makes this problem happen in a matter of minutes.

问题 We have an mjpeg video, obtained from the webcam and stored into *.avi file, still encoded as mjpeg. We need to restream this file as rtsp (and stil preserve the mjpeg there, i.e. no decoding). The goal is to emulate the webcam this video was obtained from for the software that processes the video. The file can be open with vlc/ffplay with no problems. The ffmpeg behaves like it is streaming it, however, ffplay/vlc can't open this stream. We tried to stream if with gstreamer. 1) we fount no

问题 i am developing an android app for my ip camera, and the camera has some specific api commands that it can respond to. the problem i am stuck on is that i want to display a list of videos available on the memory card of the camera. I am getting the file list but i also want to get the thumbnails of those files. The problem in getting the thumbnail is that i don't have any direct IP address of the video, the camera only provides me two things for accessing the video 1. RTSP URL of the video 2.

问题 I have used flask app for straming video via raspberrypi camera. The code i used for flask app is here: https://blog.miguelgrinberg.com/post/video-streaming-with-flask In local server it is doing video stream but not on my website. I am using apache2 server having wsgi file below: flaskapp2.wsgi #!/usr/bin/python import sys import logging logging.basicConfig(stream=sys.stderr) sys.path.insert(0,"/var/www/FlaskApp2/FlaskApp2") from ashish import app as application application.secret_key =

问题 I have an App that is receiving a video file from another App that is working as a Server. While the App is saving the file received on the socket, the video stream starts playing the file (which is under construction). In the code sample, after I press the btnStream, I press the btnPlay and App runs successfully. However, if the playing rate is greater than the download rate, an error will occur. I want to avoid this case. So I need to have a listener on the Video Playing that will pause the

问题 I'm developing an APP that needs to gets the stream of an Airdrone through mjpeg. I'm using the classes from this topic. It works great with the example but I need to add some other elements to the same view such as the buttons to control de airdrome. The example code: @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); ... mv = new MjpegView(this); setContentView(mv); ... What i'm trying to do but is not working... ... mv = (MjpegView) findViewById

问题 I am trying to create a live "video" stream using an tag on a web page. A Gstreamer pipeline continually overwrites a file "snapshot.jpeg" with a new frame grabbed from a webcam using video4linux2 with a framerate of 15 fps. A web page renders the image without caching every 100 ms. The problem is that I get ERR_CONTENT_LENGTH_MISMATCH (in browser console) for the image source on many frames. This is shown as a broken link in the browser. GStreamer 0.10 syntax gst-launch v4l2src ! video/x-raw

问题 I have installed Apache server on a Ubuntu machine, created directory in Apache /var/www/html/myvideos/ and copied the videos to this location, how do you play it back on the browser? I have opened the URL in browser http://my_server_ip/myvideos/testvideo.mp4 The video doesn't get played in the browser. Do I need to make any configuration in Apache server to make the video play in the browser ? Please guys, help me on this. Thanks 回答1: You should embed a link to the video in your index.html