variable-assignment

Copy constructor and = operator overload in C++: is a common function possible?

China☆狼群 提交于 2019-11-26 11:31:36
Since a copy constructor MyClass(const MyClass&); and an = operator overload MyClass& operator = (const MyClass&); have pretty much the same code, the same parameter, and only differ on the return, is it possible to have a common function for them both to use? CB Bailey Yes. There are two common options. One - which is generally discouraged - is to call the operator= from the copy constructor explicitly: MyClass(const MyClass& other) { operator=(other); } However, providing a good operator= is a challenge when it comes to dealing with the old state and issues arising from self assignment. Also

JavaScript OR (||) variable assignment explanation

匆匆过客 提交于 2019-11-26 11:25:34
Given this snippet of JavaScript... var a; var b = null; var c = undefined; var d = 4; var e = 'five'; var f = a || b || c || d || e; alert(f); // 4 Can someone please explain to me what this technique is called (my best guess is in the title of this question!)? And how/why it works exactly? My understanding is that variable f will be assigned the nearest value (from left to right) of the first variable that has a value that isn't either null or undefined, but I've not managed to find much reference material about this technique and have seen it used a lot. Also, is this technique specific to

What is the difference between slice assignment that slices the whole list and direct assignment?

做~自己de王妃 提交于 2019-11-26 11:23:49
I see at many places the use of slice assignment for list s. I am able to understand its use when used with (non-default) indices, but I am not able to understand its use like: a_list[:] = ['foo', 'bar'] How is that different from a_list = ['foo', 'bar'] ? a_list = ['foo', 'bar'] Creates a new list in memory and points the name a_list at it. It is irrelevant what a_list pointed at before. a_list[:] = ['foo', 'bar'] Calls the __setitem__ method of the a_list object with a slice as the index, and a new list created in memory as the value. __setitem__ evaluates the slice to figure out what

How does Python's comma operator works during assignment?

六月ゝ 毕业季﹏ 提交于 2019-11-26 11:12:14
问题 I was reading the assignment statements in the Python docs ( http://docs.python.org/reference/simple_stmts.html#assignment-statements ). In that it is quoted that: If the target is a target list enclosed in parentheses or in square brackets: The object must be an iterable with the same number of items as there are targets in the target list, and its items are assigned, from left to right, to the corresponding targets. After reading it, I thought of writing a sample like this: a = 5 b = 4 a, b

Why would you use an assignment in a condition?

狂风中的少年 提交于 2019-11-26 10:32:17
In many languages assignments are legal in conditions. I never understood the reason behind this. Why would you write: if (var1 = var2) { ... } instead of: var1 = var2; if (var1) { ... } It's more useful for loops than if statements. while( var = GetNext() ) { ...do something with var } Which would otherwise have to be written var = GetNext(); while( var ) { ...do something var = GetNext(); } I find it most useful in chains of actions which often involve error detection, etc. if ((rc = first_check(arg1, arg2)) != 0) { report error based on rc } else if ((rc = second_check(arg2, arg3)) != 0) {

Assign multiple new variables on LHS in a single line

半世苍凉 提交于 2019-11-26 10:22:20
I want to assign multiple variables in a single line in R. Is it possible to do something like this? values # initialize some vector of values (a, b) = values[c(2,4)] # assign a and b to values at 2 and 4 indices of 'values' Typically I want to assign about 5-6 variables in a single line, instead of having multiple lines. Is there an alternative? There is a great answer on the Struggling Through Problems Blog This is taken from there, with very minor modifications. USING THE FOLLOWING THREE FUNCTIONS (Plus one for allowing for lists of different sizes) # Generic form '%=%' = function(l, r, ...

Python Assignment Operator Precedence - (a, b) = a[b] = {}, 5

谁都会走 提交于 2019-11-26 09:50:43
问题 I saw this Python snippet on Twitter and was quite confused by the output: >>> a, b = a[b] = {}, 5 >>> a {5: ({...}, 5)} What is going on here? 回答1: From the Assignment statements documentation: An assignment statement evaluates the expression list (remember that this can be a single expression or a comma-separated list, the latter yielding a tuple) and assigns the single resulting object to each of the target lists, from left to right. You have two assignment target lists; a, b , and a[b] ,

R: += (plus equals) and ++ (plus plus) equivalent from c++/c#/java, etc.?

旧城冷巷雨未停 提交于 2019-11-26 09:29:02
问题 Does R have a concept of += (plus equals) or ++ (plus plus) as c++/c#/others do? 回答1: No, it doesn't, see: R Language Definition: Operators 回答2: Following @GregaKešpret you can make an infix operator: `%+=%` = function(e1,e2) eval.parent(substitute(e1 <- e1 + e2)) x = 1 x %+=% 2 ; x 回答3: R doesn't have a concept of increment operator (as for example ++ in C). However, it is not difficult to implement one yourself, for example: inc <- function(x) { eval.parent(substitute(x <- x + 1)) } In that

Why does this go into an infinite loop?

心不动则不痛 提交于 2019-11-26 09:14:16
I have the following code: public class Tests { public static void main(String[] args) throws Exception { int x = 0; while(x<3) { x = x++; System.out.println(x); } } } We know he should have writen just x++ or x=x+1 , but on x = x++ it should first attribute x to itself, and later increment it. Why does x continue with 0 as value? --update Here's the bytecode: public class Tests extends java.lang.Object{ public Tests(); Code: 0: aload_0 1: invokespecial #1; //Method java/lang/Object."<init>":()V 4: return public static void main(java.lang.String[]) throws java.lang.Exception; Code: 0: iconst_0

Why is assignment to &#39;this&#39; not allowed in java?

纵饮孤独 提交于 2019-11-26 09:10:03
问题 The error I get from the compiler is \"The left hand side of an assignment must be a variable\". My use case is deep copying, but is not really relevant. In C++, one can assign to *this . The question is not how to circumvent assignment to this . It\'s very simple, but rather what rationale is there behind the decision not to make this a variable. Are the reasons technical or conceptual? My guess so far - the possibility of rebuilding an Object in a random method is error-prone (conceptual),