use-strict

Is there a need for a “use strict” Python compiler?

自闭症网瘾萝莉.ら 提交于 2019-12-04 08:16:35
问题 There exist static analysis tools for Python, but compile time checks tend to be diametrically opposed to the run-time binding philosophy that Python embraces. It's possible to wrap the standard Python interpreter with a static analysis tool to enforce some "use strict"-like constraints, but we don't see any widespread adoption of such a thing. Is there something about Python that makes "use strict" behavior unnecessary or especially undesirable? Alternatively, is the "use strict" behavior

Javascript: besides “use strict”, which other “use” directives are there?

那年仲夏 提交于 2019-12-04 08:10:16
Besides use strict , which other use directives are there? GitaarLAB Some more examples that can be in the “directive prologue” (a section potentially usable by JavaScript engines): 'use strict'; 'use asm'; Mozilla's asm.js is a subset of the language, geared towards crunching numbers. 'use stricter'; Google's SoundScript. For fast OOP Has also some modes like: 'use stricter+types'; http://www.2ality.com/2015/02/soundscript.html 'use babel'; Used in Atom.io . (Was previously: 'use 6to5'; ) A tweet by Jeremy Ashkenas suggests some further use of + and - prefixes in the same 'use ...'; string (

Why does JSLint give strict violation error on this function?

余生颓废 提交于 2019-12-04 05:06:08
JSLint gives me the "strict violation" error, although I use the "this" context inside a function which hides it from the global scope. function test() { "use strict"; this.a = "b"; } For the record, I use the built-in JSLint parser in Webstorm. This is because JSLint doesn't recognize your function as a constructor. By convention, you must use uppercase letters. function Test() { "use strict"; this.a = "b"; } 来源: https://stackoverflow.com/questions/17770048/why-does-jslint-give-strict-violation-error-on-this-function

AngularJS controllers and “use strict”

别来无恙 提交于 2019-12-03 05:36:45
问题 I recently started using JSHint and it is requiring me to use the function form of "use strict". Since then, AngularJS throws an error: "Error: Argument 'webAddressController' is not a function, got undefined" When I remove the function form of "use strict" the controller loads fine. Controller: (function () { "use strict"; function webAddressController($scope, $rootScope, web_address_service) { // Do things } }()); Does anyone have any insight on what's going on here? 回答1: First off, I want

Is there a need for a “use strict” Python compiler?

女生的网名这么多〃 提交于 2019-12-02 23:33:46
There exist static analysis tools for Python , but compile time checks tend to be diametrically opposed to the run-time binding philosophy that Python embraces. It's possible to wrap the standard Python interpreter with a static analysis tool to enforce some " use strict "-like constraints, but we don't see any widespread adoption of such a thing. Is there something about Python that makes "use strict" behavior unnecessary or especially undesirable? Alternatively, is the "use strict" behavior unnecessary in Perl, despite its widespread adoption? Note: By "necessary" I mean "practically

AngularJS controllers and “use strict”

為{幸葍}努か 提交于 2019-12-02 18:56:39
I recently started using JSHint and it is requiring me to use the function form of "use strict". Since then, AngularJS throws an error: "Error: Argument 'webAddressController' is not a function, got undefined" When I remove the function form of "use strict" the controller loads fine. Controller: (function () { "use strict"; function webAddressController($scope, $rootScope, web_address_service) { // Do things } }()); Does anyone have any insight on what's going on here? Ben Lesh First off, I want to state the pkozlowski really knows his stuff at Angular, but this actually isn't as much of an

How to set 'use strict' globally with JSLint

谁说胖子不能爱 提交于 2019-12-01 03:31:48
I'm new to javascript and am trying to validate through JSLint. Where should I put "use strict" to use it globally and validate? This gives me error "Unexpected expression 'use strict' in statement position.": "use strict"; console.log('doing js in head-section'); function helloWorld() { console.log('called function helloWorld()'); alert('Hello World from a JS function showing an alert!'); } function helloMyNumber() { console.log('called function helloMyNumber()'); var max = 42; var yourLuckyNumber = prompt('Enter your lucky number (between 1 and '+ max +')'); var myLuckyNumber = Math.floor

“use strict”; + jQuery.getScript() = script can't export to global namespace

断了今生、忘了曾经 提交于 2019-11-30 15:15:35
Suppose I have the following script, called include_strict.js . After it executes I should have window.global1 defined: "use strict"; var globalVar = {}; alert(typeof window.globalVar); But if I include it from a block of javascript with $.getScript("include_strict.js"); The alert says undefined . Why? What is going on here? FYI, that's not what happens if I include the file using a script tag: <script type="text/javascript" src="include_strict.js"></script> Here, I see the expected alert, object . And if I remove "use strict"; , then both jQuery.getScript() and <script>; have the same effect

Is “use strict” Safe for Live Sites?

試著忘記壹切 提交于 2019-11-30 11:38:24
"use strict"; seems awesome, and we'd really like to use it at our shop. However, we just want it so that we (the developers) can find strictness-issues; we very much DO NOT want to make our site break for our actual customers when it was working fine before. Now, we could just use some server-side logic to achieve this: {% if debug %}<script>"use strict";</script>{% endif %} ... except that "use strict" operates on a file-by-file basis, so that won't actually work (well, unless we start server-side processing all of our JS files). So, my question is: do all the things "use strict" checks for

“use strict”; + jQuery.getScript() = script can't export to global namespace

喜夏-厌秋 提交于 2019-11-29 22:28:18
问题 Suppose I have the following script, called include_strict.js . After it executes I should have window.global1 defined: "use strict"; var globalVar = {}; alert(typeof window.globalVar); But if I include it from a block of javascript with $.getScript("include_strict.js"); The alert says undefined . Why? What is going on here? FYI, that's not what happens if I include the file using a script tag: <script type="text/javascript" src="include_strict.js"></script> Here, I see the expected alert,