urllib2

I am trying to make a request to an RSS feed that requires a cookie, using python. I thought using urllib2 and adding the appropriate heading would be sufficient, but the request keeps saying unautherized. Im guessing it could be a problem on the remote sites' side, but wasnt sure. How do I use urllib2 along with cookies? is there a better package for this (like httplib, mechanize, curl) import urllib2 opener = urllib2.build_opener() opener.addheaders.append(('Cookie', 'cookiename=cookievalue')) f = opener.open("http://example.com/") I would use requests package, docs , it's a lot easier to

I'm trying to make a program that will open a directory, then use regular expressions to get the names of powerpoints and then create files locally and copy their content. When I run this it appears to work, however when I actually try to open the files they keep saying the version is wrong. from urllib.request import urlopen import re urlpath = urlopen('http://www.divms.uiowa.edu/~jni/courses/ProgrammignInCobol/presentation/') string = urlpath.read().decode('utf-8') pattern = re.compile('ch[0-9]*.ppt') #the pattern actually creates duplicates in the list filelist = pattern.findall(string)

When I execute the below line, req = urllib2.Request(requestwithtoken) self.response = urllib2.urlopen(req,self.request).read() I am getting the following exception: SSLError: [SSL: SSLV3_ALERT_HANDSHAKE_FAILURE] sslv3 alert handshake failure (_ssl.c:590) The thing is I am able to get the token by pinging the service by using curl . During the process of retrieving the token, all the certificates were verified. In turn, by using the generated token, i am not able to connect to the service. I am getting the above error while trying. What could be the reason for that? martin I was having the

In python, I'm using httplib because it "keep-alive" the http connection (as oppose to urllib(2)). Now, I want to use cookielib with httplib but they seem to hate each other!! (no way to interface them together). Does anyone know of a solution to that problem? HTTP handler for urllib2 that supports keep-alive Serge Broslavsky You should consider using the Requests library instead at the earliest chance you have to refactor your code. In the mean time; HACK ALERT! :) I'd go other suggested way, but I've done a hack (done for different reasons though), which does create an interface between

Here is my server.py : import BaseHTTPServer import SocketServer class TestRequestHandler(BaseHTTPServer.BaseHTTPRequestHandler): def do_GET(self): self.wfile.write("hello world at %s" % __file__) server = BaseHTTPServer.HTTPServer(('', 10000), TestRequestHandler) #server = SocketServer.ThreadingTCPServer(('', 8888), TestRequestHandler) server.serve_forever() Here is my client.py : import urllib2 req = urllib2.Request('http://127.0.0.1:10000/') handle = urllib2.urlopen(req) content = handle.read() Then I start server.py, it works. When I start client.py, I get this error on Windows 7, Python 2

I was wondering how do you translate something like this using Python Requests? In urllib2, you can manually manipulate the data that is being sent over the wire to the API service, but Requests claims multipart file uploads are easy. However, when trying to send over the same request using the Requests library, I believe that it is not specifying some key parameters in the content-type for each of the two parts correctly. Can someone please shed some light on this matter. Thank you in advance! def upload_creative(self, account_id, file_path): """""" boundary = '-----------------------------'