url

change search item url and routing in codeigniter

自古美人都是妖i 提交于 2020-05-17 06:34:36
问题 I want to change the URL with Codeigniter routing: here is my url: home/search?location=BD home/search?location=BD&category[]=123 home/search?location=BD&category[]=123&category[]=124&category[]=125 like above url but I want to routing this url with home/BD home/BD/123 home/BD/123+124+125 or home/BD/123/124/125 My route.php : $route['home/(:any)/(:any)'] = 'home/search/$1'; What is my problem in route.php page? 回答1: Try to use a (.+) pattern on your route.php , the $1 will contain the

UIWebView get current URL of SPA (single page application) website

白昼怎懂夜的黑 提交于 2020-05-17 06:06:21
问题 I want to get my UIWebView 's current location when browsing an SPA (single-page-application) website. (Yes, I am intentionally working with UIWebView instead of WKWebView .) I know that there are multiple approaches to getting the current URL, such as: webView.request?.url?.absoluteString webView.request?.mainDocumentURL?.absoluteString webView.stringByEvaluatingJavaScript(from: "window.location") However, for an SPA website, for each of the approaches above, I am getting the initial url,

getting 404 in GET request in Go

雨燕双飞 提交于 2020-05-17 05:56:31
问题 When I use http://localhost:8080/login?id=ddfd@vcv.com&pwd=dccccf in postman or use it in android app I am getting 404 . On curl I get {"name":"Miss Moneypenny","email":"ddfd@vcv.com","password":"dccccf","mobile":27,"address":"dscsdacc"} I am not able to understand what can I do to achieve json output in postman and on other platforms like Apps in ios as well as android when I use this api and also on the browser window. My Main.go code func getSession() *mgo.Session { s, err := mgo.Dial(

How to not change the url on list filtering with react-admin?

邮差的信 提交于 2020-05-16 04:08:34
问题 Assume I have a route /customers where a List of customers is being rendered. On that same route there's also a side drawer present. That drawer contains a List with a Filter of help topics . When I start typing in the Filter in the side drawer, the url changes. That's according to how react-admin's list filter is working. The problem is that the customers list is noticing the route changes. In effect it starts querying and reloading customers based on a search term that is related to help

How to parse URL # fragments with query items in Swift

人走茶凉 提交于 2020-05-16 03:07:45
问题 Query parameters sometimes get passed as URL fragments instead of query parameters - e.g. during OAuth flows to provide client-only access to parameters. What's the simplest way to parse a URL like: https://example.com/auth-callback#access_token=mytoken&expires_in=36000&scope=zap+profile into key values for: access_token, expires_in, scope 回答1: Simply pass the fragment property as a query string to a new URLComponent and read the parsed query objects: let url = URL(string: "https://example

How to parse URL # fragments with query items in Swift

谁说我不能喝 提交于 2020-05-16 03:07:35
问题 Query parameters sometimes get passed as URL fragments instead of query parameters - e.g. during OAuth flows to provide client-only access to parameters. What's the simplest way to parse a URL like: https://example.com/auth-callback#access_token=mytoken&expires_in=36000&scope=zap+profile into key values for: access_token, expires_in, scope 回答1: Simply pass the fragment property as a query string to a new URLComponent and read the parsed query objects: let url = URL(string: "https://example

Downloading a csv.gz file from url in Python

你说的曾经没有我的故事 提交于 2020-05-13 14:02:11
问题 I'm having trouble downloading a csv.gz file from a url I have no problem downloading a tar.gz file. For the csv.gz file I'm able to extract the .gz file and read my csv file it would just be handy if I could use an URL instead of having the csv-1.0.csv.gz before hand This works: import urllib.request urllib.request.urlretrieve('http://www.mywebsite.com/csv-1-0.tar.gz','csv-1-0.tar.gz') This does not work: import urllib.request urllib.request.urlretrieve('http://www.mywebsite.com/csv-1-0.csv

Get a shareable link of a file in our google drive using Colab notebook

浪子不回头ぞ 提交于 2020-05-12 08:22:20
问题 could anyone please inform me how to automatically get a shareable link of a file in our google drive using Colab notebook? Thank you. 回答1: You can use xattr to get file_id from subprocess import getoutput from IPython.display import HTML from google.colab import drive drive.mount('/content/drive') # access drive # need to install xattr !apt-get install xattr > /dev/null # get the id fid = getoutput("xattr -p 'user.drive.id' '/content/drive/My Drive/Colab Notebooks/R.ipynb' ") # make a link

how to chage url without redirect in javascript?

巧了我就是萌 提交于 2020-05-10 06:35:06
问题 I am trying to add country name for every link in page my website. It is redirecting two times. How can I change URL without redirecting? $(document).on('click',function(e){ var querystring = '?country=' + countrySelected; if(e.nodeName === "A"){ window.location = window.location.href +querystring; } }); 回答1: Use the hash tag - # var querystring = '#country=' + countrySelected; It's used heavily in single page applications, because it doesn't redirect. 回答2: Navigate to fragment To properly

how to chage url without redirect in javascript?

别等时光非礼了梦想. 提交于 2020-05-10 06:32:07
问题 I am trying to add country name for every link in page my website. It is redirecting two times. How can I change URL without redirecting? $(document).on('click',function(e){ var querystring = '?country=' + countrySelected; if(e.nodeName === "A"){ window.location = window.location.href +querystring; } }); 回答1: Use the hash tag - # var querystring = '#country=' + countrySelected; It's used heavily in single page applications, because it doesn't redirect. 回答2: Navigate to fragment To properly