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问题 I made a simple sheet based database for chemicals using google sheets. The sheet looks like this: https://docs.google.com/spreadsheets/d/e/2PACX-1vR0-AMEKNM3ZbDq67OIKWnc7E3KP8kfOsnr0Bjg2OSjpevLLjniknGXfIiiyZvbwE9bz3EfbOpO46ef/pubhtml?gid=292509613&single=true There are many rows and columns. A user can change a value of a cell using a url link something like this https://docs.google.com/spreadsheets/d/13sLioJr_T6lqQ7y_pStBR8CKxReYwLUn4hao/edit#gid=292509613&range=B2 the link is converted to

问题 I made a simple sheet based database for chemicals using google sheets. The sheet looks like this: https://docs.google.com/spreadsheets/d/e/2PACX-1vR0-AMEKNM3ZbDq67OIKWnc7E3KP8kfOsnr0Bjg2OSjpevLLjniknGXfIiiyZvbwE9bz3EfbOpO46ef/pubhtml?gid=292509613&single=true There are many rows and columns. A user can change a value of a cell using a url link something like this https://docs.google.com/spreadsheets/d/13sLioJr_T6lqQ7y_pStBR8CKxReYwLUn4hao/edit#gid=292509613&range=B2 the link is converted to

问题 I'm using python.On my page when an anonymous user goes to the sign in page, I want to pass a variable to the backend so it indicates where the user is coming from ( send the URL). So when the user clicks on this anchor link: <a href="{{ url_for('account.signin') }}">Sign in</a> I want to send current URL of the page where the user is currently. <script> var current_url = window.location.href; <script> I thought to send it like this: <a href="{{ url_for('account.signin', current_url="window

问题 I'm using python.On my page when an anonymous user goes to the sign in page, I want to pass a variable to the backend so it indicates where the user is coming from ( send the URL). So when the user clicks on this anchor link: <a href="{{ url_for('account.signin') }}">Sign in</a> I want to send current URL of the page where the user is currently. <script> var current_url = window.location.href; <script> I thought to send it like this: <a href="{{ url_for('account.signin', current_url="window

问题 I am trying to interact with the SWAPI API. I want a view that fetches all the movies( films/ ) and one that fetches one ( film/id ). When I hit http://127.0.0.1:8000/api/films/?id=4 it enters the get_films function. I am using Django==1.11 and Django Rest Framework==3.9.0 . my urs.py: urlpatterns = [ url(r'films/',views.get_films,name="get-films"), url(r'films/(?P<id>[0-9])/',views.get_film,name="get-film"), ] my views.py: MAX_RETRIES = 5 API_URL= "https://swapi.co/api/" @api_view(['GET',

问题 I am making a website. I want to check from the server whether the link that the user submitted is actually an image that exists. 回答1: This is one way that is quick: It doesn't really verify that is really an image file, it just guesses based on file extention and then checks that the url exists. If you really need to verify that the data returned from the url is actually an image (for security reasons) then this solution would not work. import mimetypes, urllib2 def is_url_image(url):

问题 I am making a website. I want to check from the server whether the link that the user submitted is actually an image that exists. 回答1: This is one way that is quick: It doesn't really verify that is really an image file, it just guesses based on file extention and then checks that the url exists. If you really need to verify that the data returned from the url is actually an image (for security reasons) then this solution would not work. import mimetypes, urllib2 def is_url_image(url):

问题 Here's a brief overview of the process that I need help with: Client uploads images to Firebase Storage at users/displayName/uid/ - this step is clear and done. No help needed on this one. Then, client presses "request a quote" button which saves the URLs of the images (the ones that were uploaded to Storage in step 1) to Firebase Firestore - this step is clear and done. No help needed on this one. After the URLs are saved to the Firestore, I want those images from Step 1 to be moved within

问题 Using a Postgresql URL connection string in the format of: postgresql://user:secret@localhost How do I handle special characters in that string (e.g., $ ) so that it will actually function when I connect to my postgres database? I've tried simply URL encoding it, so for example, "test$" becomes "test%24" ... but that seems to be a problem as I get a "FATAL: password authentication failed " error when attempting to use it. 回答1: See Connection URIs in the doc. There are a few things that don't

问题 Using a Postgresql URL connection string in the format of: postgresql://user:secret@localhost How do I handle special characters in that string (e.g., $ ) so that it will actually function when I connect to my postgres database? I've tried simply URL encoding it, so for example, "test$" becomes "test%24" ... but that seems to be a problem as I get a "FATAL: password authentication failed " error when attempting to use it. 回答1: See Connection URIs in the doc. There are a few things that don't