url-pattern

问题 I'm using wiremock to mock certain requests and their respective response, but I'm trying to add a regex. Unfortunately, this just throws an exception stating that the request was not matched. { "request" : { "method": "GET", "urlPattern": "/my/service/url?^.*(specificParam.*(M[0-9]{9})).*$" }, "response": { ... } } I also tried it with "urlPattern": "/my/service/url\\?^.*(specificParam.*(M[0-9]{9})).*$" The request I'm sending is /my/service/url?saml2=disabled&filter=specificParam%20eq%20

问题 I feel like this is a common problem but nothing I've researched has worked yet... In my web.xml I have a mapping for all REST calls - <servlet-mapping> <servlet-name>springmvc</servlet-name> <url-pattern>/rest/*</url-pattern> </servlet-mapping> This works well if the URL is - GET /rest/people but fails if it is GET /rest/people/1 I get a 400 Bad Request error saying The request sent by the client was syntactically incorrect () . I'm not sure it even made it to the Spring servlet to get

问题 I know I cannot use regular expressions for the url-pattern of a filter-mapping, but I wanted to know if it is possible somehow to map the filter using something like /foo/.+/* 回答1: No. As to wildcard matching, the <url-pattern> only supports prefix ( /folder/* ) or suffix ( *.extension ) matching. If you want more finer grained matching like as possible with Apache HTTPD's mod_rewrite , then use Tuckey's UrlRewriteFilter or OCPSoft Rewrite instead. They support mod_rewrite -like expressions

问题 I am trying to map a servlet pattern that matches both /server/abcDef/1432124/adfadfasdfa and /server/abcDef/abcd/12345 The values '1432124' and 'abcd' are not fixed and could be a multitude of values. So essentially I need to match against /abcDef/*/* -- only the abcDef is fixed. Is there a way for me to map this? Really I am looking for something like the following: <servlet-mapping> <servlet-name>abcDefServlet</servlet-name> <url-pattern>/server/abcDef/*/*</url-pattern> </servlet-mapping>

问题 This question already has answers here : java.lang.IllegalArgumentException: Invalid <url-pattern> in servlet mapping (2 answers) Closed 3 years ago . I am trying to deploy a very simple & my first JSF application (following a really good tutorial by BalusC) on glassfish local server. I completed all the steps to create the application. And when I tried to deploy the application on the glassfish server, it just failed with the following exception message:- cannot Deploy Playground Deployment

问题 This post is a follow-up of this previous question: Django request.POST empty I had a project up and running with Python 3.5.4 and Django 1.11.13 , on Visual Studio 2015. I later updated to Django 2.1.2 because I wanted to import the "path" module, so that I can use this: urlpatterns = [ path ( '', c_views.Indice, name = 'indice' ), path ( '<int:CompiladoID>', c_views.Detalle, name = 'detalle'), path ( 'elementos/<int:CompiladoID>', c_views.Elementos, name = 'elementos'), path (

问题 Useing Spring for Security, I can get the program running using the following code. <intercept-url pattern="/web/admin**/**" access="ROLE_ADMIN" requires-channel="https"/> <intercept-url pattern="/web/**/" access="ROLE_USER,ROLE_ADMIN" requires-channel="https"/> I am trying to do this within a web.xml currently. Using JBOSS to deploy a .war file. Below is what I have, The url-pattern is what is causing me the problems in the first security-constraint. The pages are located at, and named /web

问题 When I use http.HandleFunc("/", serveRest) //serveRest is the method to handle request http.ListenAndServe("localhost:4000", nil) It will accept all request starting with "/" . How do I restrict it to serve only "localhost:4000" instead of every address like "localhost:4000/*" ? And can you guys suggest me a good tutorial for Go? 回答1: The URL pattern to which you register your handlers is documented in the http.ServeMux type: Patterns name fixed, rooted paths, like "/favicon.ico", or rooted

问题 I'm following a tutorial where my urlpatterns are: urlpatterns = patterns('', url(r'^passwords/$', PasswordListView.as_view(), name='passwords_api_root'), url(r'^passwords/(?P<id>[0-9]+)$', PasswordInstanceView.as_view(), name='passwords_api_instance'), ...other urls here..., ) The PasswordListView and PasswordInstanceView are supposed to be class based views. I could not figure out the meaning of the name parameter. Is it a default parameter passed to the view? 回答1: No. It is just that

问题 Having an @WebServlet(urlPatterns = "/myServlet/") . If the user goes to myapp/myServlet/other , I still want my servlet to catch. So to say, wildcard anything on after the servlet path. How could I do this? 回答1: You can use * as prefix or suffix wildcard. In your case, you can use /myServlet/* for a folder mapping. @WebServlet("/myServlet/*") The path info (the part after the mapping in the URL) is in the servlet by the way available as: String pathInfo = request.getPathInfo(); This would in