upload

问题 I have a form in which I am uploading pictures. I don't know how many pictures I may upload at a specific time. Are there any jQuery/AJAX solutions for dynamically adding a file upload field in a form? 回答1: simple code for adding a file field in form using jQuery <form id="myForm" action="your-action"> <input type="file" name="files[]" /> <a href="#" onclick="addMoreFiles()">Add More</a> </form> <script> function addMoreFiles(){ $("#myForm").append('<input type="file" name="files[]" />') } <

问题 I want to implement a simple file upload in my intranet-page, with the smallest setup possible. This is my HTML part: <input id="sortpicture" type="file" name="sortpic" /> <button id="upload">Upload</button> and this is my JS jquery script: $("#upload").on("click", function() { var file_data = $("#sortpicture").prop("files")[0]; var form_data = new FormData(); form_data.append("file", file_data); alert(form_data); $.ajax({ url: "/uploads", dataType: 'script', cache: false, contentType: false,

问题 We have an application done with struts2. We limited the uploaded files to microsoft documents and acrobat pdf. All go fine. But when a user change the extension of the file, struts 2 is unable to detect that change and accept the file. For example logo.png -> logo.pdf Our configuration in the struts2 file is like this: <interceptor-ref name="interceptorFileStack"> <param name="fileUpload.allowedTypes">application/pdf,application/msword,application/vnd.openxmlformats-officedocument

问题 I am so confused with this, I am trying to upload data to FTP through VBS script and it works fine for a single file file but doesn't upload multiple files when I add the script inside a loop. Also , why do we need to generate a temporary file when remote uploading to FTP, I mean to say this, this is the script I am using, Dim fso, folder, files, strPath Set fso = CreateObject("Scripting.FileSystemObject") strPath = "E:/Test" Set folder = fso.GetFolder(strPath) Set files = folder.Files Const

问题 Hi thx to tutorials and own hinking I wrote this code if(isset($_POST['upload'])) { $allowed_filetypes = array('.jpg','.jpeg','.png','.gif'); $max_filesize = 10485760; $upload_path = 'uploads/'; $description = $_POST['imgdesc']; $filename = $_FILES['userfile']['name']; $ext = substr($filename, strpos($filename,'.'), strlen($filename)-1); if(!in_array($ext,$allowed_filetypes)) die('The file you attempted to upload is not allowed.'); if(filesize($_FILES['userfile']['tmp_name']) > $max_filesize)

问题 I am trying to upload a youtube video using the GData gem (I have seen the youtube_g gem but would like to make it work with pure GData if possible), but I keep getting this error: GData::Client::BadRequestError in 'MyProject::Google::YouTube should upload the actual video to youtube (once it does, mock this test out)' request error 400: No file found in upload request. I am using this code: def metadata data = <<-EOF <?xml version="1.0"?> <entry xmlns="http://www.w3.org/2005/Atom" xmlns

问题 I have a front-end web server written in Twisted Web, that interfaces with another web server. Clients upload files to my front-end server, which then sends the files along to the back-end server. I'd like to receive the uploaded file, and then send an immediate response to the client before sending the file on to the back-end server. That way the client doesn't have to wait for both uploads to occur before getting a response. I'm trying to do this by starting the upload to the back-end

问题 my aim is to save uploaded image and set width+height to it. With the code below I can save the image, but cannot set width + height... Please have a look at the code between // and // to spot the mistakes. Thanks a lot. $format = $_FILES["picture"]["type"]; $filename = $_FILES["picture"]["tmp_name"]; $destination = "upload/" .time(). $_FILES["picture"]["name"]; //////////////////////////////////////////// $_destination = width [400]; $_destination = height [460]; // this doesn't work...

问题 I am new one of using Grand central dispatch. I read the Apple documents about using GCD but still I have no idea about use this method. My thought is I have three type of upload buttons in my view and I clicked the button simultaneously I want to upload the data based on button action using NSURLCOnnection upload the content of data dispatch queue method.How can i do this. Pls help me 回答1: Try reading Mike Ash's blog on grand central dispatch - it will give you a good idea of how to use its

问题 I'm uploading files and storing metadata in a db. Part of the metadata is the file name itself. However, somewhere down the line, the filename seems to not be getting saved! I will paste only what I think are relevant parts of the code to keep this short. class UploadFile(models.Model): ... theFile = models.FileField(upload_to = "Genius/Uploads/", null = True) filename = models.CharField(max_length = 50, blank = True, null = False) class UploadFileForm(ModelForm): class Meta: model =