unset

Antcontrib <for> and <var unset=“true”> in ant?

由 二次信任 提交于 2019-12-08 06:40:31
问题 What versions of Antcontrib support <for> and also <var unset="true" /> in Antcontrib? (Or where can I go to find out that information?) 回答1: The task docs are here, but they don't say which versions of the library support which functions. However, there haven't been any new releases for years, so I suspect you already have the latest. Note that there is no <var unset="true"/> , it's <Variable unset="true"/> . Maybe that's your problem. 回答2: Version 1.0b2 has the for task, but you have to go

Rearrange array index Eloquent Laravel

由 瘦欲@ 提交于 2019-12-07 12:19:42
问题 I have an error after delete an element from an array of laravel eloquent A property has rooms foreach ($property->rooms as $key => $room) { if ($room->type == 1 and $type ==1 and $room->price < $price->min or $room->price > $price->max) { print_r($property->rooms); unset($property->rooms[$key]); //$array = array_values($property->rooms); doesn't work print_r($property->rooms); } } When i encode this into a json, the array is convert into an object not an array Before unset Illuminate

Overwrite array in JavaScript

由 我只是一个虾纸丫 提交于 2019-12-06 07:03:28
问题 How do I overwrite (or unset and then set) an array? Seems like "array = new_array" doesn't work. 回答1: To create an empty array to assign to the variable, you can use the Array constructor: array = new Array(); Or you can use an empty array literal: array = []; If you have several references to one array so that you have to empty the actual array object rather than replacing the reference to it, you can do like this: array.splice(0, array.length); 回答2: This should work. array1 = array2; If

Remove element from bash array by content (stored in variable) without leaving a blank slot [duplicate]

由 て烟熏妆下的殇ゞ 提交于 2019-12-06 01:16:26
问题 This question already has answers here : Remove an element from a Bash array (19 answers) Closed 3 years ago . I have an array list in a bash script, and a variable var . I know that $var appears in ${list[@]} , but have no easy way of determining its index. I'd like to remove it from list . This answer achieves something very close to what I need, except that list retains an empty element where $var once was. Note, e.g.: $ list=(one two three) $ var="two" $ list=( "${list[@]/$var}" ) $ echo

PHP | Remove element from array with reordering?

由 徘徊边缘 提交于 2019-12-05 19:04:20
问题 How can I remove an element of an array, and reorder afterwards, without having an empty element in the array? <?php $c = array( 0=>12,1=>32 ); unset($c[0]); // will distort the array. ?> Answer / Solution: array array_values ( array $input ). <?php $c = array( 0=>12,1=>32 ); unset($c[0]); print_r(array_values($c)); // will print: the array cleared ?> 回答1: array_values($c) will return a new array with just the values, indexed linearly. 回答2: If you are always removing the first element, then

Rearrange array index Eloquent Laravel

由 雨燕双飞 提交于 2019-12-05 18:56:17
I have an error after delete an element from an array of laravel eloquent A property has rooms foreach ($property->rooms as $key => $room) { if ($room->type == 1 and $type ==1 and $room->price < $price->min or $room->price > $price->max) { print_r($property->rooms); unset($property->rooms[$key]); //$array = array_values($property->rooms); doesn't work print_r($property->rooms); } } When i encode this into a json, the array is convert into an object not an array Before unset Illuminate\Database\Eloquent\Collection Object ( [items:protected] => Array ( [0] => Room Object ( [table:protected] =>

PHP Object new method for Class, Memory Leak and Unset Method

由 旧城冷巷雨未停 提交于 2019-12-04 23:27:21
I have Created following class in flie index.class.php :- <?php class index{ public function loadTitle() { $title = "Welcome to My Website"; return $title; } } ?> and now, I am using it like below in my index.php file <?php require_once("index.class.php"); $obj = new index(); echo $obj->loadTitle(); ?> , now my question is Page will become heavy with lots of article and images, and i will expect 1500-2500 user every day in it. Do, i need to also unset memory, i know PHP has its own garbage collector, but following URL scares me out :- www.google.com/search?q=php+memory+leak+with+new and i saw

How to delete an exact element in a bash array?

由 China☆狼群 提交于 2019-12-04 11:56:23
问题 I am trying to remove just the first appearance of any one keyword from a bash array. ARRAY=(foo bar and any number of keywords) keywords=(red, rednet, rd3.0) I remove the keyword like this: ARRAY=( ${ARRAY[@]/"$keyword"/} ) then if "red' is the first found keyword, it will strip ' red ' from both keywords and return "foo bar net" instead of "foo bar rednet". Edit: Here is example, hopefully this makes it clearer. for keyword in ${ARRAY[@]}; do if [ "$keyword" = "red" ] || [ "$keyword" = "rd3

When I use error? and try, err need a value

由 守給你的承諾、 提交于 2019-12-04 09:38:18
Here my function that execute cmd as a Rebol instructions : exec-cmd: func [ cmd [ block! ] "Rebol instructions" /local err ] [ if error? err: try [ do cmd ] [ print mold disarm err ] ] When I launch the function, I've encountered the following error message : ** Script Error: err needs a value ** Where: exec-cmd ** Near: if error? err: try [ do cmd ] How can I avoid this message and manage the error ? When the Rebol default evaluator sees a sequence of a SET-WORD! followed by a "complete" expression, it will assign the result of that expression to the named word. However, Rebol has the

Remove element from bash array by content (stored in variable) without leaving a blank slot [duplicate]

由 本秂侑毒 提交于 2019-12-04 05:20:27
This question already has answers here : Closed 3 years ago . Remove an element from a Bash array (18 answers) I have an array list in a bash script, and a variable var . I know that $var appears in ${list[@]} , but have no easy way of determining its index. I'd like to remove it from list . This answer achieves something very close to what I need, except that list retains an empty element where $var once was. Note, e.g.: $ list=(one two three) $ var="two" $ list=( "${list[@]/$var}" ) $ echo ${list[@]} one three $ echo ${#list[@]} 3 The same thing happens if I use delete=( "$var" ) and replace
订阅 unset