unreachable-code

C# Unreachable code detected

北城余情 提交于 2019-12-05 17:41:18
问题 I'm getting a "Unreachable code detected" message in Visual Studio at the point i++ in my code below. Can you spot what I've done wrong? try { RegistryKey OurKey = Registry.CurrentUser; OurKey.CreateSubKey("Software\\Resources\\Shared"); OurKey = OurKey.OpenSubKey("Software\\Resources\\Shared", true); for (int i = 0; i < cmbPaths.Items.Count; i++) //<---- problem with i { OurKey.SetValue("paths" + i, cmbPaths.Items[i]); break; } } 回答1: The problem is that this actually isn't a loop. You don't

Why unreachable code isn't an error in C++?

筅森魡賤 提交于 2019-12-04 14:48:45
unreachable code is compile time error in languages like Java. But why it is just warning in C++ & C? Consider following example: #include <iostream> int f() { int a=3; return a; int b=6; // oops it is unreachable code std::cout<<b; // program control never goes here } int main() { std::cout<<f()<<'\n'; } Shouldn't compiler throw an error in this program, because statements after return statements in function f() will never get executed? What is the reason for allowing unreachable code? bytecode77 Unreachable code is not a compile error in C++, but usually gives a warning, depending on your

C# Unreachable code detected

安稳与你 提交于 2019-12-04 02:10:20
I'm getting a "Unreachable code detected" message in Visual Studio at the point i++ in my code below. Can you spot what I've done wrong? try { RegistryKey OurKey = Registry.CurrentUser; OurKey.CreateSubKey("Software\\Resources\\Shared"); OurKey = OurKey.OpenSubKey("Software\\Resources\\Shared", true); for (int i = 0; i < cmbPaths.Items.Count; i++) //<---- problem with i { OurKey.SetValue("paths" + i, cmbPaths.Items[i]); break; } } The problem is that this actually isn't a loop. You don't have any condition on the break so you could equivalently write something like if(cmbPath.Items.Count > 0)

Emulating GCC's __builtin_unreachable?

為{幸葍}努か 提交于 2019-12-03 08:27:58
问题 I get a whole lot of warnings about switches that only partially covers the range of an enumeration switched over. Therefor, I would like to have a "default" for all those switches and put __builtin_unreachable (GCC builtin) in that case, so that the compiler know that case is not reachable. However, I came to know that GCC4.3 does not support that builtin yet. Is there any good way to emulate that functionality? I thought about dereferencing a null pointer instead, but that may have other

Emulating GCC's __builtin_unreachable?

旧巷老猫 提交于 2019-12-02 22:11:55
I get a whole lot of warnings about switches that only partially covers the range of an enumeration switched over. Therefor, I would like to have a "default" for all those switches and put __builtin_unreachable (GCC builtin) in that case, so that the compiler know that case is not reachable. However, I came to know that GCC4.3 does not support that builtin yet. Is there any good way to emulate that functionality? I thought about dereferencing a null pointer instead, but that may have other undesirable effects/warnings and such. Do you have any better idea? You can call an inline function

When does the condition “Unreachable Code” occur in Java?

雨燕双飞 提交于 2019-12-01 17:47:53
问题 When there is some statement written after the infinite loop, that statement becomes the unreachable code. For ex: for(;;) { } Sytem.out.println("Test-1"); //unreachable code But I am facing some difficulty here. Look at the two code snippets below: Code snippet1: for(final int z=4;z<6;) { } System.out.println("Test-2"); //unreachable code Here, The last statement must be unreachable because the loop is infinite and the output is as expected. Code Snippet2: final int z=4; for(;;) { if(z<2)

Java: How to @SuppressWarnings unreachable code?

ぐ巨炮叔叔 提交于 2019-12-01 16:03:36
Sometimes when you are debugging, you have unreachable code fragment. Is there anyway to suppress the warning? The only way to do this on any compiler is @SuppressWarnings("all") . If you're using Eclipse, try @SuppressWarnings("unused") . Java has (primitive) support for debugging like this in that simple if on boolean constants will not generate such warnings (and, indeed when the evaluation is false the compiler will remove the entire conditioned block). So you can do: if(false) { // code you don't want to run } Likewise, if you are temporarily inserting an early termination for debugging,

Why java does not detect unreachable catch block if I use multiple catch blocks?

杀马特。学长 韩版系。学妹 提交于 2019-11-30 14:04:55
问题 Research following method: static private void foo() { try { throw new FileNotFoundException(); } catch (FileNotFoundException e) { e.printStackTrace(); } catch (IOException e) { e.printStackTrace(); } } This code compiles good despite last catch block actually unreachable. Now lets comment throw new FileNotFoundException(); row execute: OOOPs! we see Unreachable catch block for FileNotFoundException. This exception is never thrown from the try statement body Strange. Why does java use double

Why is an if/else if/else for a simple boolean not giving an “unreachable code” error

别等时光非礼了梦想. 提交于 2019-11-29 10:31:37
问题 Why is this code not giving an "unreachable code" error? Since a boolean can only be true or false. public static void main(String args[]) { boolean a = false; if (a == true) { } else if (a == false) { } else { int c = 0; c = c + 1; } } 回答1: From JLS 14.21. Unreachable Statements It is a compile-time error if a statement cannot be executed because it is unreachable. and The else-statement is reachable iff the if-then-else statement is reachable. Your if-then-else statement is reachable. So,

Why does a Java Compiler not produce an unreachable statement error for an unreachable then statement?

梦想与她 提交于 2019-11-29 04:22:57
问题 If I try to compile for(;;) { } System.out.println("End"); The Java compiler produces an error saying Unreachable statement . But if I add another " unreachable "(according to me) break statement and make it: for(;;) { if(false) break; } System.out.println("End"); It compiles. Why does it not produce an error? 回答1: The behaviour is defined in the JLS description of unreachable statements: The then-statement is reachable iff the if-then statement is reachable. So the compiler determines that