ulong

How to get amount of 1s from 64 bit number [duplicate]

由 断了今生、忘了曾经 提交于 2019-12-11 14:08:51
问题 This question already has answers here : Count number of bits in a 64-bit (long, big) integer? (3 answers) Closed 6 years ago . Possible duplicate: Count number of bits in a 64-bit (long, big) integer? For an image comparison algorithm I get a 64bit number as result. The amount of 1s in the number (ulong) (101011011100...) tells me how similar two images are, so I need to count them. How would I best do this in C#? I'd like to use this in a WinRT & Windows Phone App, so I'm also looking for a

Converting raw-byte values into Java types

由 隐身守侯 提交于 2019-12-11 03:39:57
问题 I have a problem with converting raw-bytes values into java types. I am receiving bytes by a datagram socket as a bytes array. I know exactly which bytes means what, but I don't know how to convert them appropriately (I mean I know offsets, but don't know if what I think I received is correct ;)). For example, I want to convert 16 bit unsigned short into java int type. I found some examples in the web, the one is: public int getUShort(byte[] bytes, int offset) { int b0 = bytes[offset] & oxFF;

C#: How to convert long to ulong

由 安稳与你 提交于 2019-12-05 18:14:49
问题 If i try with BitConverter,it requires a byte array and i don't have that.I have a Int32 and i want to convert it to UInt32. In C++ there was no problem with that. 回答1: A simple cast is all you need. Since it's possible to lose precision doing this, the conversion is explicit. long x = 10; ulong y = (ulong)x; 回答2: Try: Convert.ToUInt32() 回答3: Int32 i = 17; UInt32 j = (UInt32)i; EDIT: question is unclear whether you have a long or an int? 回答4: Given this function: string test(long vLong) {

C#: How to convert long to ulong

由 六月ゝ 毕业季﹏ 提交于 2019-12-04 02:21:54
If i try with BitConverter,it requires a byte array and i don't have that.I have a Int32 and i want to convert it to UInt32. In C++ there was no problem with that. A simple cast is all you need. Since it's possible to lose precision doing this, the conversion is explicit. long x = 10; ulong y = (ulong)x; Try: Convert.ToUInt32() Int32 i = 17; UInt32 j = (UInt32)i; EDIT: question is unclear whether you have a long or an int? Given this function: string test(long vLong) { ulong vULong = (ulong)vLong; return string.Format("long hex: {0:X}, ulong hex: {1:X}", vLong, vULong); } And this usage:

I'm using ulong for the factorial of 100, but it still overflows

由 三世轮回 提交于 2019-11-28 14:50:05
So my task is: I have the number 100, and I have to print the sum of the digits of it's factorial. So I wrote the code, found a nice way of summing the digits but my code doesn't work for the number 100. I checked for 10, and it works perfectly. First step that came to my mind, I have to change the type from int to something bigger. I know the result (of the factorial) will be a huge positive number so I choose ulong, but it still doesn't work. I checked around here on Stack Overflow, and the only answers I found suggested using 'BigInteger' but my Visual Studio doesn't seem to know it, and I

I'm using ulong for the factorial of 100, but it still overflows

由 天大地大妈咪最大 提交于 2019-11-27 08:52:35
问题 So my task is: I have the number 100, and I have to print the sum of the digits of it's factorial. So I wrote the code, found a nice way of summing the digits but my code doesn't work for the number 100. I checked for 10, and it works perfectly. First step that came to my mind, I have to change the type from int to something bigger. I know the result (of the factorial) will be a huge positive number so I choose ulong, but it still doesn't work. I checked around here on Stack Overflow, and the
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