treemap

BeginnersBook Java 集合教程

我是研究僧i 提交于 2019-11-27 17:20:39
来源: ApacheCN BeginnersBook 翻译项目 译者: 飞龙 协议: CC BY-NC-SA 4.0 贡献指南 本项目需要校对,欢迎大家提交 Pull Request。 请您勇敢地去翻译和改进翻译。虽然我们追求卓越,但我们并不要求您做到十全十美,因此请不要担心因为翻译上犯错——在大部分情况下,我们的服务器已经记录所有的翻译,因此您不必担心会因为您的失误遭到无法挽回的破坏。(改编自维基百科) 目录 Java 集合 - List ArrayList ArrayList 基础知识 java 中的 ArrayList - 集合框架 如何初始化 ArrayList 如何在 Java 中遍历 ArrayList 如何在 Java 中查找 ArrayList 的长度 ArrayList 排序 如何在 Java 中对 ArrayList 进行排序 如何在 Java 中按降序对 ArrayList 进行排序 Java ArrayList 对象排序( Comparable 和 Comparator ) ArrayList 添加/删除 Java ArrayList add() 方法 Java ArrayList add(int index, E element) Java ArrayList addAll(Collection c) 方法 如何在 Java 中将所有 List

How to Print treemap in reverse order

 ̄綄美尐妖づ 提交于 2019-11-27 14:42:14
问题 In my assignment we are read from a file the text: To be, or not to be: that is the question: Whether 'tis nobler in the mind to suffer then count the times each has occured. I've been able to print this map unsorted, then I was able to make a TreeMap and print it in natural order (which is shown below). I don't know how to print in reverse order. I know a way to use a comparator, but I'm a little rusty so I've done what I can. Furthermore, I don't know how to set the comparator up to sort

Which data structure would you use: TreeMap or HashMap? (Java) [duplicate]

瘦欲@ 提交于 2019-11-27 09:13:52
问题 This question already has an answer here: Difference between HashMap, LinkedHashMap and TreeMap 16 answers Description | A Java program to read a text file and print each of the unique words in alphabetical order together with the number of times the word occurs in the text. The program should declare a variable of type Map<String, Integer> to store the words and corresponding frequency of occurrence. Which concrete type, though? TreeMap<String, Number> or HashMap<String, Number> ? The input

DevExpress 2016.1新功能:WinForms TreeMap Control

独自空忆成欢 提交于 2019-11-27 07:17:44
下面先通过几个模型图先来感受下: DevExpress WinForms TreeMap Control 外观和操作自定义 DevExpress WinForms TreeMap允许你设置布局算法从而自定义tree map,16.1提供以下选项: 算法 示例 Slice and Dice Squarified Striped 上面的布局看着太单调?不用担心,TreeMap还有多种颜色布局方式: 颜色方案 示例 Palette Gradient Group Gradient Range 跟layout算法一样,你也可以自定义颜色方案。WinForms TreeMap控件支持selection, highlighting 和 tooltips等交互功能。 ========================= DevExpress 2016.1 即将发布 DevExpress历史版本下载 来源: oschina 链接: https://my.oschina.net/u/876556/blog/686130

WinForms篇:DevExpress v16.1新功能介绍

。_饼干妹妹 提交于 2019-11-27 07:17:21
TreeMap Control 在上一个版本(2015.1)中,DevExpress在WPF中增加了 TreeMap Control ,一种用嵌套矩形展示分层和平面数据的方式。此控件推出后,有大批Winforms版用户建议我们将其加入WinForms工具集中。为了满足广大 Winforms开发者的需求,DevExpress 2016.1正式将TreeMap Control加入WinForms版本!内置功能包括: 多布局算法: Slice and Dice, Squarified and Striped 可展示单层或多层数据 TreeMap支持多种颜色算法:gradient, group gradient, palette or range 可配置的工具提示 Item高亮和选择 外观自定义 详细介绍可参阅之前的新版预告: DevExpress 2016.1新版预告:WinForms TreeMap Control Unbound Data Source DevExpress WinForms Controls v16.1 新增支持一种新的数据类型:Unbound Data。它提供了两个事件用于恢复外部存储或在运行时修改的数据。它提供了一系列内置方法用于通知data-aware控件发生的变化。 Chart Control DevExpress WinForms, WPF 和 ASP

How to sort a treemap based on its values?

爷,独闯天下 提交于 2019-11-27 07:08:23
How can I sort a treemap using its values rather than the key? You cannot as the TreeMap's comparator is run against the keys only, e.g. see this constructor . Anyway, you can use multiple Collections, use the TreeMap (or rather HashMap) for looking up elements by keys, and have a SortedSet to iterate on the values. Anthony Here is a solution: public static <K, V extends Comparable<V>> Map<K, V> sortByValues(final Map<K, V> map) { Comparator<K> valueComparator = new Comparator<K>() { public int compare(K k1, K k2) { int compare = map.get(k2).compareTo(map.get(k1)); if (compare == 0) return 1;

putExtra treeMap returns HashMap cannot be cast to TreeMap android

流过昼夜 提交于 2019-11-27 06:54:19
问题 I need your help, I cannot understand what's happening? I'm trying to send a TreeMap between 2 activities, the code is something like this: class One extends Activity{ public void send(){ Intent intent = new Intent(One.this, Two.class); TreeMap<String, String> map = new TreeMap<String, String>(); map.put("1","something"); intent.putExtra("map", map); startActivity(intent); finish(); } } class Two extends Activity{ public void get(){ (TreeMap<String, String>) getIntent().getExtras().get("map")

How to initialize a TreeMap with pre-sorted data?

点点圈 提交于 2019-11-27 06:15:25
问题 My app uses a TreeMap to keep data sorted and have log(n) lookups & inserts. This works great in the general case while the app is running, but when the app first starts, I need to initialize the TreeMap with several million longs that I get in sorted order (ascending). Since these initialization values are already sorted, is there any way to insert them into the TreeMap without paying the log(n) cost of tree insertion and re-balancing? 回答1: Sure! The TreeMap.putAll method (and the TreeMap

Different colors with gradient for subgroups on a treemap ggplot2 R

佐手、 提交于 2019-11-27 06:11:51
问题 I have a treemap plot (shown below). The only change that I want to have is to change the color of subgroup (YEAR in the plot) to different colors, not all blue. Is this possible at all? Sample data frame PL <- c(rep("PL1", 4), repl("PL2", 4), rep("PL3", 4), rep("PL4", 4)) CNT <- sample(seq(1:50), 16) YEAR <- rep(c("2015", "2016", "2017", "2018"), 4) df <- data.frame(PL, YEAR, CNT) Plot PL <- c(rep("PL1", 4), repl("PL2", 4), rep("PL3", 4), rep("PL4", 4)) CNT <- sample(seq(1:50), 16) YEAR <-

Using java.util.Map in h:dataTable

梦想的初衷 提交于 2019-11-27 04:38:44
I need to display Map using <h:dataTable> . My backing bean has a Map property as below: public class Bean { private Map<Integer,String> map; // +getter @PostConstruct public void init() { map = new TreeMap<Integer,String>(); map.put(1,"Sasi"); map.put(2,"Pushparaju"); map.put(3,"Venkat Raman"); map.put(3,"Prabhakaran"); } } Then in JSF page I am trying to bind this Map property to the value attribute of <h:dataTable> . <h:dataTable border="1" value="#{bean.map}" var="map"> <h:column id="column1"> <f:facet name="header"> <h:outputText value="UserId"></h:outputText> </f:facet> <h:outputText