treemap

Sorting a map by date key in Java

风流意气都作罢 提交于 2019-12-02 12:33:34
I'm trying to sort a map in java by date key using TreeMap. Here's my code public static void sort() { BufferedReader br; String line; String[] data; Date date ; DateFormat df = new SimpleDateFormat("dd-mm-YYY"); Map<Date,String> map = new TreeMap<Date,String>(); try { br = new BufferedReader(new FileReader( "/home/user/Desktop/train/2013-training_set.txt")); int i=0; while ((line = br.readLine()) != null) { ++i; data = line.split(":"); map.put(df.parse(data[1]), line); } System.out.println(map.size()+" i = "+i); Set st = mp.entrySet(); Iterator it = st.iterator(); while (it.hasNext()) { Map

How to get current level on drilldown event in Highcharts treemap?

好久不见. 提交于 2019-12-02 08:58:09
问题 Seems like drilldown event is not triggered in Highcharts Treemap. I need to perform some task like showing alert with current level number on drilldown and drillup events. How can this be done in Treemaps? 回答1: At I see at this moment you can catch redraw event and prepare a simple "parser" which check id. Default structure of that is id_1 for first level, id_1_1 for second level. The simplest is use a split, and check length of array. Obviosuly this is very poor solution. events: { redraw:

How to get current level on drilldown event in Highcharts treemap?

别来无恙 提交于 2019-12-02 08:39:31
Seems like drilldown event is not triggered in Highcharts Treemap. I need to perform some task like showing alert with current level number on drilldown and drillup events. How can this be done in Treemaps? At I see at this moment you can catch redraw event and prepare a simple "parser" which check id. Default structure of that is id_1 for first level, id_1_1 for second level. The simplest is use a split, and check length of array. Obviosuly this is very poor solution. events: { redraw: function () { var rootNode = this.series[0].rootNode; if (rootNode === '') { alert(' NO DRILLED - LEVEL 0 ')

TreeMap.get() return Null even key exists

故事扮演 提交于 2019-12-02 07:39:00
问题 I am trying to get from TreeMap but it return null even the key exist. HashCode and eqauls is based on word only. Comparable is based on freqency. public static void main(){ TreeMap<Word,Integer> test = new TreeMap<>(); test.put(new Word("pqr",12),1); test.put(new Word("abc",2),1); Integer prq = test.get(new Word("pqr",1)); System.out.println(prq); prq = test.get(new Word("pqr",12)); System.out.println(prq); } public class Word implements Comparable<Word>{ String word; Integer freq; public

a集合源码剖析:TreeMap源码剖析

杀马特。学长 韩版系。学妹 提交于 2019-12-02 06:38:15
▷▷▷前言 本文不打算延续前几篇的风格(对所有的源码加入注释),因为要理解透TreeMap的所有源码,对博主来说,确实需要耗费大量的时间和经历,目前看来不大可能有这么多时间的投入,故这里意在通过于阅读源码对TreeMap有个宏观上的把握,并就其中一些方法的实现做比较深入的分析。 ▷▷ ▷ 红黑树简介 TreeMap是基于红黑树实现的,这里只对红黑树做个简单的介绍,红黑树是一种特殊的二叉排序树,关于二叉排序树,参见:http://blog.csdn.net/ns_code/article/details/19823463,红黑树通过一些限制,使其不会出现二叉树排序树中极端的一边倒的情况,相对二叉排序树而言,这自然提高了查询的效率。 二叉排序树的基本性质如下: 1、每个节点都只能是红色或者黑色 2、根节点是黑色 3、每个叶节点(NIL节点,空节点)是黑色的。 4、如果一个结点是红的,则它两个子节点都是黑的。也就是说在一条路径上不能出现相邻的两个红色结点。 5、从任一节点到其每个叶子的所有路径都包含相同数目的黑色节点。 正是这些性质的限制,使得红黑树中任一节点到其子孙叶子节点的最长路径不会长于最短路径的2倍,因此它是一种接近平衡的二叉树。 说到红黑树,自然不免要和AVL树对比一番。相比较而言,AVL树是严格的平衡二叉树,而红黑树不算严格意义上的平衡二叉树,只是接近平衡

Inflate ListView with TreeMap data (Custom Adapter)

安稳与你 提交于 2019-12-02 06:23:02
问题 Solved : I have created an adapter based on @JJV 's suggestion. I am aware that there is plenty of room for improvement, but it works for now. I have updated this simplified version of my program, with the working code; I hope it will be useful to others: MainActivity.java: import android.os.Bundle; import android.support.v7.app.AppCompatActivity; import android.widget.ListAdapter; import android.widget.ListView; import java.util.Map; import java.util.TreeMap; public class MainActivity

Not thread safe methods of CuncurrentSkipListMap in Java

你离开我真会死。 提交于 2019-12-02 06:22:20
In my Java project I need to use TreeMap in multihreaded way. I found that ConcurrentSkipListMap is what that I need but some methods are not thread safe. One of them - containsKey(Object key). What is a typical solution for using this methods in multhreded way? In my program I need put key that will not replace old and if it's impossible I will be putting another key while will not get unique key. What construction should use instead containsKey as i can't lost information? If you are worried about containsKey results going stale before you can act on them, or about this warning in the

How do I omit labels in the R treemap?

。_饼干妹妹 提交于 2019-12-02 06:03:34
I've been using the R treemap package and I have a treemap that's 2 levels deep. I want the second level labels to be printed but not the first. Using the example in the man page: tmPlot(GNI2010, index=c("continent", "iso3"), vSize="population", vColor="GNI", type="value") treemap example http://www.eecs.tufts.edu/~rveroy/stuff/GNI2010-treemap.png I want to get rid of the continent labels, but retain the iso3 labels. I apologize in advance if it is in the documents but haven't found it. To remove the continent labels, you can post hoc edit the graph. The graph produces a grid object. The last

并发容器的原理,七大并发容器详解、及使用场景

拟墨画扇 提交于 2019-12-02 03:34:41
并发容器的由来 在Java并发编程中,经常听到Java集合类,同步容器、并发容器,那么他们有哪些具体分类,以及各自之间的区别和优劣呢? 只有把这些梳理清楚了,你才能真正掌握在高并发的环境下,正确使用好并发容器,我们先从Java集合类,同步容器谈起。 1.什么是同步容器 Java的集合容器框架中,主要有四大类别:List、Set、Queue、Map,大家熟知的这些集合类ArrayList、LinkedList、HashMap这些容器都是非线程安全的。 如果有多个线程并发地访问这些容器时,就会出现问题。因此,在编写程序时,在多线程环境下必须要求程序员手动地在任何访问到这些容器的地方进行同步处理,这样导致在使用这些容器的时候非常地不方便。 所以,Java先提供了同步容器供用户使用。 同步容器可以简单地理解为通过synchronized来实现同步的容器 ,比如Vector、Hashtable以及SynchronizedList等容器。 2.同步容器,主要的分类: Vector Stack HashTable Collections.synchronized方法生成 同步容器面临的问题 可以通过查看Vector,Hashtable等这些同步容器的实现代码,可以看到这些容器实现线程安全的方式就是将它们的状态封装起来, 并在需要同步的方法上加上关键字synchronized。

Consistent Equals() results, but inconsistent TreeMap.containsKey() result

末鹿安然 提交于 2019-12-02 02:53:51
问题 I have the following object Node : private class Node implements Comparable<Node>(){ private String guid(); ... public boolean equals(Node o){ return (this == o); } public int hashCode(){ return guid.hashCode(); } public int compareTo(Node o){ return (this.hashCode() - o.hashCode()); } ... } And I use it in the following TreeMap : TreeMap<Node, TreeSet<Edge>> nodes = new TreeMap<Node, TreeSet<Edge>>(); Now, the tree map is used in a class called Graph to store nodes currently in the graph,