tree

问题 I have this function that converts a flat array to a tree based on a path property. This is my data : const input = [ {"name":"brussels_district_north","path":"Brussels/Brussels CBD/North"}, {"name":"brussels_district_louise","path":"Brussels/Brussels CBD/Louise"}, {"name":"brussels_district_west","path":"Brussels/Brussels Decentralised/West"}, {"name":"brussels_district_léopold","path":"Brussels/Brussels CBD/Léopold"}, {"name":"brussels_district_airport","path":"Brussels/Brussels Periphery

问题 I have this function that converts a flat array to a tree based on a path property. This is my data : const input = [ {"name":"brussels_district_north","path":"Brussels/Brussels CBD/North"}, {"name":"brussels_district_louise","path":"Brussels/Brussels CBD/Louise"}, {"name":"brussels_district_west","path":"Brussels/Brussels Decentralised/West"}, {"name":"brussels_district_léopold","path":"Brussels/Brussels CBD/Léopold"}, {"name":"brussels_district_airport","path":"Brussels/Brussels Periphery

问题 I have a list of elements, each has an ID and a parent ID. What I want to do is detect when there is a loop in this 'hierarchy', and show which ID starts the loop. list = [ { id: '1', parent: '2' }, { id: '2', parent: '3' }, { id: '3', parent: '4' }, { //This id is causing the loop id: '4', parent: '1' } ] I have tried this to build the tree, which works when there's no loop, but does not work with a loop: function treeify(list, idAttr, parentAttr, childrenAttr) { if (!idAttr) idAttr = 'id';

问题 I have a list of elements, each has an ID and a parent ID. What I want to do is detect when there is a loop in this 'hierarchy', and show which ID starts the loop. list = [ { id: '1', parent: '2' }, { id: '2', parent: '3' }, { id: '3', parent: '4' }, { //This id is causing the loop id: '4', parent: '1' } ] I have tried this to build the tree, which works when there's no loop, but does not work with a loop: function treeify(list, idAttr, parentAttr, childrenAttr) { if (!idAttr) idAttr = 'id';

问题 Say I have this piece of demo data: { size: 100, type: 'container', list: [ { size: 30, type: 'container', list: [ { size: 10, type: 'leaf', list: [1,2,3,4,5,6,7,8,9,10] }, { size: 15, type: 'leaf', list: [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15] }, { size: 25, type: 'leaf', list: [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25] } ] }, { size: 50, type: 'container', list: [ { size: 20, type: 'leaf', list: [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20] }, { size: 25, type:

问题 Say I have this piece of demo data: { size: 100, type: 'container', list: [ { size: 30, type: 'container', list: [ { size: 10, type: 'leaf', list: [1,2,3,4,5,6,7,8,9,10] }, { size: 15, type: 'leaf', list: [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15] }, { size: 25, type: 'leaf', list: [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25] } ] }, { size: 50, type: 'container', list: [ { size: 20, type: 'leaf', list: [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20] }, { size: 25, type:

问题 I would like to be able to personalize the plot that it is displayed to include standard deviation and statistical significance of the regressors after using the partykit::mob() function. The following code is from partykit documentation. library("partykit") if(require("mlbench")) { ## Pima Indians diabetes data data("PimaIndiansDiabetes", package = "mlbench") ## a simple basic fitting function (of type 1) for a logistic regression logit <- function(y, x, start = NULL, weights = NULL, offset

问题 I would like to be able to personalize the plot that it is displayed to include standard deviation and statistical significance of the regressors after using the partykit::mob() function. The following code is from partykit documentation. library("partykit") if(require("mlbench")) { ## Pima Indians diabetes data data("PimaIndiansDiabetes", package = "mlbench") ## a simple basic fitting function (of type 1) for a logistic regression logit <- function(y, x, start = NULL, weights = NULL, offset

问题 I have a balanced binary tree structure: Node 0 at depth 0 is the root. The root's left child is 1 and right child is 2 , and so on. Please see image: The total depth of the tree is given as N . This N is the only parameter of the problem. Nodes at level N are designated as leaf nodes. I am storing this tree using the following node structure. struct node_s{ int n, depth, parent;//n is node number int nodescendents;//number of descendents of the current node std::vector<int> descendents;/

问题 I have a balanced binary tree structure: Node 0 at depth 0 is the root. The root's left child is 1 and right child is 2 , and so on. Please see image: The total depth of the tree is given as N . This N is the only parameter of the problem. Nodes at level N are designated as leaf nodes. I am storing this tree using the following node structure. struct node_s{ int n, depth, parent;//n is node number int nodescendents;//number of descendents of the current node std::vector<int> descendents;/