transpose

Google Sheets Text Join to join character from columns into row

别等时光非礼了梦想. 提交于 2021-01-29 06:22:55
问题 have data like this and want result like this using this formula: =ARRAYFORMULA(REGEXREPLACE(TRIM(SPLIT(TRANSPOSE(QUERY(QUERY( IF(D2:D<>"", {C2:C&"♠", D2:D&","}, ), "select max(Col2) where Col1 is not null group by Col2 pivot Col1") ,,999^99)), "♠")), ",$", )) make the result like this Can someone figure it out, How to fix this formula? Thanks 来源: https://stackoverflow.com/questions/62670569/google-sheets-text-join-to-join-character-from-columns-into-row

How to transpose a 2D list array using loops in python?

此生再无相见时 提交于 2021-01-28 21:50:49
问题 Say I have: a = [[1, 1, 1, 6], [0, 2, -1, 3], [4, 0, 10, 42]] and I want to transpose it to: a = [[1,0,4], [1,2,0], [1,-1,10], [6,3,42]] using loops in python. The current code that I have is: def transpose(a): s = [] for row in range(len(a)): for col in range(len(a)): s = s + [a[col][row]] return s But this gives me the output of: [1, 0, 4, 1, 2, 0, 1, -1, 10] Instead of this: [[1,0,4], [1,2,0], [1,-1,10], [6,3,42]] Can anyone help me? I'm still new at this stuff and don't understand why it

How to transpose a 2D list array using loops in python?

大兔子大兔子 提交于 2021-01-28 21:06:58
问题 Say I have: a = [[1, 1, 1, 6], [0, 2, -1, 3], [4, 0, 10, 42]] and I want to transpose it to: a = [[1,0,4], [1,2,0], [1,-1,10], [6,3,42]] using loops in python. The current code that I have is: def transpose(a): s = [] for row in range(len(a)): for col in range(len(a)): s = s + [a[col][row]] return s But this gives me the output of: [1, 0, 4, 1, 2, 0, 1, -1, 10] Instead of this: [[1,0,4], [1,2,0], [1,-1,10], [6,3,42]] Can anyone help me? I'm still new at this stuff and don't understand why it

Is there a better way to replicate a column array n times in Google Sheets

杀马特。学长 韩版系。学妹 提交于 2021-01-28 19:02:35
问题 I need to formulaic solution to copy a column range stacking on top of itself a given number of times. I found one ugly solution by incorporating a sequence function (to get 1,2,3...n) into an arrayformula for a text operation (Left). The Left operation does nothing but return the original value, but gives me the opportunity to include the sequence array. There must be a better way to do this. Problem : Write a formula that creates a column where a named column range is stacked on top of each

Transposing JSON data

梦想的初衷 提交于 2021-01-28 12:05:52
问题 I know there are threads on this, but I dont get it and might need help on my json file. I want to bind a json to one of my SAPUI5 controls, but I dont get it converted. The thing is, I got my data already in the frontend, so I dont want to make a second backend call and I need to transpose my json data. This is what I got, columns are Mon01 .. etc. Mon01 Mon02 Mon03 Mon04 0 03/2015 04/2015 05/2015 06/2015 1 1 3 5 21 2 2 4 6 22 3 10 11 12 23 This is what I want: Mon01 Mon02 Mon03 Mon04 0 03

Join four columns into one according to each row

北战南征 提交于 2021-01-28 11:29:16
问题 A B C D E F G H I J K L M N O P If I chose to join the columns I would ={A1:A;B1:B;C1:C;D1:D} but it would look like this: A E I M B F J N ... and so on I would like it to look like this: A B C D E F G ... and so on How to proceed in this case? Note: It may happen that some of the columns are not complete in data, some may have more values than the others, but I still want to continue following this same pattern. Example: A B D E G H I J K L M N O P Result: A B D E G H ... and so on 回答1: use:

How to transpose a matrix of unequal array length in Swift 3

天涯浪子 提交于 2021-01-28 07:52:48
问题 My array is of type [[Int]] array = [[1,2,3], [4,5,6], [7,8,9,10], [11,12,13], [14,15,16]] I want the transpose result as: array = [[1,4,7,11,14], [2,5,8,12,15], [3,6,9,13,16], [0,0,10,0,0]] How to pad 0's to an array which does not have an equal row or column mapping. I want the transpose to work for both rows and columns with unequal mapping elements. Please help. 回答1: Here is an implementation that does what you want: func transpose(_ input: [[Int]]) -> [[Int]] { let columns = input.count

Table of data want to group, transpose matching values same line

偶尔善良 提交于 2021-01-27 21:06:22
问题 I have a table of data in Excel. Column A contains Names, Column B contains their interest. Each interest has a separate row. I want to take the data from this table and have a single row with the name of the customer and a column for each of their interests. IE RAW Data: I am looking to take the 4000 row table and grouping by the name. I am unsure how many times each name appears in the list (Once or Fifty times) but I want the interests placed on a single row with each interest in a

pandas groupby transpose str column

与世无争的帅哥 提交于 2021-01-27 14:18:06
问题 here is what I am trying to do: >>>import pandas as pd >>>dftemp = pd.DataFrame({'a': [1] * 3 + [2] * 3, 'b': 'a a b c d e'.split()}) a b 0 1 a 1 1 a 2 1 b 3 2 c 4 2 d 5 2 e 6 3 f how to transpose column 'b' grouped by column 'a', so that output looks like: a b0 b1 b2 0 1 a a b 3 2 c d e 6 3 f NaN NaN 回答1: Using pivot_table with cumcount : (df.assign(flag=df.groupby('a').b.cumcount()) .pivot_table(index='a', columns='flag', values='b', aggfunc='first') .add_prefix('B')) flag B0 B1 B2 a 1 a a

How do I get gawk to transpose my data into a csv file

倾然丶 夕夏残阳落幕 提交于 2021-01-07 02:58:28
问题 I have a bunch of input text files that look like this: measured 5.7 0.0000 0.0000 0.0125 0.0161 0.0203 0.0230 0.0233 0.0236 0.0241 0.0243 0.0239 0.0235 0.0226 0.0207 0.0184 0.0147 0.0000 0.0000 measured 7.4 0.0000 0.0000 0.0160 0.0207 0.0260 0.0295 0.0298 0.0302 0.0308 0.0311 0.0306 0.0300 0.0289 0.0264 0.0235 0.0187 0.0000 0.0000 Each file has a couple of lines like that. I want to take all of these files, cut out the 'measured' and first number (eg. 5.7 and 7.4) and put them in a CSV file