transpose

问题 How can I transpose a list like [[1,2,3][4,5,6][6,7,8]] to [[1,4,6],[2,7,8],[3,6,9]] ? To depict it: I'd like to flip the matrix 90 degree to the left. How can I do that? 回答1: Not sure your example is correct, but I get the idea. If using SWI-PROLOG, you can use the CLPFD module, like so: :- use_module(library(clpfd)). Allowing you to use the transpose/2 predicate, like this: 1 ?- transpose([[1,2,3],[4,5,6],[6,7,8]], X). X = [[1, 4, 6], [2, 5, 7], [3, 6, 8]]. Otherwise (if no SWI-PROLOG), you

问题 I have the following source and destination tables in SQL Server 2008R2. How can I do pivot(s) in TSQL to transform SourceTbl into DestTbl ? Hoping that the empIndex will somehow help in the pivot. SourceTbl empId empIndex empState empStDate empEndDate ======================================================== 10 1 AL 1/1/2012 12/1/2012 10 2 FL 2/1/2012 2/1/2013 15 1 FL 3/20/2012 1/1/2099 DestTbl empId empState1 empState1StDate empState1EndDt empState2 empState2StDate empState2EndDt ===========

问题 Given the following List: val l = List(List(1, 2, 3), List(4, 5), List(6, 7, 8)) If I try to transpose it, Scala will throw the following error: scala> List.transpose(l) java.util.NoSuchElementException: head of empty list at scala.Nil$.head(List.scala:1365) at scala.Nil$.head(List.scala:1362) at scala.List$$anonfun$transpose$1.apply(List.scala:417) at scala.List$$anonfun$transpose$1.apply(List.scala:417) at scala.List.map(List.scala:812) at scala.List$.transpose(List.scala:417) at .<init>(

问题 This question already has answers here : How to pivot a dataframe (2 answers) Closed last year . I have a table in csv format that looks like this. I would like to transpose the table so that the values in the indicator name column are the new columns, Indicator Country Year Value 1 Angola 2005 6 2 Angola 2005 13 3 Angola 2005 10 4 Angola 2005 11 5 Angola 2005 5 1 Angola 2006 3 2 Angola 2006 2 3 Angola 2006 7 4 Angola 2006 3 5 Angola 2006 6 I would like the end result to like like this:

问题 This question already has answers here : How to pivot a dataframe (2 answers) Closed last year . I have a table in csv format that looks like this. I would like to transpose the table so that the values in the indicator name column are the new columns, Indicator Country Year Value 1 Angola 2005 6 2 Angola 2005 13 3 Angola 2005 10 4 Angola 2005 11 5 Angola 2005 5 1 Angola 2006 3 2 Angola 2006 2 3 Angola 2006 7 4 Angola 2006 3 5 Angola 2006 6 I would like the end result to like like this:

问题 I have the following table Id Letter 1001 A 1001 H 1001 H 1001 H 1001 B 1001 H 1001 H 1001 H 1001 H 1001 H 1001 H 1001 A 1001 H 1001 H 1001 H 1001 B 1001 A 1001 H 1001 H 1001 H 1001 B 1001 B 1001 H 1001 H 1001 H 1001 B 1001 H 1001 A 1001 G 1001 H 1001 H 1001 A 1001 B 1002 B 1002 H 1002 H 1002 B 1002 G 1002 H 1002 B 1002 G 1002 G 1002 H 1002 B 1002 G 1002 H 1002 H 1002 G 1002 H 1002 H 1002 H 1002 H 1002 H 1002 M 1002 N 1002 G 1002 H 1002 H 1002 M 1002 M 1002 A 1002 H 1002 H 1002 H 1002 A 1002

问题 I have the following associative array of column data: $where = array( 'id'=>array( 12, 13, 14 ), 'date'=>array( '1999-06-12', '2000-03-21', '2006-09-31' ) ); I need to transpose / rotate the structure to be an array of rows (with merged column data assigned to their respective row). I don't need the column names in the result. Expected output: $comb = array( array(12, '1999-06-12'), array(13, '2000-03-21'), array(14, '2006-09-31') ); 回答1: As Kris Roofe stated in his deleted answer, array

问题 I am working with a data dump of transactions which is not exported from the particular system in a very friendly format for any purpose. The data in Excel is made up of approximately 700,000 rows currently, whereas once organised correctly should only consist of maybe 70,000, where the unique values of one particular column are transposed into some additional columns. Currently I am working with something like this (simplified) example below; Request_ID Status Field_Name Value 01000 Rejected

问题 I want to Transpose columns and rows when you don't have a unique id type column in BigQuery. I have large number of rows. Date values are unique for each month-year going over couple of years. Columns: date total_count_of_customer total_revenue new_customer_count new_customer_revenue churn_count churn_revenue flat_count flat_revenue returning_count returning_revenue expansion_mrr expansion_count contraction_mrr contraction_count I want to swap 'date' column values to column and rest of the

问题 I am trying to transpose data in SAS from a long format to a wide format. The problem I'm having is that I have multiple columns that I'm trying to transpose. I have a few example datasets below to demonstrate what I'm trying to do. The actual dataset I'm doing this on is going to be very large, I think one way to handle this could be to tranpose individual columns and then merge at the end, but the dataset I'm going to be doing this on is going to be significantly larger (tens of thousands