token

Flask 教程 第十章:邮件支持

房东的猫 提交于 2019-12-18 11:58:07
本文翻译自 The Flask Mega-Tutorial Part X: Email Support 这是Flask Mega-Tutorial系列的第十部分,在其中我将告诉你,应用如何向你的用户发送电子邮件,以及如何在电子邮件支持之上构建密码重置功能。 现在,应用在数据库方面做得相当不错,所以在本章中,我想抛开这个主题,开始添加发送电子邮件的功能,这是大多数Web应用必需的另一个重要部分。 为什么应用需要发送电子邮件给用户? 原因很多,但其中一个常见的原因是解决与认证相关的问题。 在本章中,我将为忘记密码的用户添加密码重置功能。 当用户请求重置密码时,应用将发送包含特制链接的电子邮件。 用户然后需要点击该链接才能访问设置新密码的表单。 本章的GitHub链接为: Browse , Zip , Diff . Flask-Mail简介 就实际的邮件发送而言,Flask有一个名为 Flask-Mail 的流行插件,可以使任务变得非常简单。 和往常一样,该插件是用pip安装的: 1 (venv) $ pip install flask-mail 密码重置链接将包含有一个安全令牌。 为了生成这些令牌,我将使用 JSON Web Tokens ,它也有一个流行的Python包: 1 (venv) $ pip install pyjwt Flask-Mail插件是通过 app.config

eBay oauth token and refresh tokens [closed]

可紊 提交于 2019-12-18 11:46:35
问题 Closed. This question is off-topic. It is not currently accepting answers. Want to improve this question? Update the question so it's on-topic for Stack Overflow. Closed 6 months ago . been struggling for couple of days with eBay token authentication. I am finding it hard to understand how to fetch new tokens, after signing up for a developer program account, I requested the key-set and got them, afterwards I grant access on Auth'n'Auth token which promises to last for 18 months, and yes the

How to call https://www.googleapis.com/plus/v1/people/me at google

空扰寡人 提交于 2019-12-18 11:34:40
问题 I am developing an Android application and need to get the "me" info from google but I always ends up in either response code 401 or 403. What am I doing wrong? Here is my code: private static final String GOOGLE_AUTH_TOKEN_TYPE = "oauth2:https://www.googleapis.com/auth/plus.me"; I get the oauth token by (note...code below is shortened): Account googleAccount = (AccountManager) getSystemService(ACCOUNT_SERVICE).getAccountsByType("com.google")[0]; final Bundle bundle = manager.getAuthToken

How to call https://www.googleapis.com/plus/v1/people/me at google

喜夏-厌秋 提交于 2019-12-18 11:34:28
问题 I am developing an Android application and need to get the "me" info from google but I always ends up in either response code 401 or 403. What am I doing wrong? Here is my code: private static final String GOOGLE_AUTH_TOKEN_TYPE = "oauth2:https://www.googleapis.com/auth/plus.me"; I get the oauth token by (note...code below is shortened): Account googleAccount = (AccountManager) getSystemService(ACCOUNT_SERVICE).getAccountsByType("com.google")[0]; final Bundle bundle = manager.getAuthToken

拼多多开放平台对接全流程

怎甘沉沦 提交于 2019-12-18 10:21:28
一. 创建应用(我这里创建了 商家后台应用) https://open.pinduoduo.com/#/application/type 二.授权登录 1.拼接拼多多授权登录Url https://mms.pinduoduo.com/open.html?response_type=code& client_id = {0} & redirect_uri = {1} &state=1212 注意这里的 client_id 需要改成你当前应用的 client_id , redirect_uri 需要修改成登录成功之后跳转的地址 这里的 redirect_uri 地址需要和你在应用设置里面填入的回调地址一致 如下图所示: 商家账号登录成功之后跳转到回调地址,在地址后面返回 code 和 state。 通过code 可以请求获取到 Token ,state则是验证与之前传入的state 是否相同 2.通过 Code 请求Token /// <summary> /// 拼多多Token刷新方法 /// </summary> /// <param name="code"></param> public void ResreshAccessByPDD(string code) { dynamic parameter = new { client_id = "应用client_id", code

How do I ensure that Scanner hasNextInt() asks for new input?

萝らか妹 提交于 2019-12-18 07:04:13
问题 New programmer here. This is probably a really basic question, but it's stumping me nevertheless. What I'm trying to do is write a method that supplies only one integer input so I can use that input in my main program without having to mess around with non-integer inputs. However, even writing the method to do that in its own method seems to be problematic. public static int goodInput () { Scanner input = new Scanner (System.in); //construct scanner boolean test = input.hasNextInt(); //set a

微信公众平台开发——群发信息

家住魔仙堡 提交于 2019-12-18 05:36:19
1、目的   完成在微信公众号中群发消息。这里只是完成简单的 文字发送 。也可以发送语音图片等,只是发送数据格式不同而已,下面有链接,可以查询数据类型的数据发送格式。 2、群发短信的流程 获取测试公众账号(有账号的可以不用测试账号,不过正式的账号限制比较多) 用户关注上面的公众账号 通过appid和appsecret获取我们的access_token 通过access_token群发短信 3、获取测试公众账号 + 关注公众号 1)、公众测试账号获取   访问上面的连接,选择“接口测试号申请”获得直接打开 http://mp.weixin.qq.com/debug/cgi-bin/sandboxinfo?action=showinfo&t=sandbox/index 通过微信客户端扫码登录即可登录。   登录完即可获取到一个测试公众账号的信息。主要有appId和appsecret两个参数,这将唯一标示一个公众号,并且需要将他们作为参数获取用户的信息。、 2)、配置接口信息 这一步可以参照 微信接入说明 ,该页提供一个php的实例下载,很简单基本上修改一下自定义的TOKEN就好了,然后把验证页面放到自己的服务器上。 这里我提供我做的一个例子: 准备资源: 域名+空间(我的是sae空间+万网域名)、仅作验证的php文件 域名指向的空间根目录我创建了一个wx_sample.php wx

What's the meaning of the “kid” claim in a JWT token?

谁说我不能喝 提交于 2019-12-18 04:28:06
问题 I generated a JWT and there are some claims which I understand well, but there is a claim called kid in header. Does anyone know what it means? I generated the token using auth0.com 回答1: kid is an optional header claim which holds a key identifier, particularly useful when you have multiple keys to sign the tokens and you need to look up the right one to verify the signature. Once a signed JWT is a JWS, consider the definition from the RFC 7515: 4.1.4. "kid" (Key ID) Header Parameter The kid

How to get a Facebook access token for a page with no app or app secret

不问归期 提交于 2019-12-18 03:42:07
问题 I am trying to automatically display wall posts from a Facebook page another website. I can use the Graph API explorer to get one manually. When I use the generated token in my code all is well. The problem is the tokens expire quickly. It just isn't practical to get a new code several times a day. I know there is a way to request an access token programatically - in my case via PHP, but all the examples call for an app secret. Since this is a page and not an app, there is no secret. I have

How to generate a Google ReCaptcha V2 secure token with PHP?

只谈情不闲聊 提交于 2019-12-18 03:36:45
问题 I'm trying to generate a secure token for ReCaptcha V2, as described here: https://developers.google.com/recaptcha/docs/secure_token Unfortunately, my generated stoken isn't valid and I can't find a way to check why it doesn't work. There is a working Java example (STokenUtils.java), but I find myself unable to translate it to PHP. public static function generateSecurityToken($secretKey){ $stoken = array( 'session_id' => session_id(), 'ts_ms' => round(microtime(true)*1000) ); $secretKey =