tld

I have a new site I am working on that is using adsense. It is https://viewing.nyc and very much a work in progress. I have some adsense ads displaying on the site already and they work -- ins the sense that they actually display ads -- but they output a ton of garbage in the Safari console. The message I constantly see is the classic: Blocked a frame with origin "https://googleads.g.doubleclick.net" from accessing a frame with origin "https://viewing.nyc". Protocols, domains, and ports must match. So, I have been playing around with it for a few days here and there, googling for solutions and

In the need for finding e-mail addresses and host names, we would like to improve an existing regex to seach only for existing public TLD's . We would like one bash command where we can copy and paste its output into our regular expression . We already had trial with (co|com) which matches only 'co' and doesn't match the full 'com' tld for .com domains, that is why the tld list need to be sorted with longest TLD's first . Can someone supply a one line "copy and paste" bash command that outputs the most recent list of TLD's sorted and formatted? Pro Backup With the help of @Alex_Volkov his

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: In the need for finding e-mail addresses and host names, we would like to improve an existing regex to seach only for existing public TLD's . We would like one bash command where we can copy and paste its output into our regular expression . We already had trial with (co|com) which matches only 'co' and doesn't match the full 'com' tld for .com domains, that is why the tld list need to be sorted with longest TLD's first . Can someone supply a one line "copy and paste" bash command that outputs the most recent list of TLD's sorted and

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: how would you extract the domain name from a URL, excluding any subdomains? My initial simplistic attempt was: '.'.join(urlparse.urlparse(url).netloc.split('.')[-2:]) This works for http://www.foo.com , but not http://www.foo.com.au . Is there a way to do this properly without using special knowledge about valid TLDs (Top Level Domains) or country codes (because they change). thanks 回答1: No, there is no "intrinsic" way of knowing that (e.g.) zap.co.it is a subdomain (because Italy's registrar DOES sell domains such as co.it ) while zap.co.uk

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: Need a way to extract a domain name without the subdomain from a url using Python urlparse. For example, I would like to extract "google.com" from a full url like "http://www.google.com" . The closest I can seem to come with urlparse is the netloc attribute, but that includes the subdomain, which in this example would be www.google.com . I know that it is possible to write some custom string manipulation to turn www.google.com into google.com, but I want to avoid by-hand string transforms or regex in this task. (The reason for this is that I

可以将文章内容翻译成中文,广告屏蔽插件可能会导致该功能失效(如失效，请关闭广告屏蔽插件后再试): 问题: I have a Java EE project which build fine with Ant, deploys perfectly to JBoss, and runs without any trouble. This project includes a few custom tag libraries (which is not JSTL !), which are also working without any difficulties. The problem is with the Eclipse IDE (Ganymede): in every single JSP file which uses our custom tags, the JSP parser flags the taglib include line with with this error: Cannot find the tag library descriptor for (example).tld This also causes every use of the tab library to be flagged as an error, and since the IDE

Basically Ive written out this about 5 times, still dont know how to properly ask, so here goes... I want two domains, say example.net and example.info which I have registered. I want them to point to the one application I'm building, then hopefully use Laravel to route the two different domains to there own pages... here is what I've tried and what problems I've ran into... ** #1 Domain Forward ** Uploaded my app to example.net and forwarded the .info domain to the .net domain. And then tried... Route::group(array('domain' => 'example.info'), function() { Route::get('/', function(){ return