timestamp

问题 I have some Unix timestamps (for example, 1357810480, so they're mainly in the past). How can I transform them into a readable date-format using Perl? 回答1: You can use localtime for that. my ($sec, $min, $hour, $mday, $mon, $year, $wday, $yday, $isdst) = localtime($unix_timestamp); 回答2: Quick shell one-liner: perl -le 'print scalar localtime 1357810480;' Thu Jan 10 10:34:40 2013 Or, if you happen to have the timestamps in a file, one per line: perl -lne 'print scalar localtime $_;'

问题 I ran into a problem as I tried to create two TIMESTAMP columns in my database. One called created and one called updated . I figured it would be easy to set the default value of both to CURRENT_TIMESTAMP and then ON UPDATE CURRENT_TIMESTAMP for the updated column. But for some reason MySQL means that's a bad idea... so I have been looking for ways to do this without having to set one of them in the insert query. I found one way by using a trigger in this answer, but I keep getting errors. I

问题 I have some code written in Go which I am trying to update to work with the latest weekly builds. (It was last built under r60). Everything is now working except for the following bit: if t, _, err := os.Time(); err == nil { port[5] = int32(t) } Any advice on how to update this to work with the current Go implementation? 回答1: import "time" ... port[5] = int32(time.Now().Unix()) 回答2: If you want it as string just convert it via strconv : package main import ( "fmt" "strconv" "time" ) func main

问题 I have some code written in Go which I am trying to update to work with the latest weekly builds. (It was last built under r60). Everything is now working except for the following bit: if t, _, err := os.Time(); err == nil { port[5] = int32(t) } Any advice on how to update this to work with the current Go implementation? 回答1: import "time" ... port[5] = int32(time.Now().Unix()) 回答2: If you want it as string just convert it via strconv : package main import ( "fmt" "strconv" "time" ) func main

问题 I am trying to select data from a table, using a "like" on date field "date_checked" (timestamp). But I have this error : SQLSTATE[42883]: Undefined function: 7 ERROR: operator does not exist: timestamp without time zone My request is : SELECT my_table.id FROM my_table WHERE my_table.date_checker LIKE '2011-01-%' I don't want to use : SELECT my_table.id FROM my_table WHERE my_table.date_checker >= '2011-01-01 00:00:00' AND my_table.date_checker < '2011-02-01 00:00:00' 回答1: It's all very well

问题 I am trying to select data from a table, using a "like" on date field "date_checked" (timestamp). But I have this error : SQLSTATE[42883]: Undefined function: 7 ERROR: operator does not exist: timestamp without time zone My request is : SELECT my_table.id FROM my_table WHERE my_table.date_checker LIKE '2011-01-%' I don't want to use : SELECT my_table.id FROM my_table WHERE my_table.date_checker >= '2011-01-01 00:00:00' AND my_table.date_checker < '2011-02-01 00:00:00' 回答1: It's all very well

问题 How can I reset the time part of a pandas timestamp? I want to reset time part in value of pandas.Timestamp. I guess I can do it using the following procedure. step 1) Timestamp to datetime type step 2) datetime to seconds step 3) truncate time part in seconds step 4) bring back seconds to Timestamp Even if my guess is correct, it takes too long to do. Is there a straightforward way to achieve this goal? In [371]: ts = pd.Timestamp('2014/11/12 13:35') In [372]: ts Out[372]: Timestamp('2014-11

问题 I have a table in cassandra with a datatype of timestamp. i am using cqlsh to get data out of the database and wanted to change the output format for how my timestamp column output looks like. I researched around and found that i can change the timestamp output format by making changes to the following file: ~/.cassandra/cqlshrc But i learnt that the only change i can make is the time elements, i cannot make the output to display my timestamps in a different timezone(say UTC). It always

问题 I need to display timestamp of a post with in django template. The timestamp would be like: "timestamp":1337453263939 in milli seconds I can convert the timestamp into datetime object and render it in the view. Is there is any direct way to display through the template? The output should be: print(datetime.datetime.fromtimestamp(1337453263.939)) 2012-05-20 00:17:43.939000 回答1: You could use custom template filters (see https://docs.djangoproject.com/en/dev/howto/custom-template-tags/). In

问题 I have an intranet running on a linux box, which authenticates against Active Directory on a Windows box, using LDAP through PHP. I can retrieve a user's entry from AD using LDAP and access the last login date from the php array eg: echo $adAccount['lastlogontimestamp'][0]; // returns something like 129802528752492619 If this was a Unix timestamp I would use the following PHP code to convert to a human readable date: date("d-m-Y H:i:s", $lastlogontimestamp); However, this does not work. Does