timestamp

问题 I have a file that contains a set of Timestamps in format of H:M:S.MS , I can read and print all of the saved Timestamps but when I do some arithmetic operation like Subtract (say Timestamp2 - Timestamp1 ) it doesn't give me the answer, I do not have experience work with bash script programming. Any suggestions, recommendations will be much appreciated. Here is the screen shot of my problem. Here is an example : Start Time = 17:53:01.166721 End Time = 17:53:01.369787 The expected result for

问题 I have a file that contains a set of Timestamps in format of H:M:S.MS , I can read and print all of the saved Timestamps but when I do some arithmetic operation like Subtract (say Timestamp2 - Timestamp1 ) it doesn't give me the answer, I do not have experience work with bash script programming. Any suggestions, recommendations will be much appreciated. Here is the screen shot of my problem. Here is an example : Start Time = 17:53:01.166721 End Time = 17:53:01.369787 The expected result for

问题 I have an X.509 certificate which has the following 2 timestamps: ['validFrom'] = String(13) "120314165227Z" ['validTo'] = String(13) "130314165227Z" What does the postfix character 'Z' mean. Does it specify the timezone? 回答1: Yes. 'Z' stands for Zulu time, which is also GMT and UTC. From http://en.wikipedia.org/wiki/Coordinated_Universal_Time: The UTC time zone is sometimes denoted by the letter Z—a reference to the equivalent nautical time zone (GMT), which has been denoted by a Z since

问题 I have a df with weekly columns as below. I want to change my column index to timestamp. Here is my df.columns df.columns: Int64Index([201601, 201602, 201603, 201604, 201605, 201606, 201607, 201608, 201609, ...], dtype='int64', name='timeline', length=104) df.columns[0]: 201553 I want to change my df.columns into timestamp as below df.columns: DatetimeIndex(['2016-01-04', '2016-01-11', '2016-01-18', '2016-01-25', '2016-02-01', '2016-02-08', '2016-02-15', '2016-02-22', '2016-02-29'.....],

问题 I have a df with weekly columns as below. I want to change my column index to timestamp. Here is my df.columns df.columns: Int64Index([201601, 201602, 201603, 201604, 201605, 201606, 201607, 201608, 201609, ...], dtype='int64', name='timeline', length=104) df.columns[0]: 201553 I want to change my df.columns into timestamp as below df.columns: DatetimeIndex(['2016-01-04', '2016-01-11', '2016-01-18', '2016-01-25', '2016-02-01', '2016-02-08', '2016-02-15', '2016-02-22', '2016-02-29'.....],

问题 I need to write a query to get an object between a range of time, currently the query looks like this: Timestamp from = ... Timestamp to = ... getHibernateTemplate().find("from " + Person.class.getName() + " ml where ml.lastModifiedOn>="+from.toString()+" and m1.lastModifiedOn<=" + to.toString()); However, this doesnot work for obvious reasons. How can I format the timestamp to be acceptable by the query. org.springframework.orm.hibernate3.HibernateQueryException: unexpected token: 16 near

问题 Basically I am trying to convert a date field from my database into a number of seconds old. I used UNIX_TIMESTAMP on our old MySQL database and am looking for an equivalent function in PostgreSQL. Thanks in advance 回答1: SELECT extract(epoch FROM your_datetime_column) FROM your_table More details in the manual: http://www.postgresql.org/docs/current/static/functions-datetime.html#FUNCTIONS-DATETIME-EXTRACT 回答2: This: select CURRENT_TIMESTAMP - '1970-01-01'; Will give you an interval type. You

问题 I need to convert a date in Windows PowerShell to the ISO 8601 format. In Linux/Unix it was no problem with TZ=0 date -d "<random-format>" +%Y-%m-%dT%H:%M:%S.000Z Now I need to do the same in Windows PowerShell. The output format on Windows is Wednesday, 19. July 2017 01:06:13 How can I do it? 回答1: PowerShell's Get-Date supports standard .NET time formats. The o round-trip format complies with ISO 8601. Like so, Get-Date -Format "o" 2017-08-15T12:10:34.4443084+03:00 回答2: Get-Date supports

问题 This question already has answers here : Date object SimpleDateFormat not parsing timestamp string correctly in Java (Android) environment (6 answers) Changing Java Timestamp format causes a change of the timestamp (2 answers) Closed 3 months ago . My below function doesn't cast the date to the defined format. val oldFormat= new SimpleDateFormat("yyyy-MM-dd-HH.mm.ss.SSSSSS") val newFormat= new SimpleDateFormat("yyyy-MM-dd hh:mm:ss.SSSSSS",Locale.ENGLISH) newFormat.format(oldFormat.parse(s)

问题 my application takes in a string like this "2002-10-15 10:55:01.000000". I need to validate that the string is a valid for a db2 timestamp. How can I do this? EDIT: This mostly works public static boolean isTimeStampValid(String inputString) { SimpleDateFormat format = new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss.SSSSSS"); try { format.parse(inputString); return true; } catch (ParseException e) { return false; } } The problem is that if I pass it a bad format for milliseconds like