timedelta

问题 I program currently something with SDL2. All works fine, but I have a problem with the SDL_GetTicks() method. Normally it should return the total application time in milliseconds, but it always returns most of the time the value 0 and sometimes the value 1. I initialized SDL with SDL_INIT_EVERYTHING flag. The problem with the following code is the loop is too fast, so the delta time is smaller than 1 ms. Is there a method to achieve a higher precision? #include "Application.hpp" void

问题 I program currently something with SDL2. All works fine, but I have a problem with the SDL_GetTicks() method. Normally it should return the total application time in milliseconds, but it always returns most of the time the value 0 and sometimes the value 1. I initialized SDL with SDL_INIT_EVERYTHING flag. The problem with the following code is the loop is too fast, so the delta time is smaller than 1 ms. Is there a method to achieve a higher precision? #include "Application.hpp" void

问题 Previously in my main loop of the game, the time was managed at 60 FPS and the respective Delay for the time delay. The Sprite sequence was animated as follows: <pre> if(++ciclos > 10){ siguienteSprite++; ciclos = 0; } </pre> Given that I am using Smooth Motion with DeltaTime, therefore I have eliminated Delay from the Main Cycle; Making this the sprites cycles of the animation are faster, and not only this, but also the time between each sequence varies. Someone could give me a hand, only

问题 I have some input data, with timestamps in the input file in the form of hours from the date time specified in the filename. This is a bit useless, so I need to convert it to python datetime.datetime objects, and then put it in a numpy array. I could write a for loop, but I'd like to do something like: numpy.arange(datetime.datetime(2000, 1,1), datetime.datetime(2000, 1,2), datetime.timedelta(hours=1)) which throws a TypeError. Can this be done? I'm stuck with python 2.6 and numpy 1.6.1. 回答1:

问题 I am trying to convert two "durations", however I am currently receiving a TypeError due to one being a datetime.timedelta and one being a datetime.time : TypeError: unorderable types: datetime.time() <= datetime.timedelta() What is an efficient way to convert a datetime.time to a datetime.timedelta ? I have checked the docs and there is no built-in method for conversion between these two types. 回答1: datetime.time() is not a duration , it is a point in a day. If you want to interpret it as a

问题 I have a pandas DataFrame with timedeltas as a cumulative sum of those deltas in a separate column expressed in milliseconds. An example is provided below: Transaction_ID Time TimeDelta CumSum[ms] 1 00:00:04.500 00:00:00.000 000 2 00:00:04.600 00:00:00.100 100 3 00:00:04.762 00:00:00.162 262 4 00:00:05.543 00:00:00.781 1043 5 00:00:09.567 00:00:04.024 5067 6 00:00:10.654 00:00:01.087 6154 7 00:00:14.300 00:00:03.646 9800 8 00:00:14.532 00:00:00.232 10032 9 00:00:16.500 00:00:01.968 12000 10

问题 I read a csv file into pandas dataframe df and I get the following: df.columns Index([u'TDate', u'Hour', u'SPP'], dtype='object') >>> type(df['TDate'][0]) <class 'pandas.tslib.Timestamp'> type(df['Hour'][0]) <type 'numpy.int64'> >>> type(df['TradingDate']) <class 'pandas.core.series.Series'> >>> type(df['Hour']) <class 'pandas.core.series.Series'> Both the Hour and TDate columns have 100 elements. I want to add the corresponding elements of Hour to TDate. I tried the following: import pandas

问题 I want to calculate the difference between two datetime.date() dates in years and months. For example; d1 = date(2001,5,1) d2 = date(2012,1,1) d3 = date(2001,1,1) d4 = date(2012,5,1) diff1 = d2 - d1 diff2 = d4 - d3 Desired result: diff1 == 10 years & 8 months. diff2 == 11 years & 4 months. Thanks. 回答1: If you are able to install the excellent dateutil package, you can do this: >>> from dateutil import relativedelta as rdelta >>> from datetime import date >>> d1 = date(2001,5,1) >>> d2 = date

问题 Hi I need some help to understand why this is happening. I have a method to track 'time remaining' in an event program: def get_program_time_budget(self): return self.estimated_duration-self.get_program_duration() All fine when the estimated_duration > self.get_program_duration() but when this goes the other way things get funny. Results are displayed to the user: Estimated 11 hours Allocated 10 hours 55 minutes Remaining 5 minutes When the result goes negative it does this: Estimated 11

问题 I need to check if some number of years have been since some date. Currently I've got timedelta from datetime module and I don't know how to convert it to years. 回答1: You need more than a timedelta to tell how many years have passed; you also need to know the beginning (or ending) date. (It's a leap year thing.) Your best bet is to use the dateutil.relativedelta object, but that's a 3rd party module. If you want to know the datetime that was n years from some date (defaulting to right now),