time

Fixed y axis in Python plotting times in 12 hr format

旧时模样 提交于 2020-01-04 14:13:45
问题 I have this plot but I need the y axis to be fixed to 00:00, 01:00, 02:00, etc all the way up to 12:00. As of now it's only plotting the values I have in the csv on the y axis. the csv is in the following format. How do o get the y axis to be constant and only show 00:00 to 12:00 in 1 hr increments and still have the data plotted correctly? ML INT 0.1 534.15 0:00 ML EXT 0.25 654.23 3:00 ML INT 0.35 743.12 6:30 And the following is the code I have so far. import pandas as pd import matplotlib

How to Delay automatic opening of Modal Dialog box window in JQuery 1.5.x?

穿精又带淫゛_ 提交于 2020-01-04 08:23:14
问题 The following dialog box works nicely when clicked upon: <a href="#" onclick="jQuery('#dialogX').dialog('open'); return false"><? echo __("Under Construction")?></a> The javascript sitting at the bottom of the html triggers the action: jQuery("#dialogX").dialog({bgiframe: true, autoOpen: false, modal: true}); Now, what I would wish, is to have the dialog popup after say 2 seconds (insterad of immediately). I saw the option autoOpen and when setting the value to 2000 instead of false, that

extern auto variable has no initializer

僤鯓⒐⒋嵵緔 提交于 2020-01-04 07:42:41
问题 I need to use a global timestamp (std::chrono::high_resolution_clock::now()) in my c++ program. I declared it in the header file Header.h: #include<chrono> using namespace std; extern auto start; I want to initialize a value in main, so in main.cpp, I did: #include"Header.h" #include<chrono> using namespace std; auto start; int main(){ start = std::chrono::high_resolution_clock::now(); } However, when compiling it, I got: error: declaration of ‘auto start’ has no initializer Can anybody tell

Why is time.sleep pausing early?

﹥>﹥吖頭↗ 提交于 2020-01-04 07:03:58
问题 I'm teaching myself python with the aid of Head First Programming. I thought I might tweak their example more to my liking, but I think I'm missing something about time.sleep. My code is print("Welcome to SuperBeans!") time.sleep(3) answer = input("Do you need a price now? y/n: ") But rather than pausing for three seconds after the welcome message, it waits 3 minutes, then displays both the message and the input request. What am I missing? Additionally, the program seems to hang indefinitely

platform-specific std::chrono::high_resolution_clock::period::num

删除回忆录丶 提交于 2020-01-04 05:53:51
问题 I've noticed that std::chrono::high_resolution_clock::period::num = 1 for every system I've tested. Does there exist any system (embedded, desktop, mobile, or otherwise) where it happens to be some other number? (On such a system, 1 second would not be representable in ticks.) 回答1: There are three implementations of std::chrono::high_resolution_clock that I am aware of: Visual Studio, gcc and clang (when used with libc++). All three of these have nanosecond-precision ( std::chrono::high

Checking when a date has passed - Swift

拈花ヽ惹草 提交于 2020-01-04 05:46:08
问题 Well, the title pretty much says it all. What I am trying to do is check when a date has passed. So, for example let us say that a user is using my app and then they go to bed and check my app in the morning. When my app opens up I need to check if the day has changed at all. Also I don't really need to know this information when the app is terminated or in the background or anything. I just need to know if the date has changed when the app is running and the user is actually interacting with

How do I get the first Monday of a given month in Go?

有些话、适合烂在心里 提交于 2020-01-04 05:22:09
问题 I'm trying to get the first Monday of a given month. Best way I can come up with is to loop through first seven days and return when .Weekday() == "Monday" . Is there a better way to do this? 回答1: By looking at the .Weekday() of the time, you can compute the first Monday. package main import ( "fmt" "time" ) // FirstMonday returns the day of the first Monday in the given month. func FirstMonday(year int, month time.Month) int { t := time.Date(year, month, 1, 0, 0, 0, 0, time.UTC) return (8

Drop row based on time

大兔子大兔子 提交于 2020-01-04 04:32:08
问题 I want to know how to drop row based on time column. My dataframe: df ID Time ID1 9:00:00 ID2 10:00:00 ID3 11:00:00 ID4 12:00:00 ID5 13:00:00 ID6 14:00:00 ID7 15:00:00 ID8 16:00:00 ID9 17:00:00 I want to eliminate row below than 11:00:00 and above 15:00:00, so expected a result: Result ID Time ID3 11:00:00 ID4 12:00:00 ID5 13:00:00 ID6 14:00:00 ID7 15:00:00 I use this code but nothing happens. df = pd.read_csv('data.csv') index_list= df.Time[(df.Time < "09:00:00") & (df.Time > "17:00:00")]

(Delta time) Getting 60 updates a second in java

旧时模样 提交于 2020-01-04 04:27:04
问题 I've seen this code several times. long lastTime = System.nanoTime(); final double ticks = 60D; double ns = 1000000000 / ticks; double delta = 0; The code above takes the System time and stores it to lastTime . The 60 ticks should equate to the number of times to update per second. while(running){ long now = System.nanoTime(); delta += (now - lastTime) / ns; lastTime = now; if(delta >= 1){ tick(); delta--; } It takes now and subtracts lastTime , then converts it to nanoseconds/60. Is there

rand() seeding with time() problem

吃可爱长大的小学妹 提交于 2020-01-04 04:06:07
问题 I'm having difficulty figuring out how to use rand() and seeding it with time() using Xcode. I want to generate random decimal numbers between 0 and 1. The code gives me seemingly random numbers for elements 1 and 2, but element 0 is always somewhere around 0.077. Any ideas why this would be? My code is: #include <stdio.h> #include <stdlib.h> #include <time.h> int main(void) { double array[3]; double rand_max = RAND_MAX; srand((int)time(NULL)); for (int iii = 0; iii < 3; iii++) array[iii] =