synchronized-block

Java synchronize block on same object in different methods

 ̄綄美尐妖づ 提交于 2021-02-04 16:22:25
问题 I am trying to understand the concept of synchronized blocks in java. As of the documents that I have read, I understood that if we acquire a lock ( synchronized block using an instance variable ) then we cannot acquire a synchronized lock on same object in that class. But when I tried practically using the following snippet I found that my understanding is going wrong. I.e I am able to acquire lock (synchronized block on same instance variable) in two different methods at the same time. When

What is the difference between a synchronized method and synchronized block in Java? [duplicate]

别来无恙 提交于 2019-12-27 12:23:35
问题 This question already has answers here : Is there an advantage to use a Synchronized Method instead of a Synchronized Block? (23 answers) Closed 2 years ago . What is the difference between a synchronized method and synchronized block in Java ? I have been searching the answer on the Net, people seem to be so unsure about this one :-( My take would be there is no difference between the two, except that the synch block might be more localized in scope and hence the lock will be of lesser time

What is the difference between a synchronized method and synchronized block in Java? [duplicate]

ⅰ亾dé卋堺 提交于 2019-12-27 12:23:27
问题 This question already has answers here : Is there an advantage to use a Synchronized Method instead of a Synchronized Block? (23 answers) Closed 2 years ago . What is the difference between a synchronized method and synchronized block in Java ? I have been searching the answer on the Net, people seem to be so unsure about this one :-( My take would be there is no difference between the two, except that the synch block might be more localized in scope and hence the lock will be of lesser time

What is the difference between a synchronized method and synchronized block in Java? [duplicate]

北慕城南 提交于 2019-12-27 12:21:29
问题 This question already has answers here : Is there an advantage to use a Synchronized Method instead of a Synchronized Block? (23 answers) Closed 2 years ago . What is the difference between a synchronized method and synchronized block in Java ? I have been searching the answer on the Net, people seem to be so unsure about this one :-( My take would be there is no difference between the two, except that the synch block might be more localized in scope and hence the lock will be of lesser time

A mutex blocks only the main thread when it reaches its call with the @synchronized directive

时光毁灭记忆、已成空白 提交于 2019-12-25 09:00:35
问题 I'm building a multithreaded application, from which more than one thread can write to an sqlite3 database including the main thread. I declared a static public variable to be used for the mutex: @implementation Application #pragma mark - #pragma mark Static Initializer static NSString * SubmitChangesLock = nil; + (void)initialize { [super initialize]; SubmitChangesLock = [[NSString alloc] initWithString:@"Submit-Changes-Lock"]; } + (NSString *)submitChangesLock { return SubmitChangesLock; }

AtomicBoolean vs synchronized block

拥有回忆 提交于 2019-12-21 11:04:48
问题 I was trying to cut thread contention in my code by replacing some synchronized blocks with AtomicBoolean . Here's an example with synchronized : public void toggleCondition() { synchronized (this.mutex) { if (this.toggled) { return; } this.toggled = true; // do other stuff } } And the alternative with AtomicBoolean : public void toggleCondition() { if (!this.condition.getAndSet(true)) { // do other stuff } } Taking advantage of AtomicBoolean 's CAS property should be way faster than relying

In java, return value within synchronized block seems like bad style. Does it really matter?

本秂侑毒 提交于 2019-12-18 12:43:55
问题 I have a Collections.synchronizedList of WeakReference, _components; I wrote something like the following, expecting the complier to complain: public boolean addComponent2(Component e) { synchronized (_components) { return _components.add(new WeakReference<Component>(e)); } } But the compiler is perfectly satisfied. Note that List.add() returns TRUE. So ok, any exit from a synchronized block releases the lock, but doesn't this LOOK strange? It's kind of like a "hole" in the block, similar to

What is the difference between synchronized on lockObject and using this as the lock?

霸气de小男生 提交于 2019-12-17 04:18:31
问题 I know the difference between synchronized method and synchronized block but I am not sure about the synchronized block part. Assuming I have this code class Test { private int x=0; private Object lockObject = new Object(); public void incBlock() { synchronized(lockObject) { x++; } System.out.println("x="+x); } public void incThis() { // same as synchronized method synchronized(this) { x++; } System.out.println("x="+x); } } In this case what is the difference between using lockObject and

What is the difference between synchronized on lockObject and using this as the lock?

試著忘記壹切 提交于 2019-12-17 04:18:06
问题 I know the difference between synchronized method and synchronized block but I am not sure about the synchronized block part. Assuming I have this code class Test { private int x=0; private Object lockObject = new Object(); public void incBlock() { synchronized(lockObject) { x++; } System.out.println("x="+x); } public void incThis() { // same as synchronized method synchronized(this) { x++; } System.out.println("x="+x); } } In this case what is the difference between using lockObject and

What is the difference between synchronized on lockObject and using this as the lock?

孤者浪人 提交于 2019-12-17 04:18:04
问题 I know the difference between synchronized method and synchronized block but I am not sure about the synchronized block part. Assuming I have this code class Test { private int x=0; private Object lockObject = new Object(); public void incBlock() { synchronized(lockObject) { x++; } System.out.println("x="+x); } public void incThis() { // same as synchronized method synchronized(this) { x++; } System.out.println("x="+x); } } In this case what is the difference between using lockObject and