sympy

I've tried to create a Sympy continuous random variable with a Rician distribution. With thanks to help from an earlier question , it seems that the best approach is to subclass SingleContinuousDistribution . I've implemented a distribution that appears to be in agreement between Wikipedia and Scipy , however I am not getting the same results as Scipy. What follows is code that implements the random variable, extracts its symbolic distribution and converts it to a Numpy representation through lambdify then plots my distribution against the PDF of the Scipy rician distribution. from sympy

I want to get latex output from a sympy expression without calculating the expression. For instance if I do latex((2+3)/7) the output would be 5/7 (with latex), but what I am after is for it to just output (2+3)/7 with latex. Like this: \frac{2+3}{7} You can manually adjust the long_frac_ratio long_frac_ratio: The allowed ratio of the width of the numerator to the width of the denominator before we start breaking off long fractions. The default value is 2. >>> latex(e,long_frac_ratio=3) '\\frac{2 + 3}{7}' You can try to sympify the expression with keyword evaluate=False : >>> latex(S('(2+3)/7'

I have a python function with variable number of arguments: F(x1, x2, ... , xN) I want to automatically generate N functions representing the derivatives of F with respect to each argument. F'_1 = dF/dx1 F'_2 = dF/dx2 ... F'_N = dF/dxN For example, I be able to give both F(x1) = sin(x1) and F(x1, x2) = sin(x1) * cos(x2) and get all the derivatives automatically. Edit2: If function F was 2 variable (fixed number of arguments), I could use def f(x,y): return sin(x)*cos(y) from sympy import * x, y = symbols('x y') f_1 = lambdify((x,y), f(x,y).diff(x)) The trick is to use inspect.getargspec to get

My website runs this Python script that would be way more optimized if Cython is used. Recently I needed to add Sympy with Lambdify , and this is not going well with Cython. So I stripped the problem to a minimum working example. In the code, I have a dictionary with string keys with values that are lists. I would like to use these keys as variables. In the following simplified example, there's only 1 variable, but generally I need more. Please check the following example: import numpy as np from sympy.parsing.sympy_parser import parse_expr from sympy.utilities.lambdify import lambdify,

I have tried to be diligent in looking through documentation and am coming up empty. I am trying to factor or eliminate terms in a expression to matrix form. My problem appears to differ from polynomial factoring (as I plan to implement a function phi(x,y,z) = a_1 + a_2*x + a_3*y + a_4*z ) import sympy from sympy import symbols, pprint from sympy.solvers import solve phi_1, phi_2, x, a_1, a_2, L = symbols("phi_1, phi_2, x, a_1, a_2, L") #Linear Interpolation function: phi(x) phi = a_1 + a_2*x #Solve for coefficients (a_1, a_2) with BC's: phi(x) @ x=0, x=L shape_coeffs = solve([Eq(phi_1, phi)