swiftui

问题 I want to change the color of the selected row. As you may see, by default it has this light gray color. I have no idea how to do that since I have found no way to access this row at all. Is there any way to do that? Demo code: struct ContentView: View { var data = Array(0...20).map { "\($0)" } @State private var selected = 0 var body: some View { VStack { Picker("", selection: $selected) { ForEach(0 ..< data.count) { Text(data[$0]) } } } } } A UIKit answer would also be welcomed since I have

问题 I want to remove the NavigationTitle Space without removing the back button. I have already tried this: .navigationBarItems(trailing: NavigationLink(destination: Preferences(viewModel: viewModel).navigationBarHidden(true)) { Image(systemName: "gear") .font(.title2) } ) but that removes the back button as well. 回答1: Standard Back button cannot be shown without navigation bar, because it is navigation item, so part of navigation bar. I assume you just need transparent navigation bar. Here is

问题 I want to remove the NavigationTitle Space without removing the back button. I have already tried this: .navigationBarItems(trailing: NavigationLink(destination: Preferences(viewModel: viewModel).navigationBarHidden(true)) { Image(systemName: "gear") .font(.title2) } ) but that removes the back button as well. 回答1: Standard Back button cannot be shown without navigation bar, because it is navigation item, so part of navigation bar. I assume you just need transparent navigation bar. Here is

问题 I want to remove the NavigationTitle Space without removing the back button. I have already tried this: .navigationBarItems(trailing: NavigationLink(destination: Preferences(viewModel: viewModel).navigationBarHidden(true)) { Image(systemName: "gear") .font(.title2) } ) but that removes the back button as well. 回答1: Standard Back button cannot be shown without navigation bar, because it is navigation item, so part of navigation bar. I assume you just need transparent navigation bar. Here is

问题 I am making a mining tapping game and I want to display a hammer wherever the user taps. I mean, wherever the user taps the hammer image will stay on for one second. Is there a way to do it? My example code is below: struct Level1: View { @State var tapScore = 0 @State var showingMinedHammer = false func showMinedHammer() { self.showingMinedHammer = true DispatchQueue.main.asyncAfter(deadline: .now() + 1) { self.showingMinedHammer = false } } func mine() { tapScore += 1 showMinedHammer() }

问题 Is there a way to build UI elements in SwiftUI inside scroll view with bottom Alignment? My use case: I have a screen where the screen has Spacer ( What ever is left after allocating below elements ) LogoView Spacer() - 30 Some Text - 4/5 lines Spacer() - 50 (this will be calculated off of GR size Height) HStack with Two Button - This should be pinned to bottom of view / ScrollView I would like to know how Can I pin the HStack view to ScrollView Bottom I've replicated my setup and reproduced

问题 Is there a way to build UI elements in SwiftUI inside scroll view with bottom Alignment? My use case: I have a screen where the screen has Spacer ( What ever is left after allocating below elements ) LogoView Spacer() - 30 Some Text - 4/5 lines Spacer() - 50 (this will be calculated off of GR size Height) HStack with Two Button - This should be pinned to bottom of view / ScrollView I would like to know how Can I pin the HStack view to ScrollView Bottom I've replicated my setup and reproduced

问题 I'm looking for a way to check the state of the option-key in SwiftUI on macOS. I.e. depending on whether the option key is pressed or not I want to perform different actions in the .onTapGesture closure. 回答1: macOS-only SwiftUI has .modifiers modifier to specify EventModifiers , so your case is covered like in below example: Rectangle() .fill(Color.yellow) .frame(width: 100, height: 40) .gesture(TapGesture().modifiers(.option).onEnded { print("Do anyting on OPTION+CLICK") }) .onTapGesture {

问题 I'm looking for a way to check the state of the option-key in SwiftUI on macOS. I.e. depending on whether the option key is pressed or not I want to perform different actions in the .onTapGesture closure. 回答1: macOS-only SwiftUI has .modifiers modifier to specify EventModifiers , so your case is covered like in below example: Rectangle() .fill(Color.yellow) .frame(width: 100, height: 40) .gesture(TapGesture().modifiers(.option).onEnded { print("Do anyting on OPTION+CLICK") }) .onTapGesture {

问题 I'm looking for a way to check the state of the option-key in SwiftUI on macOS. I.e. depending on whether the option key is pressed or not I want to perform different actions in the .onTapGesture closure. 回答1: macOS-only SwiftUI has .modifiers modifier to specify EventModifiers , so your case is covered like in below example: Rectangle() .fill(Color.yellow) .frame(width: 100, height: 40) .gesture(TapGesture().modifiers(.option).onEnded { print("Do anyting on OPTION+CLICK") }) .onTapGesture {