swap

问题 I need to swap the values of 2 arrays in a function. The problem is I can change anything in the main, just the function itself. It should recive 2 integer arrays, and swap those. The problem is, that I don't know the size of the arrays, and for my understading they can even be in diffrent sizes. Trying this code: int main() { int size = 4; //Please notice that I'm using this only to print the array int a[] = {1,2,3,4}; int b[] = {5,6,7,8}; printArr(a,"a",size); printArr(b,"b",size);

问题 The C++ standard guarantees that std::swap will throw no exception. However, what if an object to swap throws an exception during swapping? Next, how should the caller find an exception has happened? and what measures should the caller take? PS: It is very common that a constructor throws an exception. struct A { A(const A&) { throw 1; } A& operator =(const A&) { throw 2; return *this; } }; int main() { A a1, a2; std::swap(a1, a2); // An exception happened, but the caller doesn't know. // How

问题 The C++ standard guarantees that std::swap will throw no exception. However, what if an object to swap throws an exception during swapping? Next, how should the caller find an exception has happened? and what measures should the caller take? PS: It is very common that a constructor throws an exception. struct A { A(const A&) { throw 1; } A& operator =(const A&) { throw 2; return *this; } }; int main() { A a1, a2; std::swap(a1, a2); // An exception happened, but the caller doesn't know. // How

问题 The C++ standard guarantees that std::swap will throw no exception. However, what if an object to swap throws an exception during swapping? Next, how should the caller find an exception has happened? and what measures should the caller take? PS: It is very common that a constructor throws an exception. struct A { A(const A&) { throw 1; } A& operator =(const A&) { throw 2; return *this; } }; int main() { A a1, a2; std::swap(a1, a2); // An exception happened, but the caller doesn't know. // How

问题 I am using 64-bit Linux and Java JVM. I want to confirm if the memory used by JVM is smaller than physical memory size of the machine, there will be no disk memory swap by OS? 回答1: No, that's not necessarily true. Physical memory is shared by all processes, as well as by a bunch of other kernel things (e.g. the disk cache). So the amount of virtual memory used by your application is not the only consideration. 回答2: You can start your java application with the jvm argument -Xmx512m wich will

问题 #include<stdio.h> void swap(int *a,int *b){ int p=*b; *b=*a; *a=p; /*int *p=b; b=a; a=p; */ } int main(){ int a,b; scanf("%d %d",&a,&b); swap(&a,&b); printf("%d %d",a,b); } Above is the code. If I put 3 5 as an input, then it should swap its values, and 5 3 should come out as an output. I got my answer by trying int p=*b thing However I also tried commented part, but it didn't work. So, I checked their address in swap and in main. In swap int *a and int *b their address changed However, when

问题 In C I have to write a bubble sort function that swaps the nodes and not the values of a LinkedList, but I'm unable to accomplish it. Here is the code (As you can see the order is not correct): #include <stdio.h> #include <malloc.h> // malloc, free #include <stddef.h> // NULL // defining 'int' as data_t typedef int data_t; typedef struct node_s { data_t data; struct node_s* next; } node_t; node_t** list_new() { node_t** list = malloc(sizeof **list); if (!list) return NULL; *list = NULL;

问题 In C I have to write a bubble sort function that swaps the nodes and not the values of a LinkedList, but I'm unable to accomplish it. Here is the code (As you can see the order is not correct): #include <stdio.h> #include <malloc.h> // malloc, free #include <stddef.h> // NULL // defining 'int' as data_t typedef int data_t; typedef struct node_s { data_t data; struct node_s* next; } node_t; node_t** list_new() { node_t** list = malloc(sizeof **list); if (!list) return NULL; *list = NULL;

问题 Consider the following bubble sort program: arr = map(int, raw_input().split(' ')) print "Unsorted: \n{arr_name}".format(arr_name = arr) for j in range(len(arr) - 1, 0, -1): for i in range(j): if (arr[i] > arr[i + 1]): arr[i], arr[i + 1] = arr[i +1], arr[i] print "Sorted: \n{arr_name}".format(arr_name = arr) Usually a temp variable is used for sorting and that would be mean a space complexity of 0(1) . But my understanding is that, tuple swap is only a reassignment of identifiers to objects

问题 I am trying to write a code in C that reads n words from a file and modifies the content word by word. The program will count the number of vowels in each word. If the number of vowels in the current word is even, the program will swap the vowels in pair of two (no swapping in case of odd number), then it will attach the number of vowels to the word. For example if the word is apple , the modified word will look like eppla_2vow . My problem is that I don't quite know how am I supposed to make