subtraction

R subtracting 1 month from today's date gives NA

喜你入骨 提交于 2020-04-27 06:01:48
问题 I have a script in which I subset my data according to some set time periods and wanted to subset all the records that had occurred in the last month. However if I try to subtract one month from today's date it yields an NA: > today <- Sys.Date() > today [1] "2017-03-29" > today - months(1) [1] NA I do have lubridate loaded but I think this calculation is being performed with base R. If I subtract 2 or more months it works fine: > today - months(2) [1] "2017-01-29" > today - months(3) [1]

Date interval sum and subtraction in Java

安稳与你 提交于 2020-02-23 10:14:02
问题 I'm looking for a library or helper class in Java that would allow me to perform date interval sum and subtractions. For example, lets's say I have the following date intervals: A = ["2015-01-01 00:00", "2015-01-20 00:00"] B = ["2015-01-05 00:00", "2015-01-10 00:00"] C = ["2015-01-11 00:00", "2015-01-14 00:00"] D = ["2015-01-19 00:00", "2015-01-25 00:00"] 1 A 20 |----------------------------------| |---------| |----------| |------------| 5 B 10 11 C 14 19 D 25 And let's say I'd like to

Date interval sum and subtraction in Java

旧城冷巷雨未停 提交于 2020-02-23 10:12:30
问题 I'm looking for a library or helper class in Java that would allow me to perform date interval sum and subtractions. For example, lets's say I have the following date intervals: A = ["2015-01-01 00:00", "2015-01-20 00:00"] B = ["2015-01-05 00:00", "2015-01-10 00:00"] C = ["2015-01-11 00:00", "2015-01-14 00:00"] D = ["2015-01-19 00:00", "2015-01-25 00:00"] 1 A 20 |----------------------------------| |---------| |----------| |------------| 5 B 10 11 C 14 19 D 25 And let's say I'd like to

How to subtract or add two hexadecimal value in java

杀马特。学长 韩版系。学妹 提交于 2020-02-22 07:44:29
问题 Is there a way of calculating two hexadecimal value without converting it to int? for example: String sHex = "f7c0"; String bHex = "040000000"; 回答1: Hexadecimal values are integers - just represented in hex instead of decimal. Can't you just do this? int sHex = 0xf7c0; int bHex = 0x040000000; If not, then you actually meant: String sHex = "f7c0"; String bHex = "040000000"; In which case, the fastest way to do this is still by converting them to integers, using something like Integer.parseInt

How to subtract or add two hexadecimal value in java

99封情书 提交于 2020-02-22 07:44:25
问题 Is there a way of calculating two hexadecimal value without converting it to int? for example: String sHex = "f7c0"; String bHex = "040000000"; 回答1: Hexadecimal values are integers - just represented in hex instead of decimal. Can't you just do this? int sHex = 0xf7c0; int bHex = 0x040000000; If not, then you actually meant: String sHex = "f7c0"; String bHex = "040000000"; In which case, the fastest way to do this is still by converting them to integers, using something like Integer.parseInt

Adding a float to an integer using a method (not an operator) [duplicate]

天大地大妈咪最大 提交于 2020-01-25 06:47:09
问题 This question already has answers here : Difference between a+b and a.__add__(b) (1 answer) Python: __add__ and +, different behavior with float and integer (1 answer) Closed 16 days ago . I was expecting __add__ to work, but that's obviously not the case (in Python 3.8.0 at least): >>> 10 .__add__(5.5) NotImplemented >>> 10 .__radd__(5.5) NotImplemented The other way around works: >>> 5.5 .__add__(10) 15.5 >>> 5.5 .__radd__(10) 15.5 Why doesn't the first code work? Is there a good reason

How to subtract two iterables in python

大城市里の小女人 提交于 2020-01-17 04:48:25
问题 There are two lists A and B. I want to get all the elements in A but not in B. Any efficient way to do this? 回答1: You can use a list comprehension to do this for you. filtered = [i for i in A if i not in B] If the lists are both large, you might want to consider creating a set from B for faster membership lookup setB = set(B) filtered = [i for i in A if i not in setB] This solution maintains the order of A and any duplicates that exist in A . 回答2: i always like to use sets for this: set(A) -

subtracting a specific condition for each measure

╄→尐↘猪︶ㄣ 提交于 2020-01-15 11:24:11
问题 I have a data frame which looks like following and it continues up to subject 22 Beta is the dependent measure. Subject ROI Block Condition Beta 1 motor1 1 nopred_noom -2.8653 1 motor1 1 pred_noom -2.9126 1 motor1 1 nopred_om -2.8688 1 motor1 1 pred_om -2.9098 1 motor1 1 null -2.7717 1 motor1 2 nopred_noom -2.2382 1 motor1 2 pred_noom -2.0583 1 motor1 2 nopred_om -2.2207 1 motor1 2 pred_om -2.1928 1 motor1 2 null -2.1166 1 motor1 3 nopred_noom -1.5992 1 motor1 3 pred_noom -1.5493 1 motor1 3

subtracting a specific condition for each measure

左心房为你撑大大i 提交于 2020-01-15 11:24:07
问题 I have a data frame which looks like following and it continues up to subject 22 Beta is the dependent measure. Subject ROI Block Condition Beta 1 motor1 1 nopred_noom -2.8653 1 motor1 1 pred_noom -2.9126 1 motor1 1 nopred_om -2.8688 1 motor1 1 pred_om -2.9098 1 motor1 1 null -2.7717 1 motor1 2 nopred_noom -2.2382 1 motor1 2 pred_noom -2.0583 1 motor1 2 nopred_om -2.2207 1 motor1 2 pred_om -2.1928 1 motor1 2 null -2.1166 1 motor1 3 nopred_noom -1.5992 1 motor1 3 pred_noom -1.5493 1 motor1 3

Date subtraction in JavaScript

橙三吉。 提交于 2020-01-14 09:46:05
问题 I have two text boxes which accept Start Date and End Date respectively, in format YYYY/MM/DD. I need to alert the user if he selects an end date that exceeds the start date by 50 days. Here's what I have so far: var startDate = new Date(document.getElementsByName('MYSTARTDATE').value); var endDate = new Date(document.getElementsByName('MYENDDATE').value); if ((endDate - startDate) > 50) { alert('End date exceeds specification'); return false; } Just as an example, when I select Start Date as