substitution

问题 I have a data frame like below. I would like to find unique rows (uniqueness). But in this data I have 'NA'. I like if all value in one row with NA value is the same with other rows (like rows: 1,2,5) I want to ignore it, but if not same (like rows : 2,4) I like to keep it as unique row. For example, in rows 1 ,2 and 6 all values except NA are the same so because NA can be value '1 and 3' I like to remove this row and just keep row 2. Also, in row 6 values 2 and 3 (exclude NA) are the same as

问题 I need to use a variable in my SQL query. This is my script: function SQLQueryWriteToFile([string]$SQLquery, [string]$extractFile, [string]$facility) { #create sql connection to connect to the sql DB $sqlConnection = New-Object System.Data.SqlClient.SqlConnection $sqlConnection.ConnectionString = "Server=blah;Database=blah_Test;User ID=blah;Password=blah" $sqlConnection.Open() #Create a SqlCommand object to define the query $sqlCmd = New-Object System.Data.SqlClient.SqlCommand $sqlCmd

问题 I know similar questions have been asked, but this is kind of a trivial case. Given a text file endcoded with a substitution cipher, I need to decode it using python. I am not given any examples of correctly deciphered words. The relationship is 1-to-1 and case doesn't make a difference. Also, punctuation isn't changed and spaces are left where they are. I don't need help with the code as much as I need help with a general idea of how this could be done in code. My main approaches involve:

问题 I know similar questions have been asked, but this is kind of a trivial case. Given a text file endcoded with a substitution cipher, I need to decode it using python. I am not given any examples of correctly deciphered words. The relationship is 1-to-1 and case doesn't make a difference. Also, punctuation isn't changed and spaces are left where they are. I don't need help with the code as much as I need help with a general idea of how this could be done in code. My main approaches involve:

问题 I know similar questions have been asked, but this is kind of a trivial case. Given a text file endcoded with a substitution cipher, I need to decode it using python. I am not given any examples of correctly deciphered words. The relationship is 1-to-1 and case doesn't make a difference. Also, punctuation isn't changed and spaces are left where they are. I don't need help with the code as much as I need help with a general idea of how this could be done in code. My main approaches involve:

问题 I'm trying to write a Python function that replaces instances of text surrounded with curly braces with the contents of the braces, while leaving empty brace-pairs alone. For example: foo {} bar {baz} would become foo {} bar baz . The pattern that I've created to match this is {[^{}]+} , i.e. some text that doesn't contain curly braces (to prevent overlapping matches) surrounded by a set of curly braces. The obvious solution is to use re.sub with my pattern, and I've found that I can

问题 I came pretty close to solving my problem with this answer given by "barry houdini" But I run into problems incorporating it to my needs. =SUMPRODUCT(VALUE(0&SUBSTITUTE(A1:A8,"*",""))) Edit #3 - @Rory came with a very good answer to solving my problem. But what I hadn't thought about was if you enter a non-numerical value inside a cell, then the formula returns an error. So I would really like to tweak the following formula to ignore the letter "x" , or non-numerical values (if that's easier)

问题 I'm looking for an 'efficient' way to iterate through a dictionary, and replace any key or value that starts with the term 'var'. For example, if I have this: data = { "user_id": "{{var_user_id}}", "name": "bob", "{{var_key_name}}": 4 } and I have this dict of variable values: variables = { "user_id": 10, "key_name": "orders_count" } Then I'd like my final data dict to look like this: data = { "user_id": 10, "name": "bob", "orders_count": 4 } 回答1: Since you're treating it like a text template

问题 I don't understand the logic in the functioning of the scape operator \ in python regex together with r' of raw strings. Some help is appreciated. code: import re text=' esto .es 10 . er - 12 .23 with [ and.Other ] here is more ; puntuation' print('text0=',text) text1 = re.sub(r'(\s+)([;:\.\-])', r'\2', text) text2 = re.sub(r'\s+\.', '\.', text) text3 = re.sub(r'\s+\.', r'\.', text) print('text1=',text1) print('text2=',text2) print('text3=',text3) The theory says: backslash character ('\') to

问题 I don't understand the logic in the functioning of the scape operator \ in python regex together with r' of raw strings. Some help is appreciated. code: import re text=' esto .es 10 . er - 12 .23 with [ and.Other ] here is more ; puntuation' print('text0=',text) text1 = re.sub(r'(\s+)([;:\.\-])', r'\2', text) text2 = re.sub(r'\s+\.', '\.', text) text3 = re.sub(r'\s+\.', r'\.', text) print('text1=',text1) print('text2=',text2) print('text3=',text3) The theory says: backslash character ('\') to