subsequence

问题 I'v a sequence of integer number [A1, A2, A3.....AN] I'm trying to count all sub-sequences which contain at most K unique numbers. For Example: Given sequence:: [2, 3, 3, 7, 5] and K = 3 All sub-sequences are: [], [2],[3],[3],[7],[5], [2, 3],[2, 3],[2, 7],[2, 5],[3, 3],[3, 7],[3, 5],[3, 7],[3, 5],[7, 5], [2, 3, 3],[2, 3, 7],[2, 3, 5],[2, 3, 7],[2, 3, 5],[2, 7, 5],[3, 3, 7],[3, 3, 5],[3, 7, 5],[3, 7, 5], [2, 3, 3, 7],[2, 3, 3, 5],[2, 3, 7, 5],[2, 3, 7, 5],[3, 3, 7, 5], [2, 3, 3, 7, 5] I need

问题 Hello I am stuck with my homework which is: given sequence of integers, find the longest subsequence whose elements are ordered in an increasing order. Up to k exceptions that means at most k times, the next number in the sequence is smaller than previous one. Output should be the length of the longest such subsequence. I found many examples of finding LIS, even one with one change allowed, but I don't know how to check with k changes. Here is the link to post with one change: https://www

问题 It just occurred to me that when working with subsequences in Swift, func suffix(from: Int) seems to be identical to just dropFirst(_:) (Obviously, you just change the input value from say "3" to "7" in the case of an array of length "10".) Just to repeat that. So: of course, for an array of say length ten. What I mean is func suffix(from: Int) with "2" would be the same as dropFirst(_:) with "8" , for example. Similarly upTo / through seem to be identical to dropLast(_:) Other than

问题 Assuming my table is WITH `sample_project.sample_dataset.table` AS ( SELECT 'user1' user, 2 sequence, 'T1' ts UNION ALL SELECT 'user1', 2, 'T2' UNION ALL SELECT 'user1', 1, 'T3' UNION ALL SELECT 'user1', 1, 'T4' UNION ALL SELECT 'user1', 3, 'T5' UNION ALL SELECT 'user1', 2, 'T6' UNION ALL SELECT 'user1', 3, 'T7' UNION ALL SELECT 'user1', 3, 'T8' ) Can I find Subsequence of Integers available in sequence column without using STRING_AGG and REGEX OR JOIN operations ? This is to make query more

问题 I'm looking to explore different algorithms, both recursive and dynamic programming, that checks if one arrayA is a subsequence of arrayB. For example, arrayA = [1, 2, 3] arrayB = [5, 6, 1, 7, 2, 9, 3] thus, arrayA is indeed a subsequence of arrayB. I've tried a few different searches, but all I can seem to find is algorithms to compute the longest increasing subsequence. 回答1: Since you must match all elements of arrayA to some elements of arrayB , you never need to backtrack . In other words

问题 This is my code It passes for few cases but not for all, for eg. number of elements n = 6 elements a[n] = {5,5,10,100,10,5} and sum = 25 the output is 15, but output should be 25 (5 + 10 + 10) click here to see its working in IDE #include<bits/stdc++.h> #define ll long long int using namespace std; int main(){ int n; ll sum; vector<ll> v; cin>>n; ll a[n]; for(int i=0;i<n;i++){ cin>>a[i]; } cin>>sum; ll ans = 0; ll inc = a[0]; ll exc = 0; ll prev = 0; for(int i=1;i<n;i++){ prev = inc; inc =

问题 I have a list of elements (namely PowerPoint slides) which I need to reorder in the minimal possible steps. Each slide has an integer unique key (namely SlideID ), and I can produce the required order of keys really fast, but actually moving a slide (executing a move) is relatively slow, as PowerPoint updates who-knows-what when it's called, therefore I try to execute the minimum amount of move commands. So what I have is the list of keys in the original and the desired order, like: int[]

问题 This question was asked in the Google programming interview. I thought of two approaches for the same: Find all the subsequences of length. While doing so compute the sum and of the two elements and check if it is equal to k. If ye, print Yes, else keep searching. This is a brute Force approach. Sort the array in non-decreasing order. Then start traversing the array from its right end. Say we have the sorted array, {3,5,7,10} and we want the sum to be 17. We will start from element 10, index

问题 This question was asked in the Google programming interview. I thought of two approaches for the same: Find all the subsequences of length. While doing so compute the sum and of the two elements and check if it is equal to k. If ye, print Yes, else keep searching. This is a brute Force approach. Sort the array in non-decreasing order. Then start traversing the array from its right end. Say we have the sorted array, {3,5,7,10} and we want the sum to be 17. We will start from element 10, index

问题 Given a string consisting of only vowels, find the longest subsequence in the given string such that it consists of all five vowels and is a sequence of one or more a’s, followed by one or more e’s, followed by one or more i’s, followed by one or more o’s and followed by one or more u’s. If there is more than one longest subsequence, print any one. QUESTION: can u pls show how u would add memoization to soln below/show how to solve using dp? I've seen how to solve recursively (below). I'm