subdirectory

Is there a way to list all subdirectories in a given directory path in C? I was hoping I would be able to do it with the stat() function but it only works on files. CodingLab stat works on directories too. #include <sys/types.h> #include <dirent.h> #include <sys/stat.h> #include <unistd.h> int num_dirs(const char* path) { int dir_count = 0; struct dirent* dent; DIR* srcdir = opendir(path); if (srcdir == NULL) { perror("opendir"); return -1; } while((dent = readdir(srcdir)) != NULL) { struct stat st; if(strcmp(dent->d_name, ".") == 0 || strcmp(dent->d_name, "..") == 0) continue; if (fstatat

At first I wanted to ask "What is the maximum allowed sub-folder for a windows OS" But then I figured maybe my web hosting provider isn't on windows but on linux or something else. So I'm asking what are the possible maximum allowed sub-folder for all major OS that a Web Hosting Provider would usually use. (Would it be safe to say Linux, Mac, or Windows?) Then again, based on your experiences, do web hosting sites create a limit to the number of subfolders we can make? (Why this? Because I want each user to have their very own folder for easy access to their images. Would that be ok? Or is it

I am attempting to create an array of URLs for all of the resources in a sub-directory in my iOS app. I can not seem to get to the correct path, I want to be able to retrieve the URLs even if I do not know the names (i.e. I don't want to hard code the file names into the code). Below is a screen shot of the hierarchy, I am attempting to get all the files in the 'test' folder: Any help is greatly appreciated, I have attempted to use file manager and bundle main path but to no joy so far. This is the only code I have currently: let fileManager = FileManager.default let path = Bundle.main.urls

I have already gone through some previous threads: How do I set subdirectory in nginx with Django how to deploy django under a suburl behind nginx Serving flask app on subdirectory nginx + uwsgi The basic lesson is that you should only need to configure your site(s-available) to achieve this. I have now tried various permutations of server { listen 80; server_name www.example.com; location = /favicon.ico { access_log off; log_not_found off; } location /static/ { root /path/to/project; } location /project/ { root /path/to/project; include /etc/nginx/uwsgi_params; uwsgi_param SCRIPT_NAME

I am trying to extract a folder (call it Project1 ) from an existing Mercurial Repo (call in MainRepo ) using the Convert extension for Mercurial to Mercurial conversion. I have followed the methods described by Mercurial developers (and elsewhere on the web) under Windows XP: C:\MainRepo>echo include Project1 > ~myfilemap C:\MainRepo>echo rename Project1 . >> ~myfilemap C:\MainRepo>hg convert --filemap ~myfilemap . C:\Project1Repo C:\MainRepo>cd \Project1Repo C:\Project1Repo>hg update This creates the new repo (Project1Repo) with the Mercurial folder/files in place. But it does not: 1) Carry

I have a program to zip all the contents in a folder. I did not write this code but I found it somewhere online and I am using it. I intend to zip a folder for example say, C:/folder1/folder2/folder3/ . I want to zip folder3 and all its contents in a file say folder3.zip. With the below code, once i zip it, the contents of folder3.zip wil be folder1/folder2/folder3/and files. I do not want the entire path to be zipped and i only want the subfolder im interested to zip (folder3 in this case). I tried some os.chdir etc, but no luck. def makeArchive(fileList, archive): """ 'fileList' is a list of