subclass

Python print isn't using __repr__ , __unicode__ or __str__ for my unicode subclass when printing. Any clues as to what I am doing wrong? Here is my code: Using Python 2.5.2 (r252:60911, Oct 13 2009, 14:11:59) >>> class MyUni(unicode): ... def __repr__(self): ... return "__repr__" ... def __unicode__(self): ... return unicode("__unicode__") ... def __str__(self): ... return str("__str__") ... >>> s = MyUni("HI") >>> s '__repr__' >>> print s 'HI' I'm not sure if this is an accurate approximation of the above, but just for comparison: >>> class MyUni(object): ... def __new__(cls, s): ... return

I'm implementing an object that is almost identical to a set, but requires an extra instance variable, so I am subclassing the built-in set object. What is the best way to make sure that the value of this variable is copied when one of my objects is copied? Using the old sets module, the following code worked perfectly: import sets class Fooset(sets.Set): def __init__(self, s = []): sets.Set.__init__(self, s) if isinstance(s, Fooset): self.foo = s.foo else: self.foo = 'default' f = Fooset([1,2,4]) f.foo = 'bar' assert( (f | f).foo == 'bar') but this does not work using the built-in set module.

Here's what I'd like to do: class A { String string static constraints = { string(maxSize:100) } } class B extends A { static constraints = { string(url:true) } } So class A should have some constraints and B should have the same plus additional constraints on the same property. I couldn't get that to work though and I can imagine that it would clash with the Table-per-Hierarchy concept. So I tried to work around that problem by introducing a Command object with class B's constraints which can be validated in the constructor of class B. However it seems that Command objects can only be used

I currently have a class called Polynomial, The initialization looks like this: def __init__(self, *termpairs): self.termdict = dict(termpairs) I'm creating a polynomial by making the keys the exponents and the associated values are the coefficients. To create an instance of this class, you enter as follows: d1 = Polynomial((5,1), (3,-4), (2,10)) which makes a dictionary like so: {2: 10, 3: -4, 5: 1} Now, I want to create a subclass of the Polynomial class called Quadratic. I want to call the Polynomial class constructor in the Quadratic class constructor, however im not quite sure how to do

I've written some code in VBA to subclass a userform so that ultimately I can intercept WM_TIMER messages being dispatched to it. I'm doing this instead of specifying a TIMERPROC, as it allows me to use VBAs own error handling and calling methods to run callback functions. I'm using a userform rather than Application.hWnd because: I don't have to filter for my vs Excel/the host application's messages There are far too many messages going through Application.hWnd to be able to subclass it in a slow interpreted language like VBA When code execution is interrupted (pressing the stop button, or

I'm making an iOS app in swift, and I'm trying to make a collectionView programmatically. I want to use my own subclass of UICollectionReusableView as a header for the collectionview, because I need some buttons and a strechable image in the header. SupView is the UICollectionReusableView. override func viewDidLoad() { super.viewDidLoad() let layout = UICollectionViewFlowLayout() layout.headerReferenceSize = CGSizeMake(self.view.frame.width, 200) someView = SupView(frame: CGRectMake(0, 0, view.frame.width, 200)) collectionView = UICollectionView(frame: self.view.frame, collectionViewLayout:

In ES6, is there a way to call a parent constructor passing through variadic arguments, a la foo.apply(this, arguments) ? I've looked for an answer, and the only instances I see are either calling super() (no arguments) or calling super(x, y) (with specific arguments). super.apply(this, arguments) doesn't appear to work. The pattern I find convenient and follow is constructor(...args) { super(...args); } In case you have and use named arguments you could do this instead: constructor(a, b, c) { super(...arguments); } References: https://developer.mozilla.org/en/docs/Web/JavaScript/Reference